I think you need '[[' group[[i]] <- which(k1$cluster == i)
On Mon, Jun 13, 2011 at 11:35 AM, jiliguala <jiligu...@mail.com> wrote: > really thanks for helping. > > i just did just like what Petr Pikal said, > but it appeared some error like this: > > There were 50 or more warnings (use warnings() to see the first 50): > > Warning messages: > 1: In group[i] <- which(k1$cluster == i) : > number of items to replace is not a multiple of replacement length > 2: In group[i] <- which(k1$cluster == i) : > number of items to replace is not a multiple of replacement length > 3: In group[i] <- which(k1$cluster == i) : > number of items to replace is not a multiple of replacement length > ... > ... > ... > > and some solution for that, thanks.. > > -- > View this message in context: > http://r.789695.n4.nabble.com/automatically-generate-the-output-name-of-my-for-loops-tp3592160p3594096.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Jim Holtman Data Munger Guru What is the problem that you are trying to solve? ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
