Well, your second post is rather confusing too, as is your not reproducible
code.
If I understand correctly, you just want to change names of files in a
directory according to some rules, which you did not clerly specify.
First I am not sure if R is the best tool for it. Nevertheless, you do no
Dear Bert,
thank you very much for your suggestion. You are right, ill-conditioning
was sometimes a problem for 3 components, but not in the two-component
case. The modes are well separated, and the sample size is high.
My main problem is (1) the shape of the distributions and (2) the
divers
Elegant I don't know, but I think the appended does the trick.
-- Mike
> foo <- c(" 1 X[0,SMITH] * 0 0 1 ",
+ " 2 X[0,JOHNSON] * 0 0 1 ",
+ " 3 X[0,WILLIAMS] * 1 0 1 ",
Actually, I figured out that you can, but the syntax is different.
You don't declare using \usedocument{beamer} \usetheme{PaloAlto}, instead,
title and output are the correct syntax.
Is there a full conversion list from Latex Beamer to Markdown Beamer?
Thanks!
On Mon, Jan 23, 2017 at 7:20 PM, C
Hi R list,
Is it possible to use R markdown with beamer palo alto theme? Are they
compatible?
I copy pasted my LaTex code over to R, I get the following error message:
! LaTeX Error: Can be used only in preamble.
See the LaTeX manual or LaTeX Companion for explanation.
Type H for immediate
Fitting multicomponent mixtures distributions -- and 3 is already a
lot of components -- is inherently ill-conditioned. You may need to
reassess your strategy. You might wish to post on stackexchange
instead to discuss such statistical issues.
Cheers,
Bert
Bert Gunter
"The trouble with having an
Dear friends,
I am trying to separate bi- (and sometimes tri-) modal univariate
mixtures of biological data, where the first component is left bounded
(e.g. exponential or gamma) and the other(s) approximately Gaussian.
After checking several packages, I'm not really clear what to do. Here
i
Sorry. You may get private replies, but this *is* way OT on this list.
Try stats.stackexchange.com instead for statistical queries. Or,
better yet, find local consulting help. Non-random dropouts are a
difficult issue.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people
This should have been sent to the R-help mailing list, not to me
personally. I am not an expert on this sort of time series modelling
and cannot thereby provide any useful advice. My reply to you was of a
"generic" nature --- when making an enquiry, provide a reproducible
example!!!
I am c
Hi Abhinaba,
I'm sure that someone will post a terrifyingly elegant regular
expression that does this, but:
ardat<-
c([1] " 1 X[0,SMITH] * 0 0 1 ",
...
numpoststar<-function(x) {
xsplit<-unlist(strsplit(x,""))
starpos<-which(xsplit=="*")
# watch out
What is the result of running:
getOption("device")
?
It should be something like: "RStudioGD". It sounds like this has
been changed to something else, if that is the case it is a matter of
either changing it back, or figuring out where the change is being
made and fixing that.
On Mon, Jan 23,
Dear All.
Apologies for posting a question regarding survival analysis, and not R, to the
R-help list. In the past I received the best advices from the R community.
The random censorship model (the censoring times independent of the failure
times and vice versa) is one of the fundamental assu
Only your pdf attachment made it through. You would need to follow the Posting
Guide regarding file types to achieve successful transmission.
I will say that open-ended debugging of your code does not fit the Posting
Guide recommendations either... this is an R language mailing list, not a
res
This sounds like an RStudio issue to me (just a not-so-informed guess,
though). Did you reinstall that, too? Did you look/post on RStudio's
site?
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley B
Dear R users,
I am happy to announce that the package caesar is now on CRAN (
https://cran.r-project.org/web/packages/caesar/index.html).
The caesar package lets you encrypt and decrypt strings using the common
Caesar cipher or a more secure pseudorandom number generator method.
If you would lik
You need to be clear in your own mind about the distinction between RStudio and
R before you can communicate clearly about it. Specifically, we don't know how
to debug problems with RStudio here, and what you describe sounds completely
normal for the R Gui program that ships with R.
It sounds
Hello,
That's a question for R Studio, ask here: https://support.rstudio.com
Hope this helps,
Rui Barradas
Em 23-01-2017 18:19, Jackson Rodrigues escreveu:
Hi,
after updating R and RStudio I am no longer able to see my plots in the
plot pane. Instead a new window opens called: R Graphics: D
Hi,
after updating R and RStudio I am no longer able to see my plots in the
plot pane. Instead a new window opens called: R Graphics: Device 2 (Active).
I tried to use dev.off(), reinstalling, update again and etc but it does
not help.
I've checked this discussion list but I could not find any s
I don't know if I will be able to help solve your problem, but failure to
follow the recommendations in the Posting Guide was probably getting you off in
the wrong foot when you posted on the other (more appropriate?) mailing list,
as it is here.
A) Code is garbled. Post using plain text forma
Hi all,
Thanks very much for your help! You are correct in thinking the list is the
same as before, actually, my question was more about how to do the next
steps, where I needed to match the filenames of the files in my directory
with old (i.e current) and new file name prefixes in my list. For ea
Dear T.Riedle,
it is a 'combined' test, see ?causality for a formal description of the test
statistic.
If you would like results on an 'equation' by equation' approach, you could
employ anova() on restricted and unrestricted lm-objects.
Best wishes,
Bernhard
-Ursprüngliche Nachricht-
Look at the finegray command within the survival package; the competing risks vignette has
coverage of it. The command creates an expanded data set with case weights, such that
coxph() on the new data set = the Fine Gray model for the original data. Anything that
works with coxph is valid on t
Hi Listers,
I posted this message to the R-sig-ecology group last Friday but have not
had a response hence my post here.
I have been trying to run spatial analyses on a fish community dataset.
My fish dataset has 114 species(variables) x 45 sites
My spatial dataset has the Lat and Long values fo
Hi
In your case if you want to rename abot 600 items and your doble loop works it
is not worth to vectorize it. However if you want to repeat such task often and
you expect much bigger number of files vectorizing can speed things up and make
them cleaner.
Although I must admit that I do not un
Dear Luanna
It is not compulsory to avoid for loops but see below
On 23/01/2017 12:28, Luanna Dixson wrote:
I need to rename a bunch of files, by searching for string matches in a
list. Each list element containings a character with the old filename that
I want to match to, and the new file nam
Dear Luanna,
Assuming that oldnames and newnames are character (and not factor), the
just use stringsAsFactors = FALSE. That will save you from having to
convert the factors back to character.
data.frame(oldnames, newnames, stringsAsFactor = FALSE)
Best regards,
ir. Thierry Onkelinx
Instituut v
Dear David and John,
Thank you for your replies. Indeed I'm using ape and nlme packages. Here it is:
> fit<-gls(fcl~mass+activity+agility,correlation=corBrownian(phy=tree),data=df,method="ML",weights=varFixed(~vf))
> Anova(fit)
Analysis of Deviance Table (Type II tests)
Response: fcl
Df
I need to rename a bunch of files, by searching for string matches in a
list. Each list element containings a character with the old filename that
I want to match to, and the new file name that I want to rename by.
For instance, here filename '1001.xls' should match to list[[1]]$oldname
and I want
On 23.01.2017 13:29, Abhinaba Roy wrote:
Hi,
How do I extract the first number after '*' in a vector?
The vector is given below
dput(out[1:10])
c(" 1 X[0,SMITH] * 0 0 1 ",
" 2 X[0,JOHNSON] * 0 0 1 ",
"
Hi,
How do I extract the first number after '*' in a vector?
The vector is given below
> dput(out[1:10])
c(" 1 X[0,SMITH] * 0 0 1 ",
" 2 X[0,JOHNSON] * 0 0 1 ",
" 3 X[0,WILLIAMS]", "*
Thank you for your reply. The code follows the example in the vignette and I
changed it only a little as shown below.
library(vars)
data(Canada)
summary(Canada)
stat.desc(Canada,basic=FALSE)
plot(Canada, nc=2, xlab="")
# Testing for unit roots using ADF
adf1<-adf.test(Canada[,"prod"])
adf1
adf2<
Dear T.Riedle,
you cannot assign *all* variables as a cause at once. Incidentally, in your
example, you missed a 'data(Canada)'.
Having said this, you can loop over the variables names and extract the
statistic/p-values. These are contained as named list elements 'statistic' and
'p.value' in th
> on Sun, 22 Jan 2017 10:26:24 -0600 writes:
> Dear Dr Mächler, I am using runmed from R's stat
> package. I understand that you are the author of this package.
not of the package - but of function runmed().
I'm reply to R-help, so this answer maybe available to future
web searches
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