Hi,
Here are two possibilities:
R> as.vector(sapply(my.cache.list, function(x)strsplit(x, "\\.")[[1]][2]))
[1] "subject_test" "subject_train" "y_test" "y_train"
R> gsub("df\\.(.*)\\.RData", "\\1", my.cache.list)
[1] "subject_test" "subject_train" "y_test" "y_train"
Note that "." will match any character, while "\\." matches a period.
Sarah
On Thu, Jul 31, 2014 at 4:27 AM, arnaud gaboury
<arnaud.gabo...@gmail.com> wrote:
> A directory is full of data.frames cache files. All these files have
> the same pattern:
>
> df.some_name.RData
>
> my.cache.list <- c("df.subject_test.RData", "df.subject_train.RData",
> "df.y_test.RData",
> "df.y_train.RData")
>
> I want to keep only the part inside the two points. After lots of
> headache using grep() when trying something like this:
>
> grep('.(.*?).','df.subject_test.RData',value=T)
>
> I couldn't find a clean one liner and found this workaround:
>
> my.cache.list <- gsub('df.','',my.cache.list)
> my.cache.list <- gsub('.RData','',my.cache.list)
>
> The two above commands do the trick, but a clean one line with some
> regex expression would be a more "elegant" way.
>
> Does anyone have any suggestion ?
>
> TY for help
>
--
Sarah Goslee
http://www.functionaldiversity.org
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