Toby -
Since dat$doy is just a number, the default S3 method
for format is used, where the second argument is the trim
parameter. I suspect you are confusing format (which is for
output) with strptime (which is for input).
For example,
strptime(dat$doy,'%j')
will assume that the dates are in the current year, and
return a POSIXlt object. Alternatively, you could pass
an origin to as.Date:
as.Date(dat$doy,origin='2009-12-31')
to get a similar Date object.
- Phil
On Fri, 27 Aug 2010, Toby Gass wrote:
Hello, helpeRs,
I have a vector of numbers from 1-365 (days of the year) that I would
like to convert to a date. There are no NA's and no missing values.
I did not insert leading zero's for numbers less than 100.
Using the syntax:
dat$doy.1 <- as.numeric(format(dat$doy, "%j" ))
I get the following error message:
Error in prettyNum(.Internal(format(x, trim, digits, nsmall, width,
3L, :
invalid 'trim' argument
.What is the error message telling me?
(Windows OS and R 2.11.1)
Thank you.
Toby
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