I keep getting the same error message when trying to install R Commander.
My operating system is Mac OS Yosemite 10.10
I have installed R 3.2, Rstudio, XQuartz (X11), and tcltk-8.x.x-x11.dmg.
But I keep getting the following error:Loading required package: splinesLoading
required package: RcmdrMis
In that case, it seems that *libcurl* is not available for R-3.2.0 as I get
a message for
*>* *install.packages("libcurl")*
package ‘libcurl’ is not available (for R version 3.2.0)
Or if on Terminal I run
*sudo apt-get install libcurl4-openssl-dev*
Package libcurl4-openssl-dev is not availab
Hi Ishaq,
Well, you could do something absolutely ridiculous like this:
edit_my_plot<-function(x,y,z,w,r) {
npoints<-length(r)
index<-1
while(length(index)) {
matplot(x=matrix(r,nrow=3,ncol=4),y=cbind(x,y,z,w),
xlab="Number of iteration",ylab="Bias",
type="b",pch=c(1,22,22,22),lwd=2,
Hi Shiv82,
This doesn't look like it comes from the SharpeR, iBATGCH, inference
packages and there are too many other packages using the term to
easily identify it. As Rolf pointed out, alternative hypotheses are
typically framed as:
"two-sided" - non-directional, only specifies that the compariso
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Duncan
> Murdoch
> Sent: Thursday, April 30, 2015 1:33 PM
> To: Anirudh Jayaraman
> Cc: r-help@r-project.org
> Subject: Re: [R] 'Installation of package had non-zero exit
> status' on R-3.2.0 (RStudio Ve
On 30/04/15 23:22, Shivi82 wrote:
Hi All,
This is my first post in the community.
I am currently working on finding some inferences from my sample data and
the code I have used is:
inference(y = nc$weight, x = nc$habit, est = "mean", type = "ht", null = 0,
method = "theoretical"). While research
After hours of looking for the reason why one data set plots correctly and
another one does not I am still not seeing the reason. The only differences
I see between the two data sets is the number of discrete variables (one has
6 years, the other 7 years) and one contains zeros. I wonder if the
On 30/04/2015 3:20 PM, Anirudh Jayaraman wrote:
> In that case, it seems that *libcurl* is not available for R-3.2.0 as I
> get a message for
>
> *>* *install.packages("libcurl")*
It's not an R package, it's a library that you'll need on your system.
>
> package ‘libcurl’ is not available (fo
Do not post in html. You need to change your email software so that it sends
messages in plain text only. Look below to see why.
Your plot is edited by modifying the code you gave us to change the graph. Save
the code in a script file, change it in any way you want and then run the code
again t
More useful to the r-help list would be a reproducible example of the data you
are using and a clear statement of what you are trying to accomplish. It is
likely that all of your requirements can be easily met, but you spent most of
your message talking about what you have tried without telling
Jeremy:
I suggest you have a look at the latest edition of Paul Murrell's
book, "R Graphics", as you seem to be unaware that ggplot2 (as well as
a 3rd graphics paradigm, the lattice package) and base graphics are
built on 2 different and incompatible graphics engines.
Obviously, you are entitled
On 30/04/2015 2:12 PM, Anirudh Jayaraman wrote:
I recently upgraded to *R-3.2.0* from *R-2.14.1* on *Ubuntu 12.04 LTS.*
I have been *trying to install some add-on packages* (that weren't
installed in the earlier version of R) to R-3.2.0. *but to no avail*,
getting repeated error messages. For ex
Hello guys,
thanks for your quick reply
I will try and specific my problem
I have over 300.000 observations for different petrol pumps in all of Denmark
fra 1. november 2014 - 31 january 2015
for example I have:
petrol pump number: "" / date: 1. november 2014 / time: 08:14:22 / price:
I recently upgraded to *R-3.2.0* from *R-2.14.1* on *Ubuntu 12.04 LTS.*
I have been *trying to install some add-on packages* (that weren't
installed in the earlier version of R) to R-3.2.0. *but to no avail*,
getting repeated error messages. For example, *I tried installing swirl*.
Here's my outpu
Hi, Thanks for the reply!
I did try this...
# res is a data frame
levels(res$mytypeid.f) <- c(levels(res$mytypeid.f),"mynewlevel")
logreg <- glm(yesno ~ mytypeid.f + amount, data=res, family="binomial")
exp(coef(logreg))
# this result shows that the new level is not included in the regression.
Dear All,
First of all, many thanks to all R contributors for a fantastic
program, and especially to Hadley Wickham for creating ggplot2. The
following is intended to be a warning that, if the apparently
superficial problems described are not sorted out, R could well find
itself being superceded.
load("id3.rda")
attach(id3)
#transformando q13 em binária
q131<-ifelse(q13==1,1,ifelse(q13==2,2,ifelse(q13==3,2,
ifelse(q13==4,2,ifelse(q13==5,2,NA)
id3<-cbind(id3,q131)
id3$q131 <- as.factor(id3$q131)
tp1 <- glm(q131 ~ q11 + q10+q12+edcat + q08+q06+ q14, family = binomial(link =
"logit"),
Hi All,
This is my first post in the community.
I am currently working on finding some inferences from my sample data and
the code I have used is:
inference(y = nc$weight, x = nc$habit, est = "mean", type = "ht", null = 0,
method = "theoretical"). While researching more on the code as I have just
hello dears
I have Search to compare the results between the three types of cluster
k-maen ,Em and Hierarchal clusters
How i figured the number of iterations , the time required to build each
Cluster ,accuracy and sum square error SSE for each cluster in the R
programming
[[alternative
Hello,Kindly assist me on how to make the plot from the following programm to
be editable
x<-c(0.84,1.03,0.96)y<-c(1.30,1.46,1.48)z<-c(1.32,1.47,1.5)w<-c(0.07,0.07,0.07)r<-c(500,1000,2000)
# Graph cars using a y axis that ranges from 0 to 12plot(r,x, type="o",
col="blue", ylim=c(0,1.5),lwd= 2,
Dear R users,
The "lfactors" package is now available from CRAN. It provides a class
"lfactor" that is similar to the class "factor" but can be referred to by level
or label.
This package is best explained with an example
flips <- lfactor(c(0,1,1,0,0,1), levels=0:1, labels=c("Tails", "Heads"))
Yes, I think unlist() is still better.
One caution (for all): make sure the columns are all of the same
type/class/mode or you may be in for nasty surprises.
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
"Data is not information. Information is not knowledge. And k
Thank you. your suggestions all worked.
Best Regards
On Thursday, 30 April 2015, 11:52, Bert Gunter
wrote:
... and if this is what is wanted, somewhat cleaner and more
generalizable for programming would be:
do.call(c, mydata[,1:3])
## where the column indices might have to be a
Hi,
Given that a data frame is a list:
unlist(mydata[, 1:3])
For example:
> all(unlist(iris[, 1:3]) == do.call(c, iris[, 1:3]))
[1] TRUE
Also, note that the returned result in both cases above retains names:
> unlist(iris[, 1:3])
Sepal.Length1 Sepal.Length2 Sepal.Length3 Sepal.Leng
... and if this is what is wanted, somewhat cleaner and more
generalizable for programming would be:
do.call(c, mydata[,1:3])
## where the column indices might have to be adjusted to get the
desired columns.
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
"Data is
Here are two correct uses of the "stack command", if by that you mean the
stack() function.
> stack( data.frame(a=1:3, b=4:6, c=7:9) )
values ind
1 1 a
2 2 a
3 3 a
4 4 b
5 5 b
6 6 b
7 7 c
8 8 c
9 9 c
> stack( list(a=1:3, b=4:6, c=7:
Kevin Thorpe pointed out to me that there is a dropbox link at the very bottom
of the post that I missed. :(
I just downloaded it, read it in and it looks fine.
John Kane
Kingston ON Canada
> -Original Message-
> From: petr.pi...@precheza.cz
> Sent: Thu, 30 Apr 2015 14:25:23 +
>
I must correct myself,
attach does not prevent from modifying the object but can be confusing see
?attach example
> x<-1:5
> y<-NA
> xx<-data.frame(x,y)
> attach(xx)
The following objects are masked _by_ .GlobalEnv:
x, y
> rm(x,y)
> x
[1] 1 2 3 4 5
> yy<-x>3
> xx<-cbind(xx,yy)
> xx
x y
Hi
I agree with John
Just small refinements in lines
> -Original Message-
> > -Original Message-
> > From: lutipilo...@yahoo.com.br
> > Sent: Thu, 30 Apr 2015 04:24:32 -0700
> > To: r-help@r-project.org, jrkrid...@inbox.com
> > Subject: RE: [R] help - hoslem.test
> >
> > load("id
> -Original Message-
> From: lutipilo...@yahoo.com.br
> Sent: Thu, 30 Apr 2015 04:24:32 -0700
> To: r-help@r-project.org, jrkrid...@inbox.com
> Subject: RE: [R] help - hoslem.test
>
> load("id3.rda")
And what is this?
We do not have access to your office or computer hard disc.
Please
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
John Kane
Kingston ON Canada
> -Original Message-
> From: lutipilo...@yahoo.com.br
> Sent: Wed, 29 Apr 2015 18:45:26 -0700
> To: r-help@r-project.org
> Subject: [R] help - hoslem.test
>
> Hello,
>
> I
Hi Livia,
You can convert the time of day fields using strptime like this:
strptime(sapply(strsplit("time: 08:14:22"," "),"[",2),"%H:%M:%S")
This will give you the times as seconds in the current day. If you
then wish to divide the day into morning, afternoon and night, you
could create three tim
Hey :)
W2MH = y[43]; #number of infected vaccinated males high risk
> infected with
> non-vaccine strain
>
> length(y0)
[1] 42
As a sidenote, would you mind sharing the flow diagram with me, so I can
show it to my students doing a practical with DeSolve, as example of a
contemporary m
33 matches
Mail list logo
