Here are two correct uses of the "stack command", if by that you mean the stack() function.
> stack( data.frame(a=1:3, b=4:6, c=7:9) ) values ind 1 1 a 2 2 a 3 3 a 4 4 b 5 5 b 6 6 b 7 7 c 8 8 c 9 9 c > stack( list(a=1:3, b=4:6, c=7:9) ) values ind 1 1 a 2 2 a 3 3 a 4 4 b 5 5 b 6 6 b 7 7 c 8 8 c 9 9 c I would say that the "values" column of the output fits your description of what you want to do. (though I used names a, b, c instead of y1, y2, y3). But without a reproducible example, one can't say for sure. -- Don MacQueen Lawrence Livermore National Laboratory 7000 East Ave., L-627 Livermore, CA 94550 925-423-1062 On 4/29/15, 6:56 PM, "Olufemi Bolarinwa" <dafemli...@yahoo.co.uk> wrote: >Hello,I am estimating a system of nonlinear equation where I need to >stack my vector of y. I have data of about 6000units. I tried using the >rbind but instead of having a vector of 1 by 18000, it is giving me a 3 >by 6000 so that my matrix multiplication is non-conformable. The stack >command requires an identifier but in this case, I do not have a unique >identifier. >I would like to stack the the first 6000 units of y1 on the 2nd 6000 >units of y2 and 6000 units of y3. >Any help will be greatly appreciated. >ThanksOlufemi > > > > [[alternative HTML version deleted]] > >______________________________________________ >R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see >https://stat.ethz.ch/mailman/listinfo/r-help >PLEASE do read the posting guide >http://www.R-project.org/posting-guide.html >and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
