Dieter Menne wrote:
Henrik Wahren wrote:
How can one or more levels be removed from a factor of a data frame. There
was a similar post on how to do this when a factor meets some criterion
(e.g. <= 2), but I can¹t seem to get that solution to work.
Here, I simply want to drop some levels.
Hi all,
I wonder what the difference is between the functions prcomp and the PCA
plotting method used in example 3 from the fastICA package. They give totally
different plots. The reason for asking is that I've earlier used prcomp, but
now I should do an ICA, and I guess I cannot compare th
Tan, Richard wrote:
Hello, can someone help? How come
gsub("\bINDS\b","INDUSTRIES","ADVANCED ENERGY INDS")
[1] "ADVANCED ENERGY INDS"
It does, but you need to escape it:
gsub("\\bINDS\\b","INDUSTRIES","ADVANCED ENERGY INDS")
Uwe Ligges
not ADVANCED ENERGY INDUSTRIES
Thanks
Peng Yu wrote:
According to Amazon review, 'Statistical Models in S' is a key
reference for understanding the methods implemented in several of
S-PLUS' high-end statistical functions, including 'lm()', predict()',
'design()', 'aov()', 'glm()', 'gam()', 'loess()', 'tree()',
'burl.tree()', 'nls()
Hi,
You can ad it yourself:
http://stat.ethz.ch/mailman/listinfo/r-help
-Ista
On Wed, Nov 11, 2009 at 12:57 AM, 杨江伟 wrote:
> thanks a lot
>
> --
> Pleasure should be subordinate to duty.
>
> [[alternative HTML version deleted]]
>
> __
> R-help@r
Try this also:
xtabs(rep(p, 2) ~ rep(id, 2) + sprintf("var%d", c(code1, code2)), data = x)
On Wed, Nov 11, 2009 at 2:10 AM, legen wrote:
>
> Thank you for your kind help. Your script works very well. Would you please
> show me how to change NaN to zero and column variables 1, 2, ..., 8 to var1,
Dear R helpers
Suppose I have a following data
y <- c(9.21, 9.51, 9.73, 9.88, 10.12. 10.21)
t <- c(0, 0.25, 1, 3, 6, 12)
I want to find out the polynomial which fits y in terms of t i.e. y = f(t) some
function of t.
e.g. y = bo + b1*t + (b2 * t^2) + (b3 * t^3) + .. and so on.
Dear Robert,
Thanks for the information.
I tried this but it still did not work well.
I will try some other option.
Nana Browne
There is no key to happiness. The door is always open.
--- On Tue, 11/10/09, Robert J. Hijmans
Hello,
I have the following data and would like to get some hints on how to analyze
tis data, nested analysis?
Habitats: 2 (Seagrass meadows and sandy bottoms)
Seasons: 4 (Winter, Spring, Summer and Autumn)
Locations: 4 (2 locations for for each habitat and season)
Replicates: 3 replicates for
Le mercredi 11 novembre 2009 à 10:22 +0100, Uwe Ligges a écrit :
>
> Peng Yu wrote:
> > According to Amazon review, 'Statistical Models in S' is a key
> > reference for understanding the methods implemented in several of
> > S-PLUS' high-end statistical functions, including 'lm()', predict()',
> >
Emmanuel Charpentier wrote:
Le mercredi 11 novembre 2009 à 10:22 +0100, Uwe Ligges a écrit :
Peng Yu wrote:
According to Amazon review, 'Statistical Models in S' is a key
reference for understanding the methods implemented in several of
S-PLUS' high-end statistical functions, including 'lm()'
Hi all,
I wanted to have a seasonality study like whether a particular month has
significant effect as compared to others. Here is my data :
0.10499 0 0 1 0 0 0 0 0 0
0 0
0.00259 0 0 0 1 0 0 0
Try this:
> x <- read.table(textConnection("idcode1code2 p
+ 148 0.1
+ 157 0.9
+ 218 0.4
+ 262 0.2
+ 243 0.6
+ 356 0.7
+
hi,
I'm mustafa. I'm a master student Dokuz Eylül University in
Izmir/Turkey.
I focus on Statistical programming language R. I learn architecture
of R. But i don't find out any material in internet.
Would you like to help me this subject? If you have
documentations, would you like to share wi
Your script works very well. Thank you very much.
Legen
Henrique Dallazuanna wrote:
>
> Try this also:
>
> xtabs(rep(p, 2) ~ rep(id, 2) + sprintf("var%d", c(code1, code2)), data =
> x)
>
> On Wed, Nov 11, 2009 at 2:10 AM, legen wrote:
>>
>> Thank you for your kind help. Your script works v
CAN ANYONE PLEASE HELP ME WITH THIS
i HAVE TO DO A MIXED EFFECT LINEAR MODEL WITH MY DATA DUE TO THE FACT THAT I
have pseudoreplication!
Although after reading and trying it for several times can get around due to
"Error in na.fail.default(list(date = c(1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, :
missing v
That's what I want. Many thanks for your help.
Legen
jholtman wrote:
>
> Try this:
>
>> x <- read.table(textConnection("idcode1code2 p
> + 148 0.1
> + 157 0.9
> + 218 0.4
> + 262
Hi Bogaso,
Try this
vecnames<-names(test[,2:11])
fmla <- as.formula(paste("test[,1] ~ ", paste(vecnames, collapse= "+")))
res<-lm(fmla)
Regards
M
Bogaso a écrit :
Hi all,
I wanted to have a seasonality study like whether a particular month has
significant effect as compared to others. Here i
Hi friends,
Again i don't know how to pass multiple arguments from php file to r
scripts.
Please have a look at this link ; it gives a very simple explanation of
passing variables from a PHP page to r scipts.Because i have done the same
thing.
http://www.math.ncu.edu.tw/~chenwc/R_note/index.php?i
For me with ff - on a 3 GB notebook - 3e6x100 works out of the box even without
compression: doubles consume 2.2 GB on disk, but the R process remains under
100MB, rest of RAM used by file-system-cache.
If you are under windows, you can create the ffdf files in a compressed folder.
For the rando
Hi Peng,
the major problem about your specific case is that when creating the
final object, we need to set dimnames() appropriately. This triggers a
copy of the object and that's where you get the error you describe.
With the current release, unfortunately, there isn't much to do
(unless
Hi all,
Does anyone know how to get the independent components and loadings from an
Independent Component Analysis (ICA), as well as principal components and
loadings from a Pricipal Component analysis (PCA) using the fastICA package? Or
perhaps if there's another way to do ICAs in R?
Bel
On Nov 11, 2009, at 7:14 AM, Bogaso wrote:
Hi all,
I wanted to have a seasonality study like whether a particular month
has
significant effect as compared to others. Here is my data :
0.10499 0 0 1 0 0 0 0 0 0
0 0
0.00259 0
Hi,
I have a matrix with positive numbers, negative numbers, and NAs. An
example of the matrix is as follows
-1 -1 2 NA
3 3 -2 -1
1 1 NA -2
I need to compute a scaled version of this matrix. The scaling method is
dividing each positive numbers in each row by the sum of positive numbers
in that r
This is possibly the wrong list, but anyway ...
Using Linux Debian-4.0 Etch (regularly upgraded).
I set about installing Simon Woods' "soap" package -- see:
http://www.maths.bath.ac.uk/~sw283/simon/software.html
So I downloaded the tar archive soap_0.1-3.tar.gz and then ran
(as root) R CMD I
Dear all,
W.XP
I recently upgraded to R2.10.0 and did what I usually do: copied all
"special" libraries from the old installation and then used
"update.packages()" on the command line. Nothing happened. Then I clicked
on the same command on the droplist which generated
"update.packages(ask='graph
The date library was written 20 or so years ago. It was a very good
first effort, but the newer Date library has superior functionality in
nearly every way. The date library is still available, for legacy
projects such as yours, but I do not advise it for new work. To answer
your specific qu
>> (x.n <- cast(x.m, id ~ var, function(.dat){
> + if (length(.dat) == 0) return(0) # test for no data; return
> zero if that is the case
> + mean(.dat)
> + }))
Or fill = 0.
Hadley
--
http://had.co.nz/
__
R-help@r-project.org mailing list
h
Dear R-users,
I have the following zoo object:
x1x2 x3 x4
x5 x6
1998-08-31 -0.0704375904 NA NA NA
NA NA
1998-09-01 0.0379028122 NA NA NA
NA
Dear all,
I will present R language and R software environment to the Statistical Society
of Serbia.
As I will doing it to professional statisticians it seems unneccesary to
me to present them how R language works in details. I am more
interested to present them with the latest facts regarding
one approach is the following:
mat <- rbind(c(-1, -1, 2, NA), c(3, 3, -2, -1), c(1, 1, NA, -2))
mat / ave(abs(mat), row(mat), sign(mat), FUN = sum)
I hope it helps.
Best,
Dimitris
Hao Cen wrote:
Hi,
I have a matrix with positive numbers, negative numbers, and NAs. An
example of the matrix
On 11/11/2009 10:19 AM, Stefan Zeugner wrote:
Duncan Murdoch wrote:
Just declaring it there is the only reasonable way, i.e.
test<-function(foo) {
subtest <- function() {
foo <<- foo+1
}
subtest()
return(foo)
}
The reason you can't somehow assign it within an existing test is that
Here is one possibility using aggregate.zoo
> aggregate(z, as.yearmon, tail, 1)
x1 x2 x3 x4 x5 x6
Aug 1998 -0.07043759 NA NA NA NA NA
Sep 1998 -0.03098945 NA NA NA NA NA
Oct 1998 -0.00726802 NA NA NA NA NA
The above is not strictly what you asked for since it uses yearmon
times.
mustafa_binar wrote:
>
>
>
>
> hi,
> I'm mustafa. I'm a master student Dokuz Eylül University in
> Izmir/Turkey.
>
> I focus on Statistical programming language R. I learn architecture
> of R. But i don't find out any material in internet.
> Would you like to help me this subject? If you
On 11/11/2009 10:26 AM, Damjan Krstajic wrote:
Dear all,
I will present R language and R software environment to the Statistical Society
of Serbia.
As I will doing it to professional statisticians it seems unneccesary to
me to present them how R language works in details. I am more
interested
On Nov 11, 2009, at 10:36 AM, Dimitris Rizopoulos wrote:
one approach is the following:
mat <- rbind(c(-1, -1, 2, NA), c(3, 3, -2, -1), c(1, 1, NA, -2))
mat / ave(abs(mat), row(mat), sign(mat), FUN = sum)
Very elegant. My solution was a bit more pedestrian, but may have some
speed advanta
Hello,
I am searching for a function to calculate "partial" cumsums.
For example it should calculate the cumulative sums until a NA appears,
and restart the cumsum calculation after the NA.
this:
x <- c(1, 2, 3, NA, 5, 6, 7, 8, 9, 10)
should become this:
1 3 6 NA 5 11 18 26 35 45
any i
I need to get the names of the list elements when I iterate over a
list. I'm wondering how to do so?
alist=list(a=c(1,3),b=c(-1,3),c=c(-2,1))
sapply(alist,function(x){
#need to use the name of x for some subsequent process
})
__
R-help@r-proje
Dear Forum
my machine runs Ubuntu 9.04. I am trying to install Biomart, what I realize
is that something is missing and it can't install XML, RCurl but I don't
know what more to do, I looked in previous posts but I did not find
infoprmation that helped.
Thanks
Andreia
biocLite("biomaRt")
Running b
Hi Andreia --
Andreia Fonseca wrote:
> Dear Forum
>
> my machine runs Ubuntu 9.04. I am trying to install Biomart, what I realize
> is that something is missing and it can't install XML, RCurl but I don't
> know what more to do, I looked in previous posts but I did not find
> infoprmation that he
Hi,
I'm responding to the question about storage error, trying to read a 300 x
100 dataset into a data.frame.
I wonder whether you can read the data as strings. If the numbers are all one
digit, each cell would require just 1 byte instead of 8. That makes 300MB
instead of 2.4GB. You can ru
On Wed, 11 Nov 2009 10:51:53 -0500 Duncan Murdoch
wrote:
> If you know their applications you can show how well R does there,
And do mention the (increasing) number of books available. It's only a
slight exaggeration to say that there are R books on almost any
application you could think of.
Simon Seibert mytum.de> writes:
>
> Good evening list,
> I'm looking for an R implementation of the "Shuffled Complex
> Evolutionâ (SCE-UA) algorithm after Duan et al. (1993). Does anybody
> know if there is an extension/ package existing that contains it?
> Thanks very much for your help! Che
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Peng Yu
> Sent: Wednesday, November 11, 2009 8:02 AM
> To: r-h...@stat.math.ethz.ch
> Subject: [R] How to get the names of list elements when
> iterating over alist?
>
> I need
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of smu
> Sent: Wednesday, November 11, 2009 7:58 AM
> To: r-help@r-project.org
> Subject: [R] partial cumsum
>
> Hello,
>
Dear list subscriber,
suppose, I do have a minimal Sweave file 'test.Rnw':
\documentclass{article}
\begin{document}
<>=
x
@
\end{document}
Within R, I define the following function:
f <- function(x){
Sweave("test.Rnw")
}
The call:
f(x = 1:10)
results in the following error message:
> f(x
On Mon, Oct 19, 2009 at 7:57 PM, Peng Yu wrote:
> tmp <- matrix(1:2)
> tmp
> tmp[,1,drop=FALSE]
>
>
> See the above example. Is there a way to make 'drop=FALSE' as global
> default, so that when I say 'tmp[,1]', R will treat it as
> 'tmp[,1,drop=FALSE]'?
Is there a way to set drop=FALSE globally?
On Wed, 11 Nov 2009 08:53:50 -0800 William Dunlap
wrote:
> > x <- c(1, 2, 3, NA, 5, 6, 7, 8, 9, 10)
> >
> > should become this:
> >
> > 1 3 6 NA 5 11 18 26 35 45
>
> Perhaps
>> ave(x, rev(cumsum(rev(is.na(x, FUN=cumsum)
> [1] 1 3 6 NA 5 11 18 26 35 45
Clever way of puttin
On Nov 11, 2009, at 10:57 AM, David Winsemius wrote:
On Nov 11, 2009, at 10:36 AM, Dimitris Rizopoulos wrote:
one approach is the following:
mat <- rbind(c(-1, -1, 2, NA), c(3, 3, -2, -1), c(1, 1, NA, -2))
mat / ave(abs(mat), row(mat), sign(mat), FUN = sum)
Very elegant. My solution was
I am writing a rd doc, and need to use "#" in a url adress. This would make:
\url{http://www..org/myfolder/#myanchor}
Of course, I suppose this will not work because # is a special character
starting a comment line in the rd dialect. I did not found a similar
example in "Writing R exention
On Wed, 11 Nov 2009 18:11:51 +0100 Karl Ove Hufthammer
wrote:
> I wish cumsum took a 'na.rm' argument, though. It would make stuff like
> this much easier.
Or, more specifically, a 'na.value', which could perhaps default to
'NA' to get the current behaviour, but which one could set 0 for
'cum
x="\url{http://www..org/myfolder/#myanchor}";
print(x,quote=F)
Does this work for you?
Daniel
-
cuncta stricte discussurus
-
-Ursprüngliche Nachricht-
Von: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] Im
Auftrag
I'm very familiar with C++. In this sense, it is easier for me to
learn R.oo according to your advice. On the other hand, S3 and S4 are
the most used. I'm wondering what would be the best choice for me. Do
you have any recommendation considering the pros and cons of both
ways?
Is it true that pack
On Wed, Nov 11, 2009 at 08:53:50AM -0800, William Dunlap wrote:
>
> Perhaps
>> ave(x, rev(cumsum(rev(is.na(x, FUN=cumsum)
> [1] 1 3 6 NA 5 11 18 26 35 45
>
it takes some time to understand how it works, but it's perfect.
thank you,
stefan
__
On 11/11/2009 12:09 PM, Pfaff, Bernhard Dr. wrote:
Dear list subscriber,
suppose, I do have a minimal Sweave file 'test.Rnw':
\documentclass{article}
\begin{document}
<>=
x
@
\end{document}
Within R, I define the following function:
f <- function(x){
Sweave("test.Rnw")
}
The call:
f(x =
To me, R is the language of choice for a rapidly increasing number
of people involved in new statistical algorithm development. If they
are happy with the tools they currently use, learning R may be a lot of
pain for little gain.
However, if they want to stay current with the late
> -Original Message-
> From: smu [mailto:m...@z107.de]
> Sent: Wednesday, November 11, 2009 9:26 AM
> To: William Dunlap
> Cc: r-help@r-project.org
> Subject: Re: [R] partial cumsum
>
> On Wed, Nov 11, 2009 at 08:53:50AM -0800, William Dunlap wrote:
> >
> > Perhaps
> >> ave(x, rev(cu
Daniel Malter a écrit :
x="\url{http://www..org/myfolder/#myanchor}";
print(x,quote=F)
Does this work for you?
Daniel
I am not working on consol mode (which would make your suggestion
straight applicable), but writing a rd documentationn (the documentation
that comes out with the
Yes, thanks for this, this is exactly what I want to do.
However, I have a remaining problem which is how to get R to understand that
each entry in my matrix is a vector of names.
I have been trying to import my text file with the names in each vector of
names enclosed in quotes and separated by
Ben ,
Thanks! This worked after I updated my version of R (from 2.8.1 to 2.10) .
Best,
Spencer
On Tue, Nov 10, 2009 at 7:04 PM, Ben Bolker wrote:
> sj gmail.com> writes:
>
> > I am using glmer() from lmer(lme4) to run generalized linear mixed
> models. I
> > can't figure out how to extrac
On 11/11/2009 12:15 PM, Patrick Giraudoux wrote:
I am writing a rd doc, and need to use "#" in a url adress. This would make:
\url{http://www..org/myfolder/#myanchor}
That should work.
Of course, I suppose this will not work because # is a special character
starting a comment line in the
On Nov 11, 2009, at 1:02 PM, esterhazy wrote:
Yes, thanks for this, this is exactly what I want to do.
However, I have a remaining problem which is how to get R to
understand that
each entry in my matrix is a vector of names.
I have been trying to import my text file with the names in eac
Dear Ana Golveia,
It is completelly impossible someone realise what kind or help you need or
what is happening. I suggest you give a look on the posting guide, mainly
that part about a minimum reproducible code with self explaining
information, etc.
Cheers
milton
On Wed, Nov 11, 2009 at 7:22 AM
Duncan Murdoch a écrit :
On 11/11/2009 12:15 PM, Patrick Giraudoux wrote:
I am writing a rd doc, and need to use "#" in a url adress. This
would make:
\url{http://www..org/myfolder/#myanchor}
That should work.
Of course, I suppose this will not work because # is a special
character sta
Patrick Giraudoux a écrit :
Duncan Murdoch a écrit :
On 11/11/2009 12:15 PM, Patrick Giraudoux wrote:
I am writing a rd doc, and need to use "#" in a url adress. This
would make:
\url{http://www..org/myfolder/#myanchor}
That should work.
Of course, I suppose this will not work because
Duncan Murdoch wrote:
Just declaring it there is the only reasonable way, i.e.
test<-function(foo) {
subtest <- function() {
foo <<- foo+1
}
subtest()
return(foo)
}
The reason you can't somehow assign it within an existing test is that
subtest is a different closure every time.
#Hello,
#I loaded data using read.table - I needed to convert a row in the data
frame to date class:
> data
V1 V2 V3 V4
1 2008-05-19 2008-04-19 2008-03-21 2008-02-22
2 38.16999817 30.7008 36.8661 35.18999863
3 37.4754 29.9576 36.4508 35.366
This is a tricky data entry problem. The right technique will depend on the fine details of the
data, and it's not clear what those are. E.g., when you say "In my first column, for example,
I have "henry" ", it's unclear to me whether or not the double quotes are part of
the data or not - whi
Hi All,
I am new to this form and new to R, having just initiated the analysis of my
first project using R. I have been working on a logistic model of land use
change and am concerned about 1) measuring spatial autocorrelation and 2)
including an autocovariate in my model.
Here is what I think
Hi,
On Nov 11, 2009, at 1:06 PM, separent wrote:
#Hello,
#I loaded data using read.table - I needed to convert a row in the
data
frame to date class:
data
V1 V2 V3 V4
1 2008-05-19 2008-04-19 2008-03-21 2008-02-22
2 38.16999817 30.7008 36.8661 35.1
On Nov 11, 2009, at 12:06 PM, separent wrote:
#Hello,
#I loaded data using read.table - I needed to convert a row in the
data
frame to date class:
data
V1 V2 V3 V4
1 2008-05-19 2008-04-19 2008-03-21 2008-02-22
2 38.16999817 30.7008 36.8661 35.18999
On Nov 11, 2009, at 1:06 PM, separent wrote:
#Hello,
#I loaded data using read.table - I needed to convert a row in the
data
frame to date class:
You _should_ have given the actual code (as the Posting Guide
requests), but I would guess that you should have added either
as.is=TRUE or
That is wonderful, now I think I am all set! Thanks again!
Tony Plate wrote:
>
> This is a tricky data entry problem. The right technique will depend on
> the fine details of the data, and it's not clear what those are. E.g.,
> when you say "In my first column, for example, I have "henry" ",
William Dunlap wrote:
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of smu
Sent: Wednesday, November 11, 2009 7:58 AM
To: r-help@r-project.org
Subject: [R] partial cumsum
hi all - quick question:
i have a matrix 'y' of response values, with two explanatory variables
'x1' and 'x2'.
tested values of 'x1' and 'x2' are sitting in two vectors 'x1' and
'x2'.
i want to learn model parameters without "unrolling" the matrix of
response values.
example below:
# some fake da
Hello,
Thank you for responding! The data is in the same format as the example I
showed earlier. The data is different from matrix to matrix, but the general
format is:
Time1Time 2 Time3 Time4
Species1 134 5
Species2 34
Hi all,
I am new to python, R and rpy2. I having few errors when I am using
'fisher.test' function where I am struck now. Please help to fix these bugs.
My code for fisher.test goes this way
*from rpy2 import *
import rpy2.robjects as robjects
def fisherExact(a,b,c,d):
v = [a,b,c,d]
m = rob
On Nov 11, 2009, at 2:24 PM, Murat Tasan wrote:
hi all - quick question:
i have a matrix 'y' of response values, with two explanatory variables
'x1' and 'x2'.
tested values of 'x1' and 'x2' are sitting in two vectors 'x1' and
'x2'.
i want to learn model parameters without "unrolling" the matri
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Bhanu Mangipudi
> Sent: Wednesday, November 11, 2009 11:16 AM
> To: r-help@r-project.org
> Subject: [R] fisher.test negative value error
>
> Hi all,
>
> I am new to python, R an
Hello Gentlemen,
All of your answers were helpfull. Indeed, 'as.is=TRUE' or
'stringsAsFactors=FALSE' avoid importing as factors, as it did when I
imported the table without specifying anything. However, data frames will
not allow different datatypes within a single column, so, for time series, I
Milton's point is dead-on, and I would highly encourage you to give the
posting guide a look.
That said... you might try "na.action = na.omit" in your call to...
actually, we don't know what function you are using (see first point).
Regardless, sounds like you have missing data and na.action is
On Wed, 11 Nov 2009, Peng Yu wrote:
On Mon, Oct 19, 2009 at 7:57 PM, Peng Yu wrote:
tmp <- matrix(1:2)
tmp
tmp[,1,drop=FALSE]
See the above example. Is there a way to make 'drop=FALSE' as global
default, so that when I say 'tmp[,1]', R will treat it as
'tmp[,1,drop=FALSE]'?
Is there a way
On Wed, 11 Nov 2009, Larry Hotchkiss wrote:
Hi,
I'm responding to the question about storage error, trying to read a 300 x
100 dataset into a data.frame.
I wonder whether you can read the data as strings. If the numbers are all one
digit, each cell would require just 1 byte instead of 8.
I'm trying to write code to calculate partial correlations (along with
p-values). I'm new to R, and I don't know how to do this. I have searched
and come across different functions, but I haven't been able to get any of
them to work (for example, pcor and pcor.test from the ggm package).
In the
I think it would be best to learn S3 first since that is a fundamental
part of R and S4 is an extension of it and also its very simple so
there is not much to learn. After that you can branch out.
On Mon, Oct 26, 2009 at 2:28 PM, Gabor Grothendieck
wrote:
> S3 and S4 are part of the core of R so
The help for fastICA says:
The data matrix X is considered to be a linear combination of
non-Gaussian (independent) components i.e. X = SA where columns of
S contain the independent components and A is a linear mixing
matrix.
The value of fastICA is a list with components "S" (th
Hello, I'm beginning with R and I'm wondering if there's any way to display
large values (e.g. 161651654167) using my system's thousands separator or
scientific notation.
Thanks!
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R-help@r-project.org mail
Hi,
I'm new to R.
I've two sort of time series, one sampled every second and other every 30
minutes stored in two data.frames zy1 and zy2.
I've joined the two series using
date<-merge(zy1,zy2, all.x=T,all.y=T)
when I want to make a plot, using the code below, it doesn't work.
It gives me the
Dear Michel,
The only thing you need to do is download the TSA package, and read its
document. In this document you're gonna find the command eacf, so it's as
simple as using the source TSA, and in ur Tinn-R just call the instruction
with the options you want.
I expect this information to be use
When printing data.frames, R aligns columns by padding with spaces.
For example,
print(data.frame(x=c('a','bb','ccc')),right=FALSE)
x
1 a |-- vertical bar shows end of line
2 bb |-- vertical bar shows end of line
3 ccc|-- vertical bar shows end of
On Nov 11, 2009, at 3:52 PM, Patricio Cuarón wrote:
Hello, I'm beginning with R and I'm wondering if there's any way to
display
large values (e.g. 161651654167) using my system's thousands
separator or
scientific notation.
Thanks!
To get scientific notation as a default for given large va
Please what I already wrote in my previous message of this thread.
Also, everything in R.oo is based on S3 and it uses standard R
constructs and data types to achieve what it does.
You can submit packages based on R.oo, and there are several such
packages on CRAN, see 'Reverse dependencies' on
htt
Stavros Macrakis wrote:
I could of course write my own print function for this, but was
wondering if there was a standard way of doing it. If not in R,
perhaps there is some way to have ESS delete the final spaces?
ESS, or more precisely emacs, can handle that. Use the M-x
toggle-truncate-l
quote:
> x <- c(1, 2, 3, NA, 5, 6, 7, 8, 9, 10)
> rev(cumsum(rev(is.na(x
[1] 1 1 1 1 0 0 0 0 0 0
A more natural way to do this is
> cumsum(is.na(c(NA,x[-length(x)])))
[1] 1 1 1 1 2 2 2 2 2 2
endquote
Both of which suggest the original problem could also be dealt with by
usin
> See the above example. Is there a way to make 'drop=FALSE' as global
> default, so that when I say 'tmp[,1]', R will treat it as
> 'tmp[,1,drop=FALSE]'?
The following code won't change the defaults, but it would at least
let you know when you're making the mistake:
trace_all <- function(fs, tra
On Nov 11, 2009, at 4:45 PM, Carl Witthoft wrote:
> By Bill Dunlap:
quote:
> x <- c(1, 2, 3, NA, 5, 6, 7, 8, 9, 10)
> rev(cumsum(rev(is.na(x
[1] 1 1 1 1 0 0 0 0 0 0
A more natural way to do this is
> cumsum(is.na(c(NA,x[-length(x)])))
[1] 1 1 1 1 2 2 2 2 2 2
endquote
Both of whi
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of hadley wickham
> Sent: Wednesday, November 11, 2009 3:03 PM
> To: Peng Yu
> Cc: r-h...@stat.math.ethz.ch
> Subject: Re: [R] Is there a way to specify drop=FALSE as the
> global d
Hello R users,
Is anyone familiar with an R function that converts a time expression (
POSIx for example ) to time (seconds/minutes) from epoch?
I was unable to find any
Best,
Alon
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R-help@r-project.org
try this:
> x <- Sys.time()
> str(x)
POSIXct[1:1], format: "2009-11-11 18:40:10"
> x
[1] "2009-11-11 18:40:10 EST"
> as.numeric(x) # secs from 1/1/1970
[1] 1257982810
>
On Wed, Nov 11, 2009 at 6:29 PM, Alon Ben-Ari wrote:
> Hello R users,
>
> Is anyone familiar with an R function that convert
http://code.google.com/p/ihacres/source/browse/trunk/man/SCEoptim.Rd
http://code.google.com/p/ihacres/source/browse/trunk/R/sce.R
source("http://ihacres.googlecode.com/svn/trunk/R/sce.R";)
2009/11/12 Hans W Borchers :
> Simon Seibert mytum.de> writes:
>
>>
>> Good evening list,
>> I'm looking
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