Thanks to everyone for the explanations.
Toby
On 27 Aug 2010 at 12:46, Phil Spector wrote:
> Toby -
> Since dat$doy is just a number, the default S3 method
> for format is used, where the second argument is the trim
> parameter. I suspect you are confusing format (which is for
> output) wi
Toby -
Since dat$doy is just a number, the default S3 method
for format is used, where the second argument is the trim
parameter. I suspect you are confusing format (which is for
output) with strptime (which is for input).
For example,
strptime(dat$doy,'%j')
will assume that the dates
On Aug 27, 2010, at 3:29 PM, Toby Gass wrote:
Hello, helpeRs,
I have a vector of numbers from 1-365 (days of the year) that I would
like to convert to a date. There are no NA's and no missing values.
I did not insert leading zero's for numbers less than 100.
Using the syntax:
dat$doy.1 <- a
Toby,
What is it that you're trying to accomplish?
There seems to be several ideas confused in your post.
It sounds like you have input
x <- 1:365
and you want to call some function to return dates?
Which date should be returned for input 1?
January 1, 2010?
Your error is because if you giv
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