On Dec 16, 2010, at 9:56 AM, baptiste auguie wrote:
Hi,
The fastest way seems to be,
all(x[1] == x)
I'm sure that is more efficient than this methods:
patt <- paste("^",x[1],"$", sep="")
length( grep(patt, x) == length(x) )
... but sometimes it helps to have strategies that might generalize to
notions of "begins with" or "ends with" rather than "identical".
--
David.
HTH,
baptiste
On 16 December 2010 15:17, Jannis <bt_jan...@yahoo.de> wrote:
Dear list,
this might be an easy one, but I could figure out a solution (or
how to
google the right term).
Is there any way to test whether all elements of a vector are
identical?
For numeric vectors I would use
sum(diff(vector)==0)==0
but I have character vectors. Any Ideas?
Cheers
Jannis
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West Hartford, CT
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