true, it did work using unlist() funciton, it can be found the minimum
value.
and for further step, if i want identify the minimum value with the list,
which means the minimum value i have found is belonged to which
list[[j]][[i]].
i used the codes like this
##which(list1==min(list1))##
but
in Healthcare
greg.s...@imail.org
801.408.8111
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of jiliguala
> Sent: Tuesday, June 14, 2011 4:24 PM
> To: r-help@r-project.org
> Subject: Re: [R] automatically genera
thanks, Greg Snow-2.
here i hav a question, how can i save the value of a list to a vector or a
matrix? say,
i have a list (data1) and a vector or a matrix (data2).
if i made like this,
data2 <- as.vector(data1)
it does not change anything, the data2 is still a list.
what i want to do is to c
uala
> Sent: Tuesday, June 14, 2011 4:14 PM
> To: r-help@r-project.org
> Subject: Re: [R] automatically generate the output name of my "for"
> loops
>
>
> hi, im a new in R and this forum, so if there is something disturbing
> u, im
> gonna do it better.
>
hi, im a new in R and this forum, so if there is something disturbing u, im
gonna do it better.
by the way, where can i see the FAQ 7.21?? thanks..
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Sent
t; To: r-help@r-project.org
> Subject: [R] automatically generate the output name of my "for" loops
>
>
> Hello R users,
>
> I am new to R and am having difficulty with the output name of my "for"
> loops.
>
> here is the problem:
>
>
>
hi, jholtman
its true, the problem was to iniciate the list at the second level.
thx a lot
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If you want to have multidimensioned list, here is one way of doing it
by making sure you initialize the second level before using it:
data2 <- matrix(1:30, nrow = 10)
data3 <- matrix(1:300, nrow = 100)
data1 <- list() # init to a list
for (j in 1:10){
data1[[j]] <- list() #create second
hi, really thank u, Petr Pikal
problem solved already.
but here is another question:
for(i in 1:100)
data1[[i]] <- rbind(data2[1,], data3[i,])
the codes above are no problem,
but now i wnna do two loops like the codes below which have problem(the bold
letters):
i dont know what should be put
Hi
r-help-boun...@r-project.org napsal dne 13.06.2011 17:35:29:
> jiliguala
>
> really thanks for helping.
>
> i just did just like what Petr Pikal said,
> but it appeared some error like this:
>
> There were 50 or more warnings (use warnings() to see the first 50):
>
> Warning messages:
>
Hi Daniel
Try using this approach
##Drawing analogy from your example.. I am storing the values generated in a
loop in the following code
for (i in c(1:100))
{
nam <- paste("r",i, sep=".")
assign(nam, i+1)
}
##Having stored the values generated in the above loop in as many R
objects..
I think you need '[['
group[[i]] <- which(k1$cluster == i)
On Mon, Jun 13, 2011 at 11:35 AM, jiliguala wrote:
> really thanks for helping.
>
> i just did just like what Petr Pikal said,
> but it appeared some error like this:
>
> There were 50 or more warnings (use warnings() to see the first 50
really thanks for helping.
i just did just like what Petr Pikal said,
but it appeared some error like this:
There were 50 or more warnings (use warnings() to see the first 50):
Warning messages:
1: In group[i] <- which(k1$cluster == i) :
number of items to replace is not a multiple of replacem
Hi
r-help-boun...@r-project.org napsal dne 13.06.2011 05:21:23:
> Re: [R] automatically generate the output name of my "for" loops
>
> ?paste
> something like...
> paste (group, i, sep="_")
>
I believe that better idea is to use list, with which you c
?paste
something like...
paste (group, i, sep="_")
jiliguala wrote:
>
> Hello R users,
>
> I am new to R and am having difficulty with the output name of my "for"
> loops.
>
> here is the problem:
>
>
> for (i in c(1:100))
> {
> the name of the groups <- which(k1$cluster==i)
> }
>
> how
?paste
something like...
paste ("group", i, sep="_")
jiliguala wrote:
>
> Hello R users,
>
> I am new to R and am having difficulty with the output name of my "for"
> loops.
>
> here is the problem:
>
>
> for (i in c(1:100))
> {
> the name of the groups <- which(k1$cluster==i)
> }
>
> ho
Hello R users,
I am new to R and am having difficulty with the output name of my "for"
loops.
here is the problem:
for (i in c(1:100))
{
the name of the groups <- which(k1$cluster==i)
}
how can it automatically generate the name for 100 cluster? what should i
put in the bold letter place.
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