Thanks Kingsford. I thought the column power was supposed to be just for
that column but you're probably correct. English has its oddities
because if one reads the actual sentence the person wrote it's still not
clear, atleast to me.
"Actually I want to have a matrix with p columns such that
On Fri, Jan 9, 2009 at 6:36 PM, wrote:
> Charlotte: I ran your code because I wasn't clear on it and your way would
> cause more matrices than the person requested.
Bhargab gave us
x<-c(23,67,2,87,9,63,8,2,35,6,91,41,22,3)
and said: "I want to have a matrix with p columns such that each
c
Charlotte: I ran your code because I wasn't clear on it and your way
would cause more matrices than the person requested. So
I think the code below it, although not too short, does what the person
asked. Thanks though because I understand outer better now.
temp <- matrix(c(1,2,3,4,5,6),ncol=2)
One of those more elegant ways:
outer(x, 1:p, "^")
Charlotte
On Fri, Jan 9, 2009 at 4:24 PM, Sarah Goslee wrote:
> Well, mat doesn't have any dimensions / isn't a matrix, and we don't
> know what p is supposed to be. But leaving aside those little details,
> do you perhaps want something like th
Well, mat doesn't have any dimensions / isn't a matrix, and we don't
know what p is supposed to be. But leaving aside those little details,
do you perhaps want something like this:
x<-c(23,67,2,87,9,63,8,2,35,6,91,41,22,3)
p <- 5
mat<- matrix(0, nrow=p, ncol=length(x))
for(
Hi,
Can any one please explain why the following code doesn't work? Or can anyone
suggest an alternative.
Suppose
x<-c(23,67,2,87,9,63,8,2,35,6,91,41,22,3)
mat<-0;
for(j in 1:length(x))
{
for(i in 1:p)
mat[i,j]<-x[j]^i;
}
A
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