example at the bottom)
Frank
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e terrific (thanks to the
program committee and the speakers) and Kate Mullen and her team did an
extraordinary job in putting the conference together and running it. I
am proud to have been a part of it. Thank you all!
Frank
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(as in checking
goodness of fit of various parametric distributions), your final
estimators will have the variance of empirical estimators.
Frank
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on;
some perl code
perl off;
also
sas on;
some SAS code
sas off;
The purpose of parmbuff is to turn off of Rs scanning and resolution of
function arguments
and just provide the bare text between '(' and ')' in the function call.
This is a very powerful construct
(>|t|) value using the linear
model, then deleting the non-significant levels. Any other
suggestions?
Thanks,
Saeed
That is not a valid statistical procedure. You will not have the
correct d.f. in the final F test.
Frank
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//asrr.r-forge.r-project.org/rghuang.html
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contained, reproducible code.
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You still are stating the effect of the central limit theorem
incorrectly. Please see my previous note.
Frank
On 06/25/2010 10:27 AM, Joris Meys wrote:
> 2010/6/25 Frank E Harrell Jr:
>> The central limit theorem doesn't help. It just addresses type I error,
>> not power
gt;
>> i would like to test, whether the mean of the sample differ significantly
>> from the population mean.
>>
> According to probability theory, this will be in 5% of the cases if
> you repeat your sampling infinitly. But as David asked: why on earth
> do y
e indicator (0/1) of xi
+ xj > 0. So WSR tests H0:p=0.5 where p = the probability that the
average of a randomly chosen pair of values is positive. [If there are
ties this probably needs to be worded as P[xi + xj > 0] = P[xi + xj <
0], i neq j.
Frank
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y of
SAS serving hundreds of users.
Cheers,
Bob
Ted.
E-Mail: (Ted Harding)
Fax-to-email: +44 (0)870 094 0861
Date: 20-Jun-10 Time: 20:41:43
---------- XFMail
special case where each variable has only one degree of freedom.
Just do a <- anova(mod.poly3) and treat the result as matrix. You'll
get the needed multiple degree of freedom test and P-value.
Frank
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y ideal result.
That would be log(odds) = 0 or OR=1. I wonder how many other errors I
committed?
Best to convert to the rms package - see
http://biostat.mc.vanderbilt.edu/Rrms for differences with Design.
If using ordinary polynomials, use e.g.
mod.poly3 <- lrm(trait ~ pol(PC1, 3), dat
g as the ctable=T was included), but without it
latex (s6)
##I do get a nicely formated table, but again the numbers are all wrong... Also
##latex(s6, long=TRUE, prmsd=TRUE, msdsize="smaller",middle.bold=TRUE)
##makes no difference from latex(s6) alone with regards
he rank of Y and reduces to the regular nonparametric tests as special
cases.
Frank
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ter system here. My
only other option for data anlaysis is Excel, we have no money for
S-plus or any other stats programme. Can anyone suggest anything or
send me a suitable email?
Many thanks,
Georgina
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do read the posting guide http://www.R-project.org/posting-guide.html
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has already been shown to be poor in
many cases. You might run the following in parallel: full model fits
and penalized least squares using penalties selected by AIC (using
special arguments to ols along with the pentrace function).
Frank
Regards,
Mark
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If you indeed need variable
selection see if backwards stepdown works for you. It is built-in to
rms bootstrap validation and calibration functions.
Frank
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se lrm(Y ~ pol(x, 2))
Frank
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--
Joris Meys
Statistical Consultant
Ghent University
Faculty of Bioscience Engineering
Department of Applied mathematics, biometrics and process control
Coupure Links 653
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g held by the moderator.
So I assumed that the question was never posted and I reposted with
different subject lines just to make sure that it gets posted.
I sincerely apologise for the inconvenience caused.
Regards,
Vishwanath
On Sat, May 29, 2010 at 4:10 AM, Frank E Harrell Jr
wrote:
Your note
On 05/28/2010 05:31 PM, Dylan Beaudette wrote:
On Friday 28 May 2010, Frank E Harrell Jr wrote:
On 05/28/2010 03:49 PM, Dylan Beaudette wrote:
Hi,
I have fit a model using the rms package with the Gls() function.
Is there a way to get the model estimates, std errors, and p-values (i.e.
what
work with ICD9 codes.
Is anyone aware of any R method that deals with ICD9 codes
verification and manipulation.
Thanks
Vishwanath
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simple way to get a table of estimated coeficients without
hand-making a table in a text editor for inclusion within a LATEX document.
Thanks!
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Department of Biostatistics Va
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and provide commented, minimal, self-contained, reproducible code.
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n.enter' not found"
Actually, using 'survest(f, time=3)' has the same result.
Has anybody encountered this kind of error? Is there a workaround?
Best regards,
Please provide a tiny self-contained reproducible example, e.g., using
simulated data.
Frank
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ble code.
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cts (which it almost
never is).
Frank
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variable to a constant
in the newdata argument to predict, and not using that variable to
predict the linear predictor. Then you can make a nomogram from the ols
model.
Frank
- Message d'origine
De : Frank E Harrell Jr
À : Marc Carpentier
Cc : r-help-request Mailing List
with the source package, the see what is needed in lrm to use it.
Frank
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previous mail)
I didn't see any example of this "adjustement" of nomogram to 'male' or
'female'...
I hope I gave a clearer explanation and I'm not wrong about this unmentioned
case.
Marc
- Message d'origine
De : Frank E Harrell Jr
À : Marc
continuous predictors have two axes each, with male and female in close
proximity. Or maybe I'm just missing your point.
Frank
- Message d'origine
De : Frank E Harrell Jr
À : Marc Carpentier; r-help-request Mailing
List
Envoyé le : Mer 19 mai 2010, 22h 28min 51s
Objet :
er one
But nomogram() still wants me to define interact=list(...) Thanks for
any advice you might have (with adj.to or any alternative...)
Marc Carpentier
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Department of Biostatistics Vanderbi
On 05/19/2010 01:39 PM, Ben Bolker wrote:
Frank E Harrell Jr Vanderbilt.Edu> writes:
Please read the large number of notes in the e-mail archive about the
invalidity of such modeling procedures.
Frank
I'm curious: do you have an objection to multi-model averaging
a la
month+coslunar+sinlunar+plankton,
data=mydata))
m234567<-glm.convert(glm.nb(mantas~year+cosmonth+sinmonth+coslunar+sinlunar+plankton,
data=mydata))
#Seven terms - 1 model
m1234567<-glm.convert(glm.nb(mantas~site*year+cosmonth+sinmonth+coslunar+sinlunar+plankton,
data=myda
sform-both-sides nonparametric regression approaches.
Frank
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93 13071
The spss.get function in the Hmisc package handles SPSS dates.
Frank
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practice in
spectral analysis and ANPOW.
...
Bert is correct. Binning is seldom needed and usually distorts. It is the
statistical equivalent of a former governor from Alaska.
Frank
...
Sincerely,
KeithC.
My experience in time series is limited so I'll defer to others.
Frank
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lines.
Derivatives and antiderivatives are trivial to write down. The Hmisc
package has rcspline.eval and rcspline.restate functions to help, the
latter having an option to express the antiderivative in text form.
Frank
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id not approach
0.05 even for sample sizes over 100.'';conservativeness of ``exact''
methods;see \emph{Stat in Med} \textbf{28}:173-179, 2009 for a criticism
which was unanswered}
}
- Original Message
From: Frank E Harrell Jr
To: r-help@r-project.org
Sent: T
from that continuous variable,
then ?cut can help you.
george5000 wrote:
Hello everyone,
I have a data set, and I need to bin my data using a bin width of say
g(n).
Would anyone be willing to tell me how to do this in R?
Thanks
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his case, Fisher's exact test has a good chance of being
less accurate than an approximate Pearson chi-square test.
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Department of Biostatistics Vanderbilt University
__
ile for your table you can continue to
use your original method,
e.g.,
<<>>=
tmp<- latex(x,
file="x.tex")
@
\include{x.tex}
(not sure what your objection to
this was in the first place).
-Ista
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Depart
what else? I only rule out writing (again) to
the maintainers of the package.
Adelchi Azzalini
--
Adelchi Azzalini
Dipart.Scienze Statistiche, Università di Padova, Italia
tel. +39 049 8274147, http://azzalini.stat.unipd.it/
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or 50-fold repeats of 10-fold cross-validation.
Among other places these are implemented in my rms package.
Frank
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___
suggestion to improve model
performance? and is the picture bad?
5. the picture and data below.
thank you!
http://n4.nabble.com/file/n2164417/scatter.jpg scatter.jpg
http://n4.nabble.com/file/n2164417/pkc-svm.txt pkc-svm.txt
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neering
Department of Applied mathematics, biometrics and process control
Coupure Links 653
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tel : +32 9 264 59 87
joris.m...@ugent.be
---
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ad-to-head time-efficiency test
many years ago of WYSIWYG word processing and markup languages by
secretaries. The markup language approach won easily. This assumes
that people don't mind learning things that take more than a day to learn.
Frank
--- On Thu, 5/6/10, Frank E Harrell Jr
any suggestions.
John
As I recall, the survival probability used in Freedman is not at some
arbitrary time of your choosing, but rather at the average length of
follow-up time anticipated in the study.
Kevin
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On 05/06/2010 07:28 PM, (Ted Harding) wrote:
On 06-May-10 23:44:50, Frank E Harrell Jr wrote:
Ted I can't resist offering my $.02, which is that I'm puzzled why
LaTeX, being free, flexible, and powerful, is used only by millions of
people and not tens of millions.
Frank
I think, F
Ted I can't resist offering my $.02, which is that I'm puzzled why
LaTeX, being free, flexible, and powerful, is used only by millions of
people and not tens of millions.
Frank
On 05/06/2010 03:07 PM, (Ted Harding) wrote:
Replying to Chris's latest message for the sake of preserving the
thre
ld and Adolescent Psychiatry
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e Londrina
Fone: 3371-4346
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an/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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help would be greatly appreciated, thanks,
Kim
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ich is really quite simple in applications such as Stata. Thanks very
much for the assistance:
Joseph Hilbe
hi...@asu.edu or jhi...@aol.com
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___
if these messages reflect a specific problem in my
dataset ? And if the number mentioned might give me a hint on which
column to look at (and maybe transform or ignore for the imputation) ?
Thanks for any advice you might have.
Marc
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in the core
is a bit incongruent with having even provided tabs for matrices and tables?
I'll pick up more in response to Max Kuhn's message.
Very best,
Chris
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Departmen
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See http://biostat.mc.vanderbilt.edu/SweaveConvert
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PLEASE do read the posting guide
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01-04_1 0 0.5260032 -2.977887 -0.02393871
By default (which is what you have implicitly chosen) you are
requesting "lp" = linear predictors rather than "risk".
Thomas Lumley Assoc. Professor, Biostatistics
tlum...@u.washington.eduUniversi
he
multiple models and to get bootstrap confidence intervals for the ranks.
I provided some code for this a couple of weeks ago.
Frank
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Frank E Harrell Jr Professor and ChairmanSchool of Medicine
Department of Biostat
x27;t it odd that the open-source R community has developed functions
for reading in proprietary SAS and SPSS format files, but (AFAIK) the
commercial sector doesn't seem to support reading data from
open-sourced and open-specced R .Rdata files?
Barry
Hi Barry,
Stat Transfer can read and write
formula functions, or use tapply using a
vector of possible subscripts (1:n) as the first argument; then you can
use the subscripts selected to address multiple variables.
Frank
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Frank E Harrell Jr Professor and ChairmanSchool of Medicine
Department of B
r providing the right answer.
Frank
On Thu, Apr 15, 2010 at 8:26 AM, Frank E Harrell Jr
mailto:f.harr...@vanderbilt.edu>> wrote:
Michael Dykes wrote:
I have a project due in my Linear Regression class re:
regression on a data
set & my professor gave us
th low
signal to noise ratios.
Frank
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ible but will be noisy.
You did not point to a function or package that claims to be able to
compute a Brier score with censored data.
Frank
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Department of Biostatistics Vanderbilt Un
pline.
Thanks a lot!
Lee
In usual practice the natural cubic spline does not use penalization.
Frank
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Department of Biostatistics Vanderbilt University
__
t;- coef(lsfit(predict(lm2, d[101:200, ]), d$y[101:200]))[2]
}
mean(slope1)
mean(slope2)
I get
> [1] 0.8873878
> [1] 0.9603158
Frank
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PLEASE do read the posting
C-index statistic to measure the predictive power, is it a
time-dependent value (i.e. do I need to calculate it for each time period?)
or we can calculate it as a single value for the whole model ignoring the
time?
Thank you so much.
Bessy
install.packages('Hmisc')
?rcorr.cens
d these methods.
Cheers,
Claire
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bg="transparent", width=700, height=500)
example(forest)
dev.off()
Also I have seen 5,000 page listings in SAS.
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ostatistics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Frank E Harrell Jr
Sent: Thursday, April 01, 2010 5:02 AM
To: vibha patel
Cc: r-help@r-project.org
Subject: Re: [R] fitness of regression tree: how to measure???
v
data and
that the form of the tree will not replicate in future datasets.
Frank
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Department of Biostatistics Vanderbilt University
__
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th(rownames(x))) as.factor(rownames(x)) else
as.factor(1:nrow(x))
cand <- reorder.factor(cand, x[,1])
Dotplot(cand ~ Cbind(x), pch=16, xlab='Rank', ylab='Candidate')
}
require(rms)
n <- 100
age <- rnorm(n, 50, 10)
sex <- sample(c('female',
-boun...@r-project.org] On
Behalf Of Frank E Harrell Jr
Sent: Tuesday, March 30, 2010 3:57 PM
To: Michal Figurski
Cc: r-help@r-project.org
Subject: Re: [R] Problem comparing hazard ratios
Michal Figurski wrote:
Dear R-Helpers,
I am a novice in survival analysis. I have the following code:
for (i in 3
likelihood ratio chi-square
statistics of the competing biomarkers.
Frank
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h(Surv(rtime, event) ~ rcs(covariate,4) + sex + ..., x=TRUE,
y=TRUE) # restricted cubic spline with 4 knots
plot(Predict(f, covariate, sex, time=10)) # separate curves for male
and female; omit sex to make one curve; add age=50 to predict for a 50
year old
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provide commented, minimal, self-contained, reproducible code.
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Gabor Grothendieck wrote:
On Thu, Mar 25, 2010 at 10:43 PM, Frank E Harrell Jr
wrote:
(Ted Harding) wrote:
http://www.nomogram.org
They call this sort of interface "nomogram" too, and you can have
a go at the one they offer for bladder cancer. This is not a
graphical nomogram in
lues. So I can't suggest general-purpose nomogram
generating software (and I doubt it would work well in many cases).
Ted.
E-Mail: (Ted Harding)
Fax-to-email: +44 (0)870 094 0861
Date: 25-Mar-10
--
Fran
e type of regression
modeling used to produce a reliable model that is then displayed in a
nomogram. The nomogram is the easy part; it is just a graphical display
of a model. It is not the model itself.
Frank
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...@manchester.ac.uk
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mx1, mx1), c(my1, my1, my2, my2, my1), col=2)
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a Spearman correlation coefficient. Anyone wanting to
work on the code should get the master code from our subversion repository.
Frank
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rfect gift? Give the gift of Flickr!
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questions.
B) Calibration plots are very easy for either logistic regression or Cox
models when using the calibrate function in either Harrell's rms or
Design packages. (Not sure about how well they play with survfit
objects, but you ought to be able to apply the same methods.)
--
Frank E Ha
ut as I said above I'm not sure whether it would be very useful.
Z
Excellent posts. I'll just add that the Huber-White sandwhich estimator
is obtain in the rms and Design packages by using the robcov function on
a fit object. You can also use the bootstrap with bootcov.
Frank
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