> On Sep 19, 2018, at 10:48 PM, Ogbos Okike wrote:
>
> Hi David,
> That's it!!! The outcome is attached.
The explanation for this is that columns that have digits separated by dashes
will not be interpreted by R's read.table() as numeric or dates, but rather as
the default for text entries:
Hi David,
That's it!!! The outcome is attached.
Many thanks please.
Best
Ogbos
On Wed, Sep 19, 2018 at 11:34 PM David Winsemius
wrote:
>
> > On Sep 19, 2018, at 7:55 AM, Ogbos Okike
> wrote:
> >
> > Dear Experts,
> > I generated the plot attached. Every other thing is OK except the black
> >
> On Sep 19, 2018, at 7:55 AM, Ogbos Okike wrote:
>
> Dear Experts,
> I generated the plot attached. Every other thing is OK except the black
> horizontal lines which should appear like points or dots as the coloured
> ones. I can't understand why.
>
> I tried to change it to look like dots by
I'm a little surprised at some of what happens, but you can get date labels on
the x axis like this:
drng <- as.Date( c('2005-1-1' , '2005-12-31') )
plot(1, type="n", xlab="", ylab="", xaxt='n', xlim=drng, ylim=c(-.5, -10))
axis(1, at= pretty(drng), lab=format(pretty(drng)))
and if you prefer so
Dear Experts,
I generated the plot attached. Every other thing is OK except the black
horizontal lines which should appear like points or dots as the coloured
ones. I can't understand why.
I tried to change it to look like dots by calling empty plots so that I
will add them as points.
Since I hav
You loaded "lubridate" so using Erin's approach
library(lubridate)
st <- c("1961-01","1961-04","1983-02")
dat1 <- ymd(paste( st, "01", sep ="-"))
On Monday, August 20, 2018, 1:15:56 a.m. EDT,
wrote:
Thanks Erin and Jim. You have indeed solved my problem.
Philip
Quoting Erin Hodg
Nice one!
On Tue, Aug 21, 2018 at 6:14 PM John Kane wrote:
> You loaded "lubridate" so using Erin's approach
>
> library(lubridate)
> st <- c("1961-01","1961-04","1983-02")
> dat1 <- ymd(paste( st, "01", sep ="-"))
>
>
> On Monday, August 20, 2018, 1:15:56 a.m. EDT, <
> phili...@cpanel1.stormw
Thanks Erin and Jim. You have indeed solved my problem.
Philip
Quoting Erin Hodgess :
Hi Philip:
Here is something to consider:
#potential solution:
sta <- paste(st,"-01",sep="")
st1 <- as.Date(sta, format=("%Y-%m-%d"))
print(st1)
[1] "1961-01-01" "1961-04-01" "1983-02-01"
Hope this hel
Hi Phillip,
Jose has the correct answer. You probably missed this sentence in the
"Note" section of the help page:
"If the date string does not specify the date completely, the returned
answer may be system-specific."
In your case, the function throws up its hands and returns NA as you
haven't sp
On Sun, Aug 19, 2018 at 05:20:29PM -0400, phili...@cpanel1.stormweb.net wrote:
> Why the heck am I getting three NAs instead of three Dates?I have
> studied the R documentation for as.Date() and it has not turned on
> the light bulb for me.
I haven't encountered this problem before, but in my mind
Hi Philip:
Here is something to consider:
> #potential solution:
> sta <- paste(st,"-01",sep="")
> st1 <- as.Date(sta, format=("%Y-%m-%d"))
> print(st1)
[1] "1961-01-01" "1961-04-01" "1983-02-01"
Hope this helps!
Erin
Erin Hodgess, PhD
mailto: erinm.hodg...@gmail.com
On Sun, Aug 19, 2018 at
I am having trouble with what must be a very simple problem. Here is a
reproducible example:
library(lubridate)
st <- c("1961-01","1961-04","1983-02")
print(st)
#[1] "1961-01" "1961-04" "1983-02"
st1 <- as.Date(st, format=("%Y-%m"))
print(st1)
#[1] NA NA NA
Why the heck am I getting three NAs
Dear List,
I am happy to report that the problem is fixed. as.Date("1998-02-10") as
suggested by David handled the problem with easy. Many thanks to everybody.
as.Date(1998-02-10) really resulted in error. It is my oversight. I really
tried many things the day I was working on that and have forgott
What David Winsemius said, plus:
Does
legend('topleft', c("Climax", "Thule", "Sopo"), lty = 1, col =
("black","red","blue"))
not work?
It should, which will illustrate that you CAN add a legend to the plot.
The x,y that you supply to legend must be values that are within the x,y range
of the
> On Jun 22, 2018, at 12:12 PM, Ogbos Okike wrote:
>
> Dear Contributors,
>
> I am surprised that I cannot add legend to a certain plot. Although the
> x-axis indicates years, the actual data was in year, month and day format.
> I then used as.Date to play around and get what I am looking for.
Dear Contributors,
I am surprised that I cannot add legend to a certain plot. Although the
x-axis indicates years, the actual data was in year, month and day format.
I then used as.Date to play around and get what I am looking for. I am,
however, worried that I cannot add legend to the plot no mat
Dear All,
Many thanks for bailing me out.
Ogbos
On Apr 18, 2016 9:07 PM, "David Winsemius" wrote:
>
> > On Apr 18, 2016, at 10:44 AM, Ogbos Okike
> wrote:
> >
> > Dear ALL,
> > Thank you so much for your contributions.
> > I have made some progress. Below is a simple script I gleaned from
> > yo
> On Apr 18, 2016, at 10:44 AM, Ogbos Okike wrote:
>
> Dear ALL,
> Thank you so much for your contributions.
> I have made some progress. Below is a simple script I gleaned from
> your kind responses:
> Sys.setenv(TZ="Etc/GMT")
> dates <- c("02/27/92", "02/27/92", "01/14/92", "02/28/92", "02/01/
Dear ALL,
Thank you so much for your contributions.
I have made some progress. Below is a simple script I gleaned from
your kind responses:
Sys.setenv(TZ="Etc/GMT")
dates <- c("02/27/92", "02/27/92", "01/14/92", "02/28/92", "02/01/92")
times <- c("23:0:0", "22:0:0", "01:00:00", "18:0:0", "16:0
Date data cannot represent hour data. You need to use POSIXct or perhaps the
chron class from the chron package.
To use POSIXct, use ISOdatetime instead of ISOdate. Also be careful which
timezone you have set as default (in most operating systems calling
Sys.setenv(TZ="Etc/GMT") or similar wil
should also use ISOdatetime conversion function to use hours etc. in
your commands.
Cheers
Petr
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Ogbos
> Okike
> Sent: Monday, April 18, 2016 3:10 PM
> To: r-help@r-project.org
> Su
The most important thing is that Date objects by definition do not include time
of day. You want to look at ISOdatetime() and as.POSIXct() instead. And beware
daylight savings time issues.
-pd
On 18 Apr 2016, at 15:09 , Ogbos Okike wrote:
> Dear All,
>
> I have a data set containing year, mo
Dear All,
I have a data set containing year, month, day and counts as shown below:
data <- read.table("data.txt", col.names = c("year", "month", "day", "counts"))
Using the formula below, I converted the data to as date and plotted.
new.century <- data$year < 70
data$year <- ifelse(new.century,
Never mind... the solution was to read the source code of
as.Date.character. It turns out the default format="" is meaningless.
If 'format' is not given in the call to as.Date, it is NOT assumed to
be "", and the function gives very different results from a call where
the argument format="" is give
Hi all,
I have recently started working with Date objects and find the
experience unsettling, to put it mildly.
The help for as.Date says, in part:
## S3 method for class 'character'
as.Date(x, format = "", ...)
x: An object to be converted.
format: A character string. If n
nks.
-Original Message-
From: "William Dunlap" [wdun...@tibco.com]
Date: 06/19/2014 11:10 PM
To: "ce"
CC: r-help@r-project.org
Subject: Re: [R] as.Date(Sys.time()) returns tomorrow !
Is it a time zone issue? I get:
R> Sys.time()
[1] "2014-06-19 20:09:25 PDT&q
Is it a time zone issue? I get:
R> Sys.time()
[1] "2014-06-19 20:09:25 PDT"
R> as.Date(Sys.time())
[1] "2014-06-20"
R> as.Date(Sys.time(),tz="US/Pacific")
[1] "2014-06-19"
R> as.Date(Sys.time(),tz="PDT")
[1] "2014-06-20"
Wa
Dear all,
> Sys.time()
[1] "2014-06-19 22:19:17.976818 EDT"
> as.Date(Sys.time())
[1] "2014-06-20"
>
why this happens ?
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-p
Hi,
Check for the additional "%" in your code "%d%".
as.Date(strDates,"%m/%d/%Y")
#[1] "1965-01-05" "1975-08-16"
A.K.
On Sunday, March 9, 2014 12:16 PM, Hermann Norpois wrote:
Hello,
I have some problems with as.Date.
strDates <- c ("01/05/1965", "08/16/1975")
dates <- as.Date (strDates, "%
On Sun, 9 Mar 2014, Hermann Norpois wrote:
Hello,
I have some problems with as.Date.
strDates <- c ("01/05/1965", "08/16/1975")
dates <- as.Date (strDates, "%m/%d%/%Y")
^^^^
Instead of "%d%" just "%d":
On 09.03.2014 11:34, Hermann Norpois wrote:
Hello,
I have some problems with as.Date.
strDates <- c ("01/05/1965", "08/16/1975")
dates <- as.Date (strDates, "%m/%d%/%Y")
^
Remove the "%" after the "d".
Best,
Uwe Ligges
dates
[1] NA NA # I expected my da
Hello,
I have some problems with as.Date.
strDates <- c ("01/05/1965", "08/16/1975")
dates <- as.Date (strDates, "%m/%d%/%Y")
dates
[1] NA NA # I expected my dates. What was going wrong?
Thanks
Hermann
[[alternative HTML version deleted]]
__
R
From: Liz Hare
To: r-help@r-project.org
Cc:
Sent: Tuesday, July 30, 2013 12:00 PM
Subject: [R] as.Date with characters error
Hello,
I'm trying to convert dates in the format dd-mmm-yy using as.Date.
I have two columns like this, and it works on one but not on the other.
options(stringsAsF
Hi,
Did you checked after removing "e" from "formate"?
ortho$test.dat <- as.Date(ortho$xray.date, formate="%d-%b-%y")
A.K.
- Original Message -
From: Liz Hare
To: r-help@r-project.org
Cc:
Sent: Tuesday, July 30, 2013 12:00 PM
Subject: [R] as.Date w
Hello,
I'm trying to convert dates in the format dd-mmm-yy using as.Date.
I have two columns like this, and it works on one but not on the other.
> options(stringsAsFactors=FALSE)
> ortho <- read.csv("test1.csv", header=TRUE, nrows=10)
> ortho
DogID BirthDate xray.date
1 11877 23-Aug-87 15-F
Hi,
Try:
x<- c("2/26/13 11:59 PM", "2/25/13 10:25 AM")
strptime(x,"%m/%d/%y %I:%M %p")
#[1] "2013-02-26 23:59:00" "2013-02-25 10:25:00"
#or
library(lubridate)
parse_date_time(x,"%m/%d/%y %I:%M %p")
# 2 parsed with %m/%d/%y %I:%M %p
#[1] "2013-02-26 23:59:00 UTC" "2013-02-25 10:25:00 UTC"
A.K.
Hi,
You should have provided a reproducible example.
To convert in general, ?as.POSIXct()
A.K.
- Original Message -
From: Antonio Rodriges
To: r-help@r-project.org
Cc:
Sent: Tuesday, December 25, 2012 7:28 AM
Subject: [R] as.Date to as.POSIXct
Hello,
I have converted some UNIX
Hello,
I have converted some UNIX time stamps with as.Date as follows
dates_unix <- seq(
as.Date(convertTimeToString(timeStart)),
length = length(data),
by="1 mon")
and now I would like to convert "dates_unix" from type D
Hello,
Try reading the data file with stringsAsFactors = FALSE, like this you
don't have character vectors, you have factors, which are coded as
consecutive integers 1, 2, etc.
?read.table
?read.csv
See in particular the argument above, stringsAsFactors
Hope this helps,
Rui Barradas
Em 01
Please don't post files to nabble in the future -- when Nabble removes
them, we then have a broken link in the real archives: dput() is much
preferred way to send data.
Anyways:
# mydata <- read.csv("http://r.789695.n4.nabble.com/file/n4638691/jan_2011.csv";)
#
# dput(head(mydata, 15))
structure
Thank you Ricardogg and Arun. I don't know how I missed that. Too many
sleepless nights perhaps. Thank you.
--
View this message in context:
http://r.789695.n4.nabble.com/as-date-do-not-know-how-to-convert-mydata-1-to-class-Date-tp4638691p4638708.html
Sent from the R help mailing list archive
For me it owrks when i write it like:
as.Date(paste(mydata$Delivery.Date), "%m/%d/%Y")
Hope it works,
Regards,
Ricardo
--
View this message in context:
http://r.789695.n4.nabble.com/as-date-do-not-know-how-to-convert-mydata-1-to-class-Date-tp4638691p4638696.html
Sent from the R help mailin
I have an object, which I pull in from a csv file here
http://r.789695.n4.nabble.com/file/n4638691/jan_2011.csv jan_2011.csv
mydata <- read.csv("jan_2011.csv", header=TRUE, sep=",")
> head(mydata)
Delivery.Date Hour.Ending Repeated.Hour.Flag Settlement.Point
Settlement.Point.Price
101/01
On Apr 17, 2011, at 7:24 PM, Wonjae Lee wrote:
Thank you for replying the as.Date error question.
I have one more question as below.
I used cbind command, and data x changed, 2010-11-16 to 14929,
2010-11-17 to
14930.
What happened to them?
What should I do to see -mm-dd format data?
Thank you for replying the as.Date error question.
I have one more question as below.
I used cbind command, and data x changed, 2010-11-16 to 14929, 2010-11-17 to
14930.
What happened to them?
What should I do to see -mm-dd format data?
> x=c("11/16/2010","11/17/2010","11/18/2010","11/19/201
On Sun, 17 Apr 2011, Wonjae Lee wrote:
Hi,
I have some problems with as.Date function.
After I applied as.Date for my data, "2010" changed to "2020" as below
Where am I wrong?
You used %y (two-digit year, here: "20" and then expanded to "2020")
instead of %Y (four-digit year, here "2010").
as.Date(x,"%m/%d/%Y")
[1] "2010-11-16" "2010-11-17" "2010-11-18" "2010-11-19"
Notice the Y (four digit date).
Dennis
On Sun, Apr 17, 2011 at 6:34 AM, Wonjae Lee wrote:
> Hi,
>
> I have some problems with as.Date function.
> After I applied as.Date for my data, "2010" changed to "2020" as below
Hi,
I have some problems with as.Date function.
After I applied as.Date for my data, "2010" changed to "2020" as below
Where am I wrong?
Thanks
Wonjae
> x=c("11/16/2010","11/17/2010","11/18/2010","11/19/2010")
> x=as.Date(x,"%m/%d/%y")
> x
[1] "2020-11-16" "2020-11-17" "2020-11-18" "2020-11-19"
> Sent: 9. februar 2011 11:48
> To: Philipp Pagel
> Cc: BXC (Bendix Carstensen); r-help@r-project.org
> Subject: Re: [R] as.Date
>
> And I am hereby reporting this bug to the package maintainer.
>
> On Wed, 9 Feb 2011, Philipp Pagel wrote:
>
> > On Wed, Feb 09,
And I am hereby reporting this bug to the package maintainer.
On Wed, 9 Feb 2011, Philipp Pagel wrote:
On Wed, Feb 09, 2011 at 08:44:30AM +0100, Valeri Fabio wrote:
Hello,
I find out which package disturbs as.Date(). It is the package Epi:
as.Date(36525, origin="1900-01-01")
[1] "2000-01-0
On Wed, Feb 09, 2011 at 08:44:30AM +0100, Valeri Fabio wrote:
> Hello,
>
> I find out which package disturbs as.Date(). It is the package Epi:
>
> > as.Date(36525, origin="1900-01-01")
> [1] "2000-01-02"
> > library(Epi)
> > as.Date(36525, origin="1900-01-01")
> [1] "2070-01-01"
> > detach("packa
un...@r-project.org] On
Behalf Of Valeri Fabio
Sent: Mittwoch, 9. Februar 2011 08:12
To: r-help@r-project.org
Subject: Re: [R] as.Date
Thanks for the reply.
The original test was without the quote. The quote come into play when I try to
solve this problem changing from " to '. However
Sent: Dienstag, 8. Februar 2011 18:45
To: Philipp Pagel
Cc: r-help@r-project.org
Subject: Re: [R] as.Date
On Tue, 8 Feb 2011, Philipp Pagel wrote:
>> I have a strange behavior of the as.Date() function. For example:
>> as.Date(36525, origin="1900-01-01'")
>>
>>
On Tue, 8 Feb 2011, Philipp Pagel wrote:
I have a strange behavior of the as.Date() function. For example:
as.Date(36525, origin="1900-01-01'")
I would expect to get 2000-01-01. But R gives me
That's almost exactly what I get with R 2.11.1, LINUX (minus the
one-day differnce which is probably
> I have a strange behavior of the as.Date() function. For example:
> as.Date(36525, origin="1900-01-01'")
>
> I would expect to get 2000-01-01. But R gives me
That's almost exactly what I get with R 2.11.1, LINUX (minus the
one-day differnce which is probably correct, too lazy to count leap
year
On Feb 8, 2011, at 11:15 AM, Valeri Fabio wrote:
Hi everybody,
I have a strange behavior of the as.Date() function.
No, you have a programming error.
For example:
as.Date(36525, origin="1900-01-01'")
You have a superfluous "'"
> as.Date(36525, origin="1900-01-01")
[1] "2000-01-02"
Hi everybody,
I have a strange behavior of the as.Date() function. For example:
as.Date(36525, origin="1900-01-01'")
I would expect to get 2000-01-01. But R gives me
[1] "2070-01-01"
I tried with several origins but the results are still the same. It
seems that the origin does n
Try this:
format(dt, '%Y-%m-%d'), if you want Date class:
as.Date(format(dt, '%Y-%m-%d'))
On Mon, Sep 13, 2010 at 2:24 PM, Andrew Yee
wrote:
Thanks David, now I wonder how you can have as.Date() render the
date using
local time rather than UTC.
Andrew
On Mon, Sep 13, 2010 at 12:08 PM
Henrique, thanks for your suggestion. For my applications, character would
have been sufficient, so your suggestion of using format() works fine too.
Perhaps I should submit a feature request for as.Date() to let you specify
local time.
Thanks,
Andrew
On Mon, Sep 13, 2010 at 2:06 PM, Henrique D
On Sep 13, 2010, at 1:24 PM, Andrew Yee wrote:
> Thanks David, now I wonder how you can have as.Date() render the
> date using local time rather than UTC.
>
Since we are both in the EDT TZ at the moment, our times are UTC-4
(hours = 60*60 seconds)
> dt <- as.POSIXct("2010-08-22 23:14:52")
Thanks David, now I wonder how you can have as.Date() render the date using
local time rather than UTC.
Andrew
On Mon, Sep 13, 2010 at 12:08 PM, David Winsemius wrote:
>
> On Sep 13, 2010, at 11:56 AM, Andrew Yee wrote:
>
> I'm trying to understand why as.Date() is converting a the modified dat
On Sep 13, 2010, at 11:56 AM, Andrew Yee wrote:
I'm trying to understand why as.Date() is converting a the modified
date of
a file from August 22 to August 23.
foo <- file.info(file.to.process)
str(foo)
'data.frame': 1 obs. of 10 variables:
$ size : num 5.37e+09
$ isdir : logi FALSE
$
I'm trying to understand why as.Date() is converting a the modified date of
a file from August 22 to August 23.
> foo <- file.info(file.to.process)
> str(foo)
'data.frame': 1 obs. of 10 variables:
$ size : num 5.37e+09
$ isdir : logi FALSE
$ mode :Class 'octmode' int 436
$ mtime : POSIX
TY for the tip. The lower case is in fact the culprit.
> -Original Message-
> From: Erik Iverson [mailto:er...@ccbr.umn.edu]
> Sent: Tuesday, June 01, 2010 6:05 PM
> To: arnaud Gaboury
> Cc: r-help@r-project.org
> Subject: Re: [R] as.date
>
>
> > Whe
Change this line to :
>pose$CREATED.DATE=as.Date(pose$CREATED.DATE,"%d/%m/%Y") # mind the capital
Y
>pose
DESCRIPTION CREATED.DATE QUANITY CLOSING.PRICE
1 COTTON NO.2 Jul/10 2010-05-13 1 81.2000
2 COTTON NO.2 Jul/10 2010-05-13 1 81.2000
3 PALLADIUM Jun/10 2010-05-
Hello,
The lowercase 'y' is year without century. This should work for you:
as.Date(x=df$CREATED.DATE, format="%d/%m/%Y")
HTH,
Josh
On Tue, Jun 1, 2010 at 8:57 AM, arnaud Gaboury wrote:
> Dear group,
>
> Here is my df (obtained with a read.csv2()):
>
>
> df <-
> structure(list(DESCRIPTION =
Where does the problem comes from?? Maybe from my sytem date ??
Simply from not reading the options carefully enough, from ?strptime,
‘%y’ Year without century (00-99). If you use this on input, which
century you get is system-specific. So don't! Most often
values 0
Dear group,
Here is my df (obtained with a read.csv2()):
df <-
structure(list(DESCRIPTION = c("COTTON NO.2 Jul/10", "COTTON NO.2 Jul/10",
"PALLADIUM Jun/10", "PALLADIUM Jun/10", "SUGAR NO.11 Jul/10",
"SUGAR NO.11 Jul/10"), CREATED.DATE = c("13/05/2010", "13/05/2010",
"14/05/2010", "14/05/2010
zzz1 is POSIXct so looking at:
> as.Date.POSIXct
function (x, ...)
{
z <- floor(unclass(x)/86400)
attr(z, "tzone") <- NULL
structure(z, class = "Date")
}
we see as.Date.POSIXct takes the POSIXct object, zzz1, and converts it
to Date relative to GMT. There is no time zone argument on
e answer.
>
> Usually one has x=y --> f(x)=f(y)
>
> which doesn't seem to hold here (put x=zzz1, y=zzz2, f=as.Date()).
>
> Or do I overlook something?
>
>
> - Original Message - From: "Marek Janad"
> To:
> Sent: Thursday, December 24, 20
Mark, not sure that's the answer.
Usually one has x=y --> f(x)=f(y)
which doesn't seem to hold here (put x=zzz1, y=zzz2, f=as.Date()).
Or do I overlook something?
- Original Message -
From: "Marek Janad"
To:
Sent: Thursday, December 24, 2009 00:08
S
Look at documentation
?as.Date
as.Date first represents time in UTC, what gives:
as.POSIXlt(zzz1, tz="UTC")
HTH
2009/12/20 MAL :
> All!
>
> This piece of code:
>
> zzz1 <- as.POSIXct("1999-03-18", tz="CET")
> zzz2 <- as.POSIXlt("1999-03-18", tz="CET")
> zzz1 == zzz2
> as.Date(zzz1)
> as.Date(z
I don't know the details of why this is happening, but in any case it
is a good idea to round() your times if you want to convert them to
dates. Just as you would round() a numeric value to convert it to an
integer.
as.Date(round(zzz1, "days"))
2009/12/21 Jason Morgan :
> Hello,
>
> On 2009.12.2
All!
This piece of code:
zzz1 <- as.POSIXct("1999-03-18", tz="CET")
zzz2 <- as.POSIXlt("1999-03-18", tz="CET")
zzz1 == zzz2
as.Date(zzz1)
as.Date(zzz2)
yields TRUE for "zzz1==zzz2", but the two dates returned by as.Date are
different:
as.Date(zzz1)
[1] "1999-03-17"
as.Date(zzz2)
[1] "199
Hello,
On 2009.12.20 18:06:17, MAL wrote:
> All!
>
> This piece of code:
>
> zzz1 <- as.POSIXct("1999-03-18", tz="CET")
> zzz2 <- as.POSIXlt("1999-03-18", tz="CET")
> zzz1 == zzz2
> as.Date(zzz1)
> as.Date(zzz2)
>
> yields TRUE for "zzz1==zzz2", but the two dates returned by as.Date are
> diff
All!
This piece of code:
zzz1 <- as.POSIXct("1999-03-18", tz="CET")
zzz2 <- as.POSIXlt("1999-03-18", tz="CET")
zzz1 == zzz2
as.Date(zzz1)
as.Date(zzz2)
yields TRUE for "zzz1==zzz2", but the two dates returned by as.Date are
different:
> as.Date(zzz1)
[1] "1999-03-17"
> as.Date(zzz2)
[1] "1999-
Hello Gentlemen,
All of your answers were helpfull. Indeed, 'as.is=TRUE' or
'stringsAsFactors=FALSE' avoid importing as factors, as it did when I
imported the table without specifying anything. However, data frames will
not allow different datatypes within a single column, so, for time series, I
On Nov 11, 2009, at 1:06 PM, separent wrote:
#Hello,
#I loaded data using read.table - I needed to convert a row in the
data
frame to date class:
You _should_ have given the actual code (as the Posting Guide
requests), but I would guess that you should have added either
as.is=TRUE or
On Nov 11, 2009, at 12:06 PM, separent wrote:
#Hello,
#I loaded data using read.table - I needed to convert a row in the
data
frame to date class:
data
V1 V2 V3 V4
1 2008-05-19 2008-04-19 2008-03-21 2008-02-22
2 38.16999817 30.7008 36.8661 35.18999
Hi,
On Nov 11, 2009, at 1:06 PM, separent wrote:
#Hello,
#I loaded data using read.table - I needed to convert a row in the
data
frame to date class:
data
V1 V2 V3 V4
1 2008-05-19 2008-04-19 2008-03-21 2008-02-22
2 38.16999817 30.7008 36.8661 35.1
#Hello,
#I loaded data using read.table - I needed to convert a row in the data
frame to date class:
> data
V1 V2 V3 V4
1 2008-05-19 2008-04-19 2008-03-21 2008-02-22
2 38.16999817 30.7008 36.8661 35.18999863
3 37.4754 29.9576 36.4508 35.366
In the development version of R the output
changes to:
> x1 = as.POSIXlt("2008-01-02 00:58:00")
>
> x2 = as.POSIXct("2008-01-02 00:58:00")
>
> as.Date(x1); as.Date(x2)
[1] "2008-01-02"
[1] "2008-01-02"
>
> R.version.string
[1] "R version 2.8.0 Under development (unstable) (2008-06-28 r46012)"
O
Hi,
I'm working with objects of classes "Date","POSIXlt" and "POSIXct" and still
having some Date/Time-related concepts unclear. In the documentation of
"as.Date" one can find:
"The 'as.Date' methods accept ... '"POSIXlt"' and '"POSIXct"'. (The last are
converted to days by ignoring the time afte
> "PD" == Peter Dalgaard <[EMAIL PROTECTED]>
> on Thu, 03 Jul 2008 12:07:41 +0200 writes:
[..]
PD> and the help page has the explanation.
[..]
PD> [By the way, there used to be a way to see the current help pages on the
PD> web, but I can't remember how.
Ron Michael wrote:
> When I use the code as.Date(0) the I get : "1970-01-01". My question is why
> it is like that? help file on as.Date seems to give no light on that. Can
> anyone clarify me?
>
Which version of R is this?
R version 2.7.1 (2008-06-23)
...
> as.Date(0)
Error in as.Date.numeri
On Thu, 3 Jul 2008, Ron Michael wrote:
When I use the code as.Date(0) the I get : "1970-01-01". My question is
why it is like that? help file on as.Date seems to give no light on
that. Can anyone clarify me?
In R, "Date" objects are stored internally as the number of days since
1970-01-01 (t
When I use the code as.Date(0) the I get : "1970-01-01". My question is why it
is like that? help file on as.Date seems to give no light on that. Can anyone
clarify me?
Â
Regards,
Send instant messages to your online friends http://uk.messenger.yahoo.com
[[alternative HTML version dele
Hi Terry,
thanks for the information, I should know this in advance but I´m not used
to case sensitive syntax - thanks Delphi...
regards,
Eric Will
Terry Therneau wrote:
>
>>> Konga wrote:
Hi,
I have a data.frame with the following variable:
$ xx :Factor w/ 66 levels "0
>> Konga wrote:
>>> Hi,
>>>
>>> I have a data.frame with the following variable:
>>> $ xx :Factor w/ 66 levels "01.02.2006","01.03.2006",..: 3 3 3 3 3 3 3 3
>>> 3
>>>
>>> now I?d like use "as.date" on it - if I comprehend the instructions on
>>> http://finzi.psych.upenn.edu/R/library/base/html/fo
Thanks a lot, it works!
Now I have to find out why - but I think I can/should do it on my own ;o)
--
View this message in context:
http://www.nabble.com/as.date---german-date-format-tp14712654p14728914.html
Sent from the R help mailing list archive at Nabble.com.
___
"Functions to convert between character
representations and objects of class "Date"
representing calendar dates."
$ xx :Factor w/ 66 levels
try as.character(xx)
--- Konga <[EMAIL PROTECTED]> wrote:
>
> Hi,
>
> I have a data.frame with the following variable:
> $ xx :Factor w/ 66 levels
Konga wrote:
>
> Uwe Ligges-3 wrote:
>>
>>
>> Konga wrote:
>>> Hi,
>>>
>>> I have a data.frame with the following variable:
>>> $ xx :Factor w/ 66 levels "01.02.2006","01.03.2006",..: 3 3 3 3 3 3 3 3
>>> 3
>>>
>>> now I´d like use "as.date" on it - if I comprehend the instructions on
>>> http:
Uwe Ligges-3 wrote:
>
>
>
> Konga wrote:
>> Hi,
>>
>> I have a data.frame with the following variable:
>> $ xx :Factor w/ 66 levels "01.02.2006","01.03.2006",..: 3 3 3 3 3 3 3 3
>> 3
>>
>> now I´d like use "as.date" on it - if I comprehend the instructions on
>> http://finzi.psych.upenn.ed
Konga wrote:
> Hi,
>
> I have a data.frame with the following variable:
> $ xx :Factor w/ 66 levels "01.02.2006","01.03.2006",..: 3 3 3 3 3 3 3 3 3
>
> now I´d like use "as.date" on it - if I comprehend the instructions on
> http://finzi.psych.upenn.edu/R/library/base/html/format.Date.html
>
Hi,
I have a data.frame with the following variable:
$ xx :Factor w/ 66 levels "01.02.2006","01.03.2006",..: 3 3 3 3 3 3 3 3 3
now I´d like use "as.date" on it - if I comprehend the instructions on
http://finzi.psych.upenn.edu/R/library/base/html/format.Date.html
it should work like this:
as.
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