Phil Spector wrote: > > > For chron objects: > > aggregate(thedata$value,list(hour=hours(thedata$date)),mean) > >
Ok, thanks, that's what I need. Now it seems so easy... Could you tell me why we write... ? aggregate(thedata$value,list(hour=hours(thedata$date)),mean) instead of just aggregate(thedata$value,hours(thedata$date),mean) thanks -- View this message in context: http://r.789695.n4.nabble.com/Different-way-of-aggregating-tp2330497p2331072.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
