Another possibility is
mapply(rbind,list1,list2,SIMPLIFY=FALSE)
- Phil Spector
Statistical Computing Facility
Department of Statistics
will this do it for you:
> lapply(seq(length(list1)), function(i)rbind(list1[[i]], list2[[i]]))
[[1]]
[,1] [,2] [,3] [,4] [,5]
[1,]16 11 16 21
[2,]27 12 17 22
[3,]38 13 18 23
[4,]49 14 19 24
[5,]5 10 15 20 25
[6,] 10 11
Hi, I am wondering whether we can apply 'cbind/rbind' on many **equivalent**
list objects. For example please consider following:
> list1 <- list2 <- vector("list", length=2); names(list1) <- names(list2)
<- c("a", "b")
> list1[[1]] <- matrix(1:25, 5)
> list1[[2]] <- matrix(2:26, 5)
> list2[[1]] <
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