Hi again (, I am the PO from my own email account)
I agree that the word "basically" puts the NA issues aside. But my
point is that R subsetting behavior when there are NAs in a logical
index is quite tricky to say the less, and deserves the trouble of
pointing it out in every place it is appro
> peter dalgaard
> on Fri, 16 Nov 2018 13:39:27 +0100 writes:
> Well, "Basically, " is an excuse for not being
> accurate. Making the code more complex doesn't really help
> the explanation. It could be better to just add "(except
> for NA handling)" or so.
> -pd
Well, "Basically, " is an excuse for not being accurate. Making the code more
complex doesn't really help the explanation. It could be better to just add
"(except for NA handling)" or so.
-pd
> On 16 Nov 2018, at 11:08 , buzon informatica, ige
> wrote:
>
> The which() function help page s
Hi Gafar,
As Jeff has pointed out, the median value may not exist within the
dataset. However, this function will give you either the position of
the value that is the median, or the position of the two closest
values if none equal the median. Be aware that this function may fall
victim to the "ind
The median is not always a member of the data set. What do you really want?
I for one would want people to follow the guidance in the footer on every email
on this mailing list.
--
Sent from my phone. Please excuse my brevity.
On June 4, 2016 9:01:41 AM PDT, Gafar Matanmi Oyeyemi
wrote:
>De
Yes, the round(seq( )) sollution does it.
Many thanks to the sender of this (and other similar) solutions.
TB
On Thu, Aug 16, 2012 at 3:45 AM, Petr Savicky wrote:
> On Wed, Aug 15, 2012 at 10:37:17PM +1000, Tom Bird wrote:
> > Hi,
> >
> > I am using 32-bit R v 2.15.1, on Mac OsX v 10.6.8 with
HI,
Try this:
S<-as.numeric(formatC(seq(0,4,0.01),digits=3))
which(S==2.02)
#[1] 203
which(S==2.03)
#[1] 204
which(S==3.03)
#[1] 304
which(S==3.3)
#[1] 331
which(S==3.)
#[1] 301
A.K.
- Original Message -
From: Tom Bird
To: r-help@r-project.org
Cc:
Sent: Wednesday, August 15, 201
On Wed, Aug 15, 2012 at 10:37:17PM +1000, Tom Bird wrote:
> Hi,
>
> I am using 32-bit R v 2.15.1, on Mac OsX v 10.6.8 with R GUI 1.52 Leopard
> build 32-bit (6188). I have also replicated this error on R 2.13.2 on a
> windows 7 machine.
>
> In some sequences of numbers, I am unable to use the w
FAQ 7.31
?is.equal
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#.. Playing
Resea
It looks like an example of FAQ 7.31 Why doesn't R think these numbers are
equal?
John Kane
Kingston ON Canada
> -Original Message-
> From: tomasb...@gmail.com
> Sent: Wed, 15 Aug 2012 22:37:17 +1000
> To: r-help@r-project.org
> Subject: [R] which() function not finding certain number
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf Of David Winsemius
> Sent: Sunday, October 16, 2011 1:59 PM
> To: Jeff Newmiller
> Cc: r-help@r-project.org; syrvn
> Subject: Re: [R] Which function to use:
On Oct 16, 2011, at 1:32 PM, Jeff Newmiller wrote:
Note that "male" comes before "female" in your data frame.
---
Jeff Newmiller The . . Go Live...
syrvn wrote:
Hi,
thanks for the tip! I do it as follows now
Note that "male" comes before "female" in your data frame.
---
Jeff Newmiller The . . Go Live...
DCN: Basics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#.. Playing
Research Engineer (Solar/Batteries O.O#. #.O#. with
/S
Hi,
thanks for the tip! I do it as follows now but I still have a problem I do
not understand:
abbrvs <- data.frame(c("peter", "name", "male", "female"),
c("P", "N", "m", "f"))
colnames(abbrvs) <- c("pattern", "replac
On Oct 16, 2011, at 12:35 PM, syrvn wrote:
Hello,
I have a simple question but I don't know which method is best to
use for my
problem.
I have the following strings:
str1 <- "My_name_is_peter"
str2 <- "what_is_your_surname_peter"
I would like to apply predefined abbreviations for peter=p
Hi,
Try with more parentheses:
> l[((which(100420==l))-1):which(100420==l)]
[1] "100419" "100420"
It was interpreted as 4-(1:4)=3 2 1 0
Ivan
Le 6/2/2010 09:41, arnaud Gaboury a écrit :
Dear group,
Here is a list of elements :
l<-
c("100415", "100416", "100419", "100420", "100421", "100422"
Hi Arnaud
Try this
l[((which(100420==l))-1):which(100420==l)]
Regards
Mo
arnaud Gaboury a écrit :
Dear group,
Here is a list of elements :
l <-
c("100415", "100416", "100419", "100420", "100421", "100422",
"100423", "100426", "100427", "100428", "100429", "100430", "100503",
"100504", "1
The correct line is :
> l[(which(100420==l)-1):which(100420==l)]
[1] "100419" "100420"
> -Original Message-
> From: arnaud Gaboury [mailto:arnaud.gabo...@gmail.com]
> Sent: Wednesday, June 02, 2010 9:41 AM
> To: r-help@r-project.org
> Cc: 'arnaud Gaboury'
> Subject: which function
>
>
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