Well, mat doesn't have any dimensions / isn't a matrix, and we don't
know what p is supposed to be. But leaving aside those little details,
do you perhaps want something like this:
x<-c(23,67,2,87,9,63,8,2,35,6,91,41,22,3)
p <- 5
mat<- matrix(0, nrow=p, ncol=length(x))
for(j in 1:length(x))
{
for(i in 1:p)
mat[i,j]<-x[j]^i
}
Two notes: I didn't try it out, and if that's what you want rather
than a toy example
of a larger problem, there are more elegant ways to do it in R.
Sarah
On Fri, Jan 9, 2009 at 6:42 PM, Bhargab Chattopadhyay
<bharga...@yahoo.com> wrote:
> Hi,
>
>
> Can any one please explain why the following code doesn't work? Or can anyone
> suggest an alternative.
> Suppose
> x<-c(23,67,2,87,9,63,8,2,35,6,91,41,22,3)
> mat<-0;
> for(j in 1:length(x))
> {
> for(i in 1:p)
> mat[i,j]<-x[j]^i;
> }
> Actually I want to have a matrix with p columns such that each column will
> have the elements of x^(column#).
>
> Thanks in advance.
>
> Bhargab
>
>
>
--
Sarah Goslee
http://www.functionaldiversity.org
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