Phil Spector wrote:
>
>
> For chron objects:
>
> aggregate(thedata$value,list(hour=hours(thedata$date)),mean)
>
>
Ok, thanks, that's what I need. Now it seems so easy...
Could you tell me why we write... ?
aggregate(thedata$value,list(hour=hours(thedata$date)),mean)
instead of just
ag
Hi:
On Wed, Aug 18, 2010 at 4:43 PM, skan wrote:
>
> Hi
>
>
> Usually "aggregate" is used to calculate things such as the sum of all data
> on the first day, the sum next day, and so on.
> But how can I calculate the mean of the first hour of all days, the mean of
> the second hour of all days,
Skan -
I'll answer this question:
"how can I calculate the mean of the first hour of all days, the mean of
the second hour of all days, and so on."
Since you didn't include a reproducible example, I have to make
some assumptions. Since you are interested in hours, I'm guessing
your dates are
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