Roni -
Try this:
lm(formula(paste(outcome,'income + covariate1 + coviarate2',sep='~')),
data=my.data) -> model
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
spec...@stat.berkeley.edu
On Thu, 3 Jun 2010, Roni Kobrosly wrote:
Hi,
I made a small table of strings that will serve as variable names for lm models
I will run. The table looks like this:
varnames
num name
1 1 zCANTAB_log_IED_totaltrials
2 2 zCANTAB_log_IED_preED
3 3 zCANTAB_logPALerrors
4 4 zCANTAB_PALstages
5 5 zCANTAB_logRTI
6 6 zCANTAB_RVP_Totalmisses
7 7 zCANTAB_log_RVP_falsealarm
8 8 zCANTAB_DMS_12000
9 9 zCANTAB_PRM_Percent
10 10 zCANTAB_SRM_Percent
11 11 zCANTAB_sqrt_SWM_within
12 12 zCANTAB_sqrt_SWM_Total
13 13 zSS_WJ_PC
14 14 zSS_WJ_CALC
15 15 zSS_WJ_LW
16 16 zSS_WJ_AP
17 17 zSS_WJ_MF
What I'm trying to do is
varnames[1,2] -> outcome
lm(outcome ~ income + covariate1 + coviarate2, data=my.data) -> model
I get the following error message:
"Error in model.frame.default(formula = outcome ~ Hollings_Enroll + Child_sex +
:
variable lengths differ (found for 'Hollings_Enroll')"
But when I run the model:
lm(zCANTAB_log_IED_totaltrials ~ income + covariate1 + coviarate2, data=my.data)
-> model
it works fine. Eventually, once I resolve this, I'd like to make a custom R
function to automatically generate 17 regression models with these 17 outcome
variable strings. Do you have any ideas how to resolve this error?
Thanks!
-Roni
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