> On Nov 14, 2014, at 5:48 PM, Aravindhan, K wrote:
>
> Team,
> Can some one help me in computing the R-squared value in glm.
>
Which version of a pseudo-R^2? What’s the model?
> Thanks
> Aravindhan
>
> [[alternative HTML version deleted]]
This is a plain text mailing list
> R-help@
> On Nov 14, 2014, at 6:28 PM, Aravindhan, K wrote:
>
> Team,
> Has anyone looked at this question from me ? it will help me immensely if
> someone can provide an answer to this.
>
> Thanks
> Aravindhan
>
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun..
Team,
Has anyone looked at this question from me ? it will help me immensely if
someone can provide an answer to this.
Thanks
Aravindhan
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of K Aravindhan
Sent: Friday, August 08, 2014 7
Team,
Can some one help me in computing the R-squared value in glm.
Thanks
Aravindhan
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http:/
If your data uses a special marker such as "--" or "n/a" to indicate not
available then once you have identified those markers (using any method, though
Don's procedure below is what I use) then you can specify them with the
na.strings parameter to read.csv. (See the help for read.table for many
Thanks. I will try to further simplify the example.
On Sat, Nov 15, 2014 at 2:01 AM, Jeff Newmiller
wrote:
> While you appear to have been thorough in providing access to your code, I
> don't think I will install a bunch of your dev code to debug it for you.
> The Posting Guide does say your exa
While you appear to have been thorough in providing access to your code, I
don't think I will install a bunch of your dev code to debug it for you. The
Posting Guide does say your example should be minimal, and IMO this doesn't fit
that description. You should extract enough generic functions to
Hi Duncan,
thanks for answering and I'm very sorry: I was a bit too quick with letting
the example go.
This should be self-contained now:
require("devtools")
## Dependencies //
devtools::install_github("Rappster/conditionr")
devtools::install_github("Rappster/typr")
devtools::install_github("Ra
Dear list,
I just encountered a behavior that I've never seen before:
Is it possible, that certain argument names (lazy in my case) are
special/reserved and thus would lead to unexpected behavior when a calling
stack is involved that spreads across functions of three different
packages: optionr::
On Nov 14, 2014, at 12:15 PM, ivan wrote:
> Hi,
>
> I am trying to compute bootstrap confidence intervals for weighted means of
> paired differences with the boot package. Unfortunately, the weighted mean
> estimate lies out of the confidence bounds and hence I am obviously doing
> something wro
Sorry, I was too quick.
Try
A[ match(B, A$ID2) ,]
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 11/14/14, 1:45 PM, "Pedro Mardones" wrote:
>Dear R user;
>
>Consider the following toy example
>
>A <- data.frame(ID1 = c(1
On 15/11/14 10:45, Pedro Mardones wrote:
Dear R user;
Consider the following toy example
A <- data.frame(ID1 = c(1,2,3,1,2,3,1,2,3), ID2 =
c("a","b","c","d","e","f","g","h","i"), stringsAsFactors = FALSE)
B <- sample(a$ID2, 6, replace = TRUE)
Lets say B is = "a", "a", "a", "h", "b", "e"
I wan
Try
B <- c("a", "a", "a", "h", "b", "e")
subset(A, ID2 %in% B)
or
subset(A, ID2 %in% unique(B))
will do as well
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 11/14/14, 1:45 PM, "Pedro Mardones" wrote:
>Dear R user;
>
On 14/11/14 18:29, Popoola Daniel wrote:
Good Morning Sir/Ma, I am POPOOLA DANIEL a Forest Biometrician in
making from the University of Ibadan, Ibadan Nigeria. Please Sir/Ma I
am having issues on performing Non-linear mixed model on R (using
maximum likelihood approach). I am trying to input fou
Dear R user;
Consider the following toy example
A <- data.frame(ID1 = c(1,2,3,1,2,3,1,2,3), ID2 =
c("a","b","c","d","e","f","g","h","i"), stringsAsFactors = FALSE)
B <- sample(a$ID2, 6, replace = TRUE)
Lets say B is = "a", "a", "a", "h", "b", "e"
I want to extract from A the rows where ID2 == B
Here is one way using the XML package:
> x <- '
+
+
+
+ Open Analysis from Library
+ /Z- Archive - TO BE
+ purged/ConditionEmailTest
+
+
+ Send Email
+
+ chidambaramselvaku...@gmail.com
+ chidambaramselvaku...@gmail.com
+
+ Sales Re
Hi,
I am trying to compute bootstrap confidence intervals for weighted means of
paired differences with the boot package. Unfortunately, the weighted mean
estimate lies out of the confidence bounds and hence I am obviously doing
something wrong.
Appreciate any help. Thanks. Here is a reproducible
On 14/11/2014 12:34 PM, Chidambaram Selvakumar wrote:
Hi Team,
Can you please help me on the below?
1) Is it possible to achieve the below requirement through or not?
Open XMl; find and remove the all the string tag;add new string tag
based on the email count; save it in the same XML.
2
Petr is almost certainly correct. A further suggestion:
Continue to import using stringsAsFactors = FALSE
On one of the columns that should be numeric, use as.numeric(), find the
NA's in the result of that, and then look at those rows of the data. There
will be something there that is non-numeric
Mikhail,
The canonical recommendation is to wrap you code in a package -- either
source or even binary -- and to install it on the nodes.
Writing a package is the correct answer to many questions, and is
particularly true here.
Dirk
--
http://dirk.eddelbuettel.com | @eddelbuettel | e...@debia
Sorry for the trouble with double posting: I never received my original message
through the mailing list so I assumed that it did not go through.
I’ll try your suggestions, thank you.
Mikhail.
> On Nov 14, 2014, at 12:04, Jeff Newmiller wrote:
>
> Repeating yourself verbatim is poor form. At
Repeating yourself verbatim is poor form. At least quote your previous message
and indicate that this is a reprise.
While I doubt that my opinion is universal, I think that mixing C and R in the
same file is already living on the edge of good practice. You are assuming that
all of your nodes ha
Hi Team,
Can you please help me on the below?
1) Is it possible to achieve the below requirement through or not?
Open XMl; find and remove the all the string tag;add new string tag
based on the email count; save it in the same XML.
2) If yes can you please share the script
As I am new to
i think you can set: options(stringsAsFactor=FALSE) which will apply
globally or use read.csv(..., stringsAsFactor=FALSE) when imporing.
have a look at the documentation ?read.csv
good luck.
On 11/14/2014 09:44 AM, David Winsemius wrote:
>
> On Nov 13, 2014, at 4:28 PM, Ramesh Gautam wrote:
>
>
> -Original Message-
> From: David L Carlson [mailto:dcarl...@tamu.edu]
> Sent: Friday, November 14, 2014 10:25 AM
> To: John Posner; 'r-help@r-project.org'
> Subject: RE: Help with ddply/summarize
>
> I think this is what you want:
>
> > MyVar <- 1:10
> > MyVar
> [1] 1 2 3 4 5 6
Hi,
I use multicore package quite a lot. However, I want to find a way to check
on the progress of my job. For example:
ftest <- function(x){
if(x %% 100 == 0) print(x)
y <- 2x
return(y)
}
res <- mclapply(1:1000,ftest)
This would print the value of x in a for loop, but doesn't produce anythin
Thankyou very much Berend. It worked!!!
Have a great weekend!!
:)
Eliza
> Subject: Re: [R] replacing columns with same names
> From: b...@xs4all.nl
> Date: Fri, 14 Nov 2014 16:24:03 +0100
> CC: r-help@r-project.org
> To: eliza_bo...@hotmail.com
>
>
> On 14-11-2014, at 16:04, eliza botto wrote:
Hello —
I am using inline C functions within foreach %dopar% loop. On SMP (doParallel,
doMP) it works but on MPI-based clusters (doMPI) it does’t. The reason, I
think, is because the object code produced using the inline package,
essentially an .so file, does not get copied onto the worker node
I think this is what you want:
> MyVar <- 1:10
> MyVar
[1] 1 2 3 4 5 6 7 8 9 10
> mean(MyVar)
[1] 5.5
> txt <- "MyVar"
> mean(txt)
[1] NA
Warning message:
In mean.default(txt) : argument is not numeric or logical: returning NA
> mean(get(txt))
[1] 5.5
--
On 14-11-2014, at 16:04, eliza botto wrote:
> Dear useRs,
> I have two matrices
>> dput(EB)
> structure(1:15, .Dim = c(3L, 5L), .Dimnames = list(NULL, c("A", "B", "C",
> "D", "E")))
>
>> dput(EA)
> structure(31:36, .Dim = c(3L, 2L), .Dimnames = list(NULL, c("D", "E")))
> I have two question
>
Dear useRs,
I have two matrices
> dput(EB)
structure(1:15, .Dim = c(3L, 5L), .Dimnames = list(NULL, c("A", "B", "C", "D",
"E")))
> dput(EA)
structure(31:36, .Dim = c(3L, 2L), .Dimnames = list(NULL, c("D", "E")))
I have two question
1-Generally speaking, How can I replace the columns of matrix wit
Use the p_f numbers as an "index" of spot$pxlast. Suppose your data frame
is called mydata,
mydata$newvar <- spot$pxlast[mydata$p_f]
Jean
On Fri, Nov 14, 2014 at 8:48 AM, Francesca Pancotto <
francesca.panco...@unimore.it> wrote:
> Dear Contributors
> I seem not to get the general rule applyin
Dear Contributors
I seem not to get the general rule applying to the use of loops.
I need some help. I have a database in which i need to generate a variable
according to the following rule.
This is the database head
bank_name date px_last Q_Y p_made p_for p_m p_f
aba.1
Hello Duncan,
Jeff's tweaks to my code has worked. Now I am trying your way. Below are the
R script and console. The issue is that the object (list.of.files) has not
been created. Any thoughts?
Thanks,
### R script ##
#file.copy.dm.way.R
#identify th
Jeff,
Thank you so much for your help.
Below are the revised code (done with your hints) that has worked and the
console. I have just added - overwrite=TRUE) to file.copy().
Pradip
###
#file.copy.jn.way.R
#identify the folders
fromFolder <- "H:/R/cis
On 14/11/2014 8:21 AM, Jeff Newmiller wrote:
Sorry.. typo...
file.copy(file.path(fromFolder,list.of.files), toFolder)
Or construct the list of files containing full paths. See ?list.files.
Duncan Murdoch
---
Jeff Newmi
On 14/11/2014 7:18 AM, Alexander Shenkin wrote:
Hello all,
I have a set of points in 3D space that represent vertices of a
non-convex polyhedron. I would like to plot this polyhedron, and have
been trying to do so with rgl.triangles, but to no avail. I imagine I
don't understand what rgl.trian
Sorry.. typo...
file.copy(file.path(fromFolder,list.of.files), toFolder)
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#. ##.#. Live Go...
It seems rather complicated. AFAIK cor gives you correlation matrix, you can
check items in this matrix but I do not understand your rules.
¨
Cheers
Petr
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Cox Lwaka
> Sent: Frida
Your list.of.files variable just has filenames without the fromFolder path. Try
file.copy(file.path,fromFolder,list.of.files), toFolder)
---
Jeff NewmillerThe . . Go Live...
DCN:
Hello all,
I have a set of points in 3D space that represent vertices of a
non-convex polyhedron. I would like to plot this polyhedron, and have
been trying to do so with rgl.triangles, but to no avail. I imagine I
don't understand what rgl.triangles expects for arguments. I have
construct
Hello,
Here is something (file.copy) trivial but does not seem to work. I could not
figure out what I am doing wrong.
The R script below creates folders (fromFolder and toFolder) and finds the list
of files (list.of.files) to be copied to the toFolder, which I have verified
using the print
On 13/11/2014, 10:28 PM, Jeff Newmiller wrote:
>> Which text editor can actually display _^H correct?
>
> Not aware of any. It is from very old line printer behavior, which most
> (all?) printers can still support even though few computers are set up to
> utilize it.
The "less" command in Unix-
On 13/11/2014, 8:16 PM, Rolf Turner wrote:
> On 14/11/14 13:59, Duncan Murdoch wrote:
>> On 13/11/2014, 2:51 PM, Zheng Da wrote:
>>> Hello,
>>>
>>> I'm trying to generate plain text from the .Rd files. I run "R CMD
>>> Rd2txt xx.Rd -o xx.txt" to get the plain text file. When I open the
>>> text fil
With "geometric mean 1 CI /3.92", I assume you mean "(upper bound - lower
bound) / 3.92". Two things:
1) That will give you the SE of the mean, not the SD of the observations (which
is what you need as input).
2) Probably the CI for the geometric mean was calculated on the log-scale (as
Michae
Hello Marco,
> By any chance, are using that for prediction?
Yes, I am using it for prediction.
> To compute P(A = a | whatever you conditioned on), just sum the
> corresponding weights over the total weight mass. Since no language
> trickery is involved, this works reliably.
Thank you! It's ex
Thanks,Following your explanation i have through bi conductor but still unable
to figure out how to group. for the data, my data takes values 0,1,2 hence
simulating from a multinomial distribution such as (rmultinom(10, size = 3,
prob = c(0.1,0.2,0.8))) gives 10 variables from three individuals
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