e are in hdf4 format.
Thank you
Uday
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hi ,
last time I did not mention the specific version of linux and it was problem
with only syntax but with correction I got new error.
I found that some people has faced this problem before and some of them
have mentioned that it may be because of dependencies issue and
install.packages("Rcmd
is problem.
install.packages("hdf5")
Installing package(s) into ‘/home/uday/R/x86_64-pc-linux-gnu-library/2.14’
(as ‘lib’ is unspecified)
trying URL
'http://cran.revolutionanalytics.com/src/contrib/hdf5_1.6.9.tar.gz'
Content type 'application/x-gzip
Hi
Thanks for reply
after usinginstall.packages("hdf5")
I get error
{Installing package(s) into ‘/home/uday/R/x86_64-pc-linux-gnu-library/2.14’
(as ‘lib’ is unspecified)
trying URL
'http://cran.revolutionanalytics.com/src/contrib/hdf5_1.6.9.tar.gz'
Content type 'applica
Hi,
Recently I have installed R in my Linux operating system , after
installation I was trying to install some packages and I was getting error
installed.packages("hdf5")
{ Package LibPath Version Priority Depends
Imports LinkingTo Suggests Enhances OS_type
License Archs Built}
this
I would like to calculate vector from existing value
e.g
v <- 1000
s <- 30
d1<- v-s
d1<- 970
d2<- d1 -s
d2<- 940
d 3 <- d2-s
d3<- 910
:
:
d15 <- .
so how I should get vector of length 15
roblem is bit more clear than before
Cheers
Uday
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h
approx function
approx(pres, sci.pre)
Error in xy.coords(x, y) : 'x' and 'y' lengths differ
I am looking for interpolated output with 1 x 19 demotions .
does somebody knows how to deal with this issue ?
Thanks
Uday
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I have some dataset
ak[1:3,]
[,1] [,2] [,3] [,4] [,5] [,6] [,7]
[,8] [,9]
[1,] 0.3211745 0.4132568 0.5649930 0.6920562 0.7760113 0.8118568 0.8609301
0.9088819 0.9326736
[2,] 0.3159234 0.
Hi Rui,
Thanks a lot it works
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lines(ak[2,],pre[2,],type="l",col="red")
but every files contains more than 1000 observations.
Is it possible to use this function for two different matrix data ?
if yes then please let me know how to do it .
Thanks
Uday
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Hi Liviu ,
thanks for post , but I could not find findFn('spaghetti') , I can see the
following functions in sos package
Extract.findFn
findFn
grepFn
hits
installPackages
PackageSum2
PackageSummary
print.findFn
sortFindFn
summary.findFn
unionFindFn
writeFindFn2xls
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I would like to plat some spaghetti plots from my data , ma data is as
follows
ak[1:3,]
[,1] [,2] [,3] [,4] [,5] [,6] [,7]
[,8] [,9]
[1,] 0.3211745 0.4132568 0.5649930 0.6920562 0.7760113 0.8118568 0.8609301
0.9088819 0.9326736
[2,] 0.3159234 0.407
Does anybody knows how to convert Modified Julian Days(MJD) to YMDHMS format?
The sample data set which I have is as follows
time <- c(1832.415 ,1832.415 ,1832.415 ,1832.415 ,1832.415 ,1832.415
,1832.415, 1832.415, 1832.415 ,1832.415)
which is Days since "1.1.2000" (in UT time, starting at 00:00:
Hi Hth -- Gerrit ,
thanks for reply
sorry it was typo mistake , but I corrected that problem before . But the
error is still same.
setwd("/Groups/data_first/")
file_was <- list.files(path = ".", pattern = "v2.0.2.was", all.files =
FALSE, full.names = FALSE, recursive = FALSE, ignore.case =
ive = FALSE, ignore.case = FALSE)
path<-c("/Groups/data_second/")
file_wasaux2 <-list.files(path,pattern="v2.0.2.wasaux2")
files<- 1
for ( i in files){
data1 <- read.table(file_was[i],header=TRUE)
data2 <- read.table(paste(path, file_wasaux2[i],se
I would like to read data from two different folder and then combine this
together
the code which I have tried are as follows
setwd("/Groups/data_first/")
file_was <- list.files(path = ".", pattern = "v2.0.2.was", all.files =
FALSE, full.names = FALSE, recursive = FALSE, ignore.case = FALSE)
path
Hi Ray,
Thanks for reply
/R/PlotGridded2DMap.R
/R/image.plot.fix.R
/R/image.plot.plt.fix.r
are the functions those I wrote for plotting and they work with another
data, but only I have some issue with only the codes those I provided
before.
and what do you mean by " I am redefining the map()
I am using following codes to plot map
library(sp)
library(rgdal)
library(maps)
library(gplots)
library(clim.pact)
library(fields)
source("/R/PlotGridded2DMap.R")
source("/R/image.plot.fix.R")
source("/R/image.plot.plt.fix.r")
seasonal_plot<-function(input,lonll=-180,latll=-90,lonres=5.,latres=3
Hey Gerrit ,
Thanks your solution works
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htt
I want to replace some values in my Array
e.g
data<- c(1,2,3,4,5,6,7,8,9,10,11,12)
I would like to replace 1,2,3 by 1 , 4,5,6 by 2, 7,8,9 by 3 and 10,11,12 by
4
I am expecting out put
data<- 1 1 1 2 2 2 3 3 3 4 4 4
I have tried replace function
replace(data, (data==1 |data==2| data==3),1)
I would like to read hdf5 or h5 files in R .
I found two packages hdf5 and h5r , but in both packages they have
information how to get attribute from data.
In my case I would like see what kind of parameters are saved in every file.
I have tried
h5 <- hdf5load("GOSATTFTS20090601_02C02SV0002R101
a.2005[1:3], data.2006[4:6])
cheers
Uday
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ht
I got two .RData file e.g data.2005.RData & data.2006.RData
I would like to combine these two different data set and make single RData
file.
in both file there are some NULL files are also available and I would like
to clear this NULL files also.
$ : NULL
$ : NULL
$ : num [1:43285, 1:8] -21.1
I would like to convert my point data to grid data
my data contains e.g
lat <- c(25.1618 , 24.8664, 21.0575, 21.1537, 21.2477, 21.3403,
20.7617, 20.8577, 20.9516, 21.0443)
lon <- c(55.7660, 55.6890, 54.7205, 54.2142, 53.7105,53.2053, 54.6470,
54.1419, 53.6389, 53.1348)
z <- c(
I am plotting some data using sp package
library (sp)
library(maps)
data.aggm # data
# Define standard projection
ll <- CRS("+proj=longlat +datum=WGS84")
# convert to a SpatialPointsDataFrame
xy <- cbind(data.aggm[,1], data.aggm[,2])
ch4.spPoints <- SpatialPointsDataFrame(coor
The following error I got
Warning messages:
1: In sci.lat[i] = data[, 7] :
number of items to replace is not a multiple of replacement length
2: In sci.lon[i] = ((temp.lon + 180)%%360) - 180 :
number of items to replace is not a multiple of replacement length
3: In sci.ch4[i] = data[, 45] :
I want to create r object from my data set.
I have several data files and I would like to read individual parameter
from file and save all 10 files parameter in a single array
e.g
setwd("/temp/")
file_s <- list.files(path = ".", pattern = "0b.was", all.files = FALSE,
full.na
Hi Iris,
thanks for reply
but this solution does not work
Uday
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Michael , the first error which I got is
"number of items to replace is not a multiple of replacement length"
sorry last time it did not copied whole thing
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Thanks for reply Michael
the error which I got is as follows :
Error in gzfile(file, "wb") : cannot open the connection
In addition: Warning message:
In gzfile(file, "wb") :
cannot open compressed file 'data.RData', probable reason 'Permission
denied'
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atitude,longitude=longitude, time=time,temp=temp,
file="data.RData")
but it does not work.
I am new in R and I got stuck here.
Cheers
Uday
I am beginner in R and I got stuck here
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at least two dimensions
it need matrix, so is there any way to deal with this kind of problem.
Cheers
Uday
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Hi Dan,
I am sorry about that it was typo mistake but the both values are -999.99 .
your solution works.
Thanks
Uday
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6 -999.00
expected answer
[,1] [,2][,3]
[1,]255.00
[2,]369.00
I am new in R & I got stuck with this step.
Uday
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Sent from the R hel
ould like to do is I want to plot data according to my observations
taken ( its in month)
but when I run my codes it plots same file from2005:2008 but it suppose to
plot 48 different files for different months.
I got stuck here, I am quit new in R.
it would be very nice it somebody can tell me
Thank you Michael
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I have some data set which is available from 2005-2010 . I would like plot
monthly maps out of it.
So how I should write loop that can plot this yearly data to for every month
and write title for individual months too.
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I want to use spplot function for plotting data on wold map
spplot.points(obj, zcol = names(obj), ..., names.attr,
scales = list(draw = FALSE), xlab = NULL, ylab = NULL, aspect =
mapasp(obj,xlim,ylim),
panel = panel.pointsplot, sp.layout = NULL, identify = FALSE, formula,
Hi ,
Thanks for reply
My latitude and longitude contains 9-10 observations per file
when I run coords <- expand.grid(lat=1:5,long=1:5) then my computer
*** caught segfault ***
address 0x6951c20, cause 'memory not mapped'
Traceback:
1: .C("spline_eval", z$method, nu = as.integer(n),
The dimensions of variables are unknown , they changes to every file.
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Hi it works fine
thanks
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I have some data set which has latitude, longitude and Z values.
I would like to plot them on global map.
I am thinking to use image
image(x, y, z, zlim, xlim, ylim, col = heat.colors(12),
add = FALSE, xaxs = "i", yaxs = "i", xlab, ylab,
breaks, oldstyle = FALSE, useRaster = FALSE, .
I have some data files e.g 100 . and after for loop I would like to save all
data in one single data frame
file_s <- list.files(path = ".", pattern = "v2.0.2.txt", all.files = FALSE,
full.names = FALSE, recursive = FALSE,
ignore.case = FALSE)
for (i in 1:100){
Hi Petr,
You were correct , thats was the mistake . I am sorry for last reply. now
its working.
Cheers
Uday
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I have some dataset
sci.pre <- 0.300.380.500.650.801.031.331.72
2.22
2.873.815.066.759.00 11.97 14.15 16.34 19.04
22.27 25.49 29.72 34.67 40.47 47.29 55.29 64.67 75.6
88.50 103.50 121.10 141.70 165.80 194.00 22
Dear Uwe ,
Thanks for reply
I have tried format function that u suggested (format(time_t1, "%Y %m %d %H
%M %S") and I got
format(time_t1, "%Y %m %d %H %M %S")
[1] "126230400" "126252000" "126273600" "126295200" "126316800" "126338400"
I think something is not working correct.
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I have some time data and which is in seconds
time <-c( 126230400 126252000 126273600 126295200 126316800 126338400)
now I wanted to convert this time to Y M D H M S format
I have tried following codes but it does not give me the out put in Y M D
H M S
time_t1 <- as.POSIXlt(time, origin="200
spDistsN1(m, m[1,], longlat=TRUE)
hist(dist[2:9997])
try <- deldir(sci_lon,sci_lat)
try_p <- deldir(sci_lon,sci_lat,plot=TRUE,wl='tr')
Now I would like to calculate the length of each triangulated face , could
somebody please tell me how to calculate it ?
Cheers
Uday
I have some satellite data which contains latitude and longitude information
.
>From this data I would like to calculate distance between first location
(scalar latitude and longitude) and all other (vectors latitude and
longitude)
How I should solve this problem ?
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Hi Thanks for reply, there was some mistakes in typo. I have already
corrected it.
this function gives us closest point ( R book reference).
So I would like to find all observations on another grid spatially and
temporally.
the function is just for finding all closest observations.
uday
sorry there is typing error in codes
the correct ones are
nobs<-length(s_lat)
for (i in 1:length(nobs)){lat_match<- which(abs(t_lat - s_lat ==
min(abs(t_lat - s_lat)))}
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Dear All,
I have data set which includes details of locations e.g latitude, longitude
, time.
I would like to compare two different data sets ( sampling in space and
time).
the e.g data sets are as follows
t_lat
[1] -90.00 -86.17 -82.34 -78.51 -74.68 -70.85 -67.02 -63.19 -59.36 -55.53
-51.70
I new in R programming language.
I have some time data
time
[1] "2005-01-03 05:11:39 UTC" "2005-01-03 06:36:02 UTC" "2005-01-03
06:36:55 UTC"
[4] "2005-01-03 06:37:00 UTC" "2005-01-03 06:38:04 UTC" "2005-01-03
06:38:04 UTC"
[7] "2005-01-03 06:38:04 UTC" "2005-01-03 06:38:04 UTC" "2005-01-03
Hi,
How I should convert Fractional days in Year Month Days Hour Minute and Day
format ?
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