Hi, thanks for the tip! I do it as follows now but I still have a problem I do not understand:
abbrvs <- data.frame(c("peter", "name", "male", "female"), c("P", "N", "m", "f")) colnames(abbrvs) <- c("pattern", "replacement") str <- "My name is peter and I am male" for(m in 1:nrow(abbrvs)) { str <- sub(abbrvs$pattern[m], abbrvs$replacement[m], str, fixed=TRUE) print(str) } This works perfectly fine as I get: "My N is P and I am m" However, when I replace male by female then I get the following: "My N is P and I am fem" but I want to have "My N is P and I am f". Even with the parameter fixed=true I get the same result. Why is that? -- View this message in context: http://r.789695.n4.nabble.com/Which-function-to-use-grep-replace-substr-etc-tp3909871p3909922.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.