> all(vector[1]==vector)
should be quick.
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On Dec 16, 2010, at 10:19 AM, David Winsemius wrote:
On Dec 16, 2010, at 9:56 AM, baptiste auguie wrote:
Hi,
The fastest way seems to be,
all(x[1] == x)
I'm sure that is more efficient than this methods:
patt <- paste("^",x[1],"$", sep="")
length( grep(patt, x) == length(x) )
Wrong po
On Dec 16, 2010, at 9:56 AM, baptiste auguie wrote:
Hi,
The fastest way seems to be,
all(x[1] == x)
I'm sure that is more efficient than this methods:
patt <- paste("^",x[1],"$", sep="")
length( grep(patt, x) == length(x) )
... but sometimes it helps to have strategies that might generali
Hi,
The fastest way seems to be,
all(x[1] == x)
HTH,
baptiste
On 16 December 2010 15:17, Jannis wrote:
> Dear list,
>
>
> this might be an easy one, but I could figure out a solution (or how to
> google the right term).
>
> Is there any way to test whether all elements of a vector are identi
On Dec 16, 2010, at 9:17 AM, Jannis wrote:
Dear list,
this might be an easy one, but I could figure out a solution (or how
to google the right term).
Is there any way to test whether all elements of a vector are
identical?
?identical
For numeric vectors I would use
sum(diff(vector
Thanks Tal. Sometimes easy solutions are close by but hard to find when
one is focused on the wrong direction :-)!
Jannis
Tal Galili schrieb:
How about:
length(unique(vector)) >1
?
Contact
Details:---
Contact me: tal.gal..
How about:
length(unique(vector)) >1
?
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
www.r-statistics.com (English)
-
Dear list,
this might be an easy one, but I could figure out a solution (or how to
google the right term).
Is there any way to test whether all elements of a vector are identical?
For numeric vectors I would use
sum(diff(vector)==0)==0
but I have character vectors. Any Ideas?
Cheers
Janni
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