will this do it for you:
> lapply(seq(length(list1)), function(i)rbind(list1[[i]], list2[[i]]))
[[1]]
[,1] [,2] [,3] [,4] [,5]
[1,] 1 6 11 16 21
[2,] 2 7 12 17 22
[3,] 3 8 13 18 23
[4,] 4 9 14 19 24
[5,] 5 10 15 20 25
[6,] 10 11 12 13 14
[[2]]
[,1] [,2] [,3] [,4] [,5]
[1,] 2 7 12 17 22
[2,] 3 8 13 18 23
[3,] 4 9 14 19 24
[4,] 5 10 15 20 25
[5,] 6 11 16 21 26
[6,] 11 12 13 14 15
On Sun, Feb 6, 2011 at 1:32 PM, B. Jonathan B. Jonathan
<bkheijonat...@gmail.com> wrote:
> Hi, I am wondering whether we can apply 'cbind/rbind' on many **equivalent**
> list objects. For example please consider following:
>
>> list1 <- list2 <- vector("list", length=2); names(list1) <- names(list2)
> <- c("a", "b")
>> list1[[1]] <- matrix(1:25, 5)
>> list1[[2]] <- matrix(2:26, 5)
>> list2[[1]] <- 10:14
>> list2[[2]] <- 11:15
>> list1
> $a
> [,1] [,2] [,3] [,4] [,5]
> [1,] 1 6 11 16 21
> [2,] 2 7 12 17 22
> [3,] 3 8 13 18 23
> [4,] 4 9 14 19 24
> [5,] 5 10 15 20 25
> $b
> [,1] [,2] [,3] [,4] [,5]
> [1,] 2 7 12 17 22
> [2,] 3 8 13 18 23
> [3,] 4 9 14 19 24
> [4,] 5 10 15 20 25
> [5,] 6 11 16 21 26
>> list2
> $a
> [1] 10 11 12 13 14
> $b
> [1] 11 12 13 14 15
>
> Here I want to "rbind" these 2 list-s according to "a" and "b" i.e. I want
> to get another list of length 2 where each element will be matrix with (6x5)
> dimension. How can I do that?
>
> Thanks for your time
>
> [[alternative HTML version deleted]]
>
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>
--
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
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