Re: [R] Regex - subsetting parts of a file name.

2014-07-31 Thread arnaud gaboury
> > R> as.vector(sapply(my.cache.list, function(x)strsplit(x, "\\.")[[1]][2])) > [1] "subject_test" "subject_train" "y_test""y_train" > > > R> gsub("df\\.(.*)\\.RData", "\\1", my.cache.list) > [1] "subject_test" "subject_train" "y_test""y_train" > > > Note that "." will match any

Re: [R] Regex - subsetting parts of a file name.

2014-07-31 Thread Sarah Goslee
Hi, Here are two possibilities: R> as.vector(sapply(my.cache.list, function(x)strsplit(x, "\\.")[[1]][2])) [1] "subject_test" "subject_train" "y_test""y_train" R> gsub("df\\.(.*)\\.RData", "\\1", my.cache.list) [1] "subject_test" "subject_train" "y_test""y_train" Note that "

Re: [R] Regex - subsetting parts of a file name.

2014-07-31 Thread arun
Try: gsub(".*\\.(.*)\\..*","\\1", my.cache.list) [1] "subject_test"  "subject_train" "y_test"    "y_train" #or library(stringr) str_extract(my.cache.list, perl('(?<=\\.).*(?=\\.)')) [1] "subject_test"  "subject_train" "y_test"    "y_train"  A.K. On Thursday, July 31, 2014 11:05 AM,

Re: [R] Regex - subsetting parts of a file name.

2014-07-31 Thread S Ellison
> I want to keep only the part inside the two points. After lots of headache > using grep() when trying something like this: > > grep('.(.*?).','df.subject_test.RData',value=T) > > > Does anyone have any suggestion ? gsub("df\\.(.+)\\.RData", "\\1", 'df.subject_test.RData') Steve E ***

[R] Regex - subsetting parts of a file name.

2014-07-31 Thread arnaud gaboury
A directory is full of data.frames cache files. All these files have the same pattern: df.some_name.RData my.cache.list <- c("df.subject_test.RData", "df.subject_train.RData", "df.y_test.RData", "df.y_train.RData") I want to keep only the part inside the two points. After lots of headache using