Please read the Posting Guide
no html email
reproducible example please
In general, you can use expand.grid to generate all combinations of inputs,
compute results as a vector just as long as the expand.grid data frame has
rows, and identify which results meet your criteria by a logical test, an
How about (assuming the variables you defined):
ms <- matrix(unlist(vs), ncol=2,byrow=TRUE)
m[ms]
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#. ##.#. Live Go.
Hi,
I guess this should also work:
Matrix[,apply(Matrix,2,function(x) all(c(TRUE,x[-length(x)]!=x[-1])))]
# [,1] [,2] [,3]
#[1,] 1 5 5
#[2,] 2 4 1
#[3,] 3 3 4
#[4,] 4 2 3
#[5,] 5 1 2
A.K.
- Original Message -
From: Benjamin Ward (ENV)
HI,
You could use ?Reduce() also in the second case:
lapply(vs,function(v){Reduce(f,as.list(v))})
#[[1]]
#[1] 10
#[[2]]
#[1] 6
#[[3]]
#[1] 1
A.K.
- Original Message -
From: Carlos Pita
To: r-help@r-project.org
Cc:
Sent: Friday, January 25, 2013 7:46 PM
Subject: Re: [R] Pass vector
Hi,
May be this helps:
Matrix[,colSums(diff(Matrix))!=0]
# [,1] [,2] [,3]
#[1,] 1 5 5
#[2,] 2 4 1
#[3,] 3 3 4
#[4,] 4 2 3
#[5,] 5 1 2
A.K.
- Original Message -
From: Benjamin Ward (ENV)
To: "r-help@r-project.org"
Cc:
Sent: Friday, Jan
In view of our private communication on this matter (to the effect that
you had not been able to elicit a response from Vito Muggeo) I did a
little delving into the code of segmented.lm(). I ***think*** I have found
the problem. On line 243 (of the code as seen from loading the package)
the con
Benjamin Ward (ENV uea.ac.uk> writes:
> I'd like to write a piece of code which will remove columns from a matrix, if
the column contains only one
> value, say every value in the column is a "3":
>
> Matrix <- matrix(NA, nrow=5, ncol=4)
> Matrix[,1] <- c(1,2,3,4,5)
> Matrix[,2] <- c(3,3,3,3,3)
>
On Jan 25, 2013, at 7:00 AM, Andres, Jose wrote:
> Dear All,
> During the last few days I've been trying to get ggplot2 installed in my Mac
> but when installing dependencies I cannot access dichromat.
> Error in download.file(url, destfile, method, mode = "wb", ...) :
> cannot open URL
> 'htt
Hi,
Inline:
- Original Message -
From: emorway
To: r-help@r-project.org
Cc:
Sent: Friday, January 25, 2013 5:29 PM
Subject: Re: [R] resizing data
I played around with your example on the smaller dataset, and it seemed like
it was doing what I wanted. However, applying it to the larg
Hi all,
I'd like to write a piece of code which will remove columns from a matrix, if
the column contains only one value, say every value in the column is a "3":
Matrix <- matrix(NA, nrow=5, ncol=4)
Matrix[,1] <- c(1,2,3,4,5)
Matrix[,2] <- c(3,3,3,3,3)
Matrix[,3] <- c(5,4,3,2,1)
Matrix[,4] <- c(
HI,
It's not clear why you wanted to take the transpose and resize it afterwards.
It could be done in one step as David suggested.
Suppose, you wanted to get the result after you transposed the matrix:
x<-matrix(1:64,8)
x1<-t(x)
matrix(unlist(split(x1,row(x1))),ncol=4,byrow=T)
# [,1] [,2] [
On Jan 25, 2013, at 5:55 AM, Yongjie ZHANG wrote:
> On OS X 10.8.2, after I installed ggplot2, and picked mirror of Singapore. it
> could not find qplot function.
> Could anyone pls help me ? Thank you.
>
> Pls see:
>> install.packages("ggplot2")--- Please select a CRAN mirror for use in this
Hi,
Your question is bit confusing to me.
When you say that "which rrts are the same, and which are the new ones", to
me it looks like "0.35, 0.36" are new addition to Mnd at time points 6 and 9.
Extending Dennis' solution:
Just for understanding the problem:
vec1<-c(0.45,0.48,1.24,1.22,0.44,
which(x==1,arr.ind=TRUE)
row col
#[1,] 1 7
y<-t(matrix(x,nrow=546))
which(y==1,arr.ind=TRUE)
# row col
#[1,] 341 328
A.K.
- Original Message -
From: emorway
To: r-help@r-project.org
Cc:
Sent: Friday, January 25, 2013 5:29 PM
Subject: Re: [R] resizing data
I played a
Hi,
Try this:
Dates1<-c("2005-04-01 BST","2005-04-04 BST","2005-04-05 BST")
Dates2<-as.Date(gsub("\\s+\\w+$","",Dates1))
mat1<-matrix(1:9,nrow=3)
library(zoo)
z1<-zoo(mat1,Dates2)
z1
#
#2005-04-01 1 4 7
#2005-04-04 2 5 8
#2005-04-05 3 6 9
#if you use:
mat2<-matrix(1:9,nrow=3)
Dear Herry,
I would like to know if you found an answer elsewhere to your question.
I'm trying to get information around the nodes of a CA (daisy() followed
by agnes()) made on plant trait using the gower metric for taxonomic
purpuse. I'm not an expert in statistic but I understood that your way
m
Dear All,
During the last few days I've been trying to get ggplot2 installed in my Mac
but when installing dependencies I cannot access dichromat.
Error in download.file(url, destfile, method, mode = "wb", ...) :
cannot open URL
'http://cran.stat.sfu.ca/bin/macosx/leopard/contrib/2.15/dichromat
This idea is very simple and helpful. But one has to start with 0.05.
Thanks.
test.df$n<- seq(0.05,1, by=0.05)
2013/1/24 Rui Barradas
> Hello,
>
> try the following.
>
> test.df$Var1 <- seq(0,1, by=0.05)[-1]
> test.df
>
>
> Hope this helps,
>
> Rui Barradas
>
> Em 24-01-2013 17:39, Wim Kreinen
Or,
suu[unlist(lapply(suu,length)!=0)]
#[[1]]
#[1] 1 2
#[[2]]
# [,1] [,2]
#[1,] 1 3
#[2,] 2 4
A.K.
- Original Message -
From: Rui Barradas
To: Tammy Ma
Cc: "r-help@r-project.org"
Sent: Friday, January 25, 2013 8:15 AM
Subject: Re: [R] how to delete the null elements
On OS X 10.8.2, after I installed ggplot2, and picked mirror of Singapore. it
could not find qplot function.
Could anyone pls help me ? Thank you.
Pls see:
> install.packages("ggplot2")--- Please select a CRAN mirror for use in this
> session ---also installing the dependencies ¡®colorspace¡¯, ¡
> Jeff I didn't pretend to imply that the mapping should by always
s/by always/always be/
Sorry.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.h
Thanks Bert, do.call is exactly what I was looking for. What in lisp
is apply and in python f(*v).
> Your whole premise that the arguments of a function should be mappable to
> elements of a vector seems contrary to good R programming practice.
Jeff I didn't pretend to imply that the mapping sho
Your whole premise that the arguments of a function should be mappable to
elements of a vector seems contrary to good R programming practice. Consider
changing the called function's handling of arguments instead to accept the
vector of data directly if a vector makes sense, or to a list if the a
Well, of course the answer is yes (it always is!). I'm just not sure
what the question is.
However, I believe you want something like
do.call(the_function, parameter_list).
?do.call ## for details.
Note that if v is really a (named) vector, it can be converted to a
list via as.list().
Cheers,
Hi,
I want to know if it's possible to pass a vector v=c(x,y,...) to a
function f(x,y,...) so that each vector element corresponds to a
formal argument of the function. For python programmers: f(*v).
Specifically, what I'm trying to achieve is: given a list of
coordinates l=list(c(x1,y1,z1), c(x2
On 13-01-25 4:37 PM, Tim Howard wrote:
David,
Thank you again for the reply. I'll try to make readLines() and strplit() work. What bugs me
is that I think it would import fine if the folks who created the csv had used double quotes
"" rather than an escaped quote \" for those pesky internal qu
On Fri, 25 Jan 2013, Kay Cichini wrote:
Hello,
I'm searching for a test that applies to a dataset (N=36) with a
continuous zero-inflated dependent variable
In a regression setup, one can use a regression model with a response
censored at zero. survreg() in survival fits such models, tobit()
On Jan 25, 2013, at 2:29 PM, emorway wrote:
> I played around with your example on the smaller dataset, and it seemed like
> it was doing what I wanted. However, applying it to the larger problem, I
> didn't get a resized 2D dataset that preserved the order I was hoping for.
> Hopefully the fol
On 1/25/2013 2:29 PM, emorway wrote:
I played around with your example on the smaller dataset, and it seemed like
it was doing what I wanted. However, applying it to the larger problem, I
didn't get a resized 2D dataset that preserved the order I was hoping for.
Hopefully the following illustra
Hello,
I'm searching for a test that applies to a dataset (N=36) with a continuous
zero-inflated dependent variable and only one nominal grouping variable
with 2 levels (balanced).
In fact there are 4 response variables of this kind which I plan to test
seperately - the amount of zeroes ranges fr
I played around with your example on the smaller dataset, and it seemed like
it was doing what I wanted. However, applying it to the larger problem, I
didn't get a resized 2D dataset that preserved the order I was hoping for.
Hopefully the following illustrates the larger problem:
x<-matrix(0,nr
Dear All
I have the following data (somewhat simplyfied):
TINF <-1
a <-c(500,750,1000,1250,1500,1750,2000)
b <-c(8,12,18,24,36,48,60,72,96)
following function:
infcprodessa <-function (D, tin, tau, ts)
(D * (1 - exp(-0.048 * tin))/(tin * (0.048*79) * (1 - exp(-0.048 * tau *
exp(-0.0
Thanks for taking to time to help me out with this, I really appreciate it!
Quoting "S Ellison-2 [via R]" :
>
>
>> -Original Message-
>> I'd love to write a code that would allow me replace the example code:
>>
>> fit1F <- mle2(LL, fixed=list(xhalf=6))
>>
>> with something like:
>>
>> v
On Jan 25, 2013, at 1:12 PM, emorway wrote:
> Undoubtedly this question has been asked before, I just can't seem to find
> the combination of search terms to produce it. I'm trying to resize a
> dataset that is pulled into R using read.table. However, I think the same
> problem can be produced
On Jan 25, 2013, at 1:37 PM, Tim Howard wrote:
> David,
> Thank you again for the reply. I'll try to make readLines() and strplit()
> work. What bugs me is that I think it would import fine if the folks who
> created the csv had used double quotes "" rather than an escaped quote \" for
> thos
David,
Thank you again for the reply. I'll try to make readLines() and strplit() work.
What bugs me is that I think it would import fine if the folks who created the
csv had used double quotes "" rather than an escaped quote \" for those pesky
internal quotes. Since that's the case, I'd think
Not sure what is your exact requirement but you can compute marginals
and conditional probabilities using 'prob' package of Prof. Kerns.
On 25 January 2013 22:15, Rui Barradas wrote:
> Hello,
>
> You need to be much more specific. What do you know about the distributions
> of X and Y? And about t
On Jan 25, 2013, at 11:35 AM, Tim Howard wrote:
> Great point, your fix (quote="") works for the example I gave. Unfortunately,
> these text strings have commas in them as well(!). Throw a few commas in any
> of the text strings and it breaks again. Sorry about not including those in
> the e
Hello,
You need to be much more specific. What do you know about the
distributions of X and Y? And about their joint distribution?
If you suspect the joint distribution to be a bivariate normal try
package mvtnorm with
mu <- c(mean(x), mean(y))
sigma <- cov(cbind(x, y))
You can also try k
Undoubtedly this question has been asked before, I just can't seem to find
the combination of search terms to produce it. I'm trying to resize a
dataset that is pulled into R using read.table. However, I think the same
problem can be produced using matrix:
x<-matrix(1:64,8)
x
# [,1] [,2] [,3
Great point, your fix (quote="") works for the example I gave. Unfortunately,
these text strings have commas in them as well(!). Throw a few commas in any
of the text strings and it breaks again. Sorry about not including those in
the example.
So, I need to incorporate commas *and* quotes wi
On Jan 25, 2013, at 10:42 AM, Tim Howard wrote:
> All,
>
> I have some csv files I am trying to import. I am finding that quotes inside
> strings are escaped in a way R doesn't expect for csv files. The problem only
> seems to rear its ugly head when there are an uneven number of internal
> q
Hi,
To clarify further: these are results for degradation studies.
We search for degradations at 0 months, again at 3 months, again at 6 months,
...
Each analysis gives us a rrt, and a result.
To make final conclusions, we have to align the results manually (at least for
now).
rrt is depend
Drat, I forgot to tell you what system I am on:
> sessionInfo()
R version 2.15.1 (2012-06-22)
Platform: i386-pc-mingw32/i386 (32-bit)
locale:
[1] LC_COLLATE=English_United States.1252 LC_CTYPE=English_United States.1252
LC_MONETARY=English_United States.1252 LC_NUMERIC=C
All,
I have some csv files I am trying to import. I am finding that quotes inside
strings are escaped in a way R doesn't expect for csv files. The problem only
seems to rear its ugly head when there are an uneven number of internal quotes.
I'll try to recreate the problem:
# set up a matrix,
Dear R family,
I want to calculate the joint probability (distribution) of two random
continuous variables X and Y.
Could to please tell me how to do it?Thanks in advance..
elisa
[[alternative HTML version deleted]]
___
I am trying to use the cfa command in the lavaan package to run a CFA
however I am unsure over a couple of issues.
I have @25 dichotomous variables, 300 observations and an EFA on a
training dataset suggests a 3 factor model.
That is a lot of variables, and a rather small sample size (for binar
Thank you, Terry.
So in the spline model, how to do the interpretation for HR? For linear
term, the HR can be interpreted as "comparing a person with age 65, for
example, against mean age. But if there is no defined centering point in
spline, what's the compared value when we do the interpretation?
What a shame..
Don't know the details about ts, but I tried the code with data.frame, then
checked the result with OpenOffice offered percentiles for the same data.
It was identical, so now I am a bit confused...
2013/1/25 David Winsemius
>
> On Jan 23, 2013, at 5:45 AM, Simonas Kecorius wrote:
The image came through but no data. I'd suggest using ?dput to send the data.
John Kane
Kingston ON Canada
> -Original Message-
> From: janesh.devk...@gmail.com
> Sent: Thu, 24 Jan 2013 11:46:53 -0600
> To: r-help@r-project.org
> Subject: [R] Insert segment only on particular facets in
On Jan 23, 2013, at 5:45 AM, Simonas Kecorius wrote:
I found a code:
y.ts <- ts(data, frequency=12)
aggregate(y.ts, FUN=quantile, probs=0.10)
Seems it works fine even for a big data.frame.
Except for the fact that 'y.ts' is not a dataframe, so you are using a
function that has different a
> -Original Message-
> I'd love to write a code that would allow me replace the example code:
>
> fit1F <- mle2(LL, fixed=list(xhalf=6))
>
> with something like:
>
> var<-xhalf
> val<-6
>
> fit1F <- mle2(LL, fixed=list(var=val))
>
> or
>
> var<-c("xhalf","=")
> val<-6
>
> fit1F <- ml
The normalization is the same as is found when you have type="terms" from a gam model:
each term is centered so that mean(predicted) = 0. For a simple linear term beta*age this
implies that the predicted value will be 0 at the mean of age, for a polynomial or spline
this does not translate to a
Quite a long time ago, there was a thread about generalized eigenvalues,
which ended inconclusively.
http://tolstoy.newcastle.edu.au/R/help/05/06/6832.html
For students, a good proposal for the Google Summer of Code (gsoc-r)
would be a nice interface to things like the QZ algorithm and simil
Tammy Ma live.com> writes:
> > suu
> [[1]]
> NULL
> [[2]]
> NULL
> [[3]]
> item_id prod
> 1 2
> [[4]]
> item_id prod
> 1 2
> 2 4
>
> how to delete all "NULL" elements from suu to get only
>
> >suu
> [[3]]
> item_id prod
> 1 2
> [[4]]
> item_id prod
>
Hello,
Try the following.
suu <- list(NULL, NULL, 1:2, matrix(1:4, 2))
suu[!sapply(suu, is.null)]
Hope this helps,
Rui Barradas
Em 25-01-2013 12:31, Tammy Ma escreveu:
HI,
I have the list:
suu
[[1]]
NULL
[[2]]
NULL
[[3]]
item_id prod
1 2
[[4]]
item_id prod
1
On 25.01.2013 12:08, Berend Hasselman wrote:
On 25-01-2013, at 10:25, marcoguerzoni
wrote:
dear all,
thank you for reading.
I have a dataset of artists and where and when they had an
exhibition.
I'd like to create an affiliation network in the form of matrix,
telling me
which aritist h
HI,
I have the list:
> suu
[[1]]
NULL
[[2]]
NULL
[[3]]
item_id prod
1 2
[[4]]
item_id prod
1 2
2 4
how to delete all "NULL" elements from suu to get only
>suu
[[3]]
item_id prod
1 2
[[4]]
item_id prod
1 2
2 4
??
Kind
I still don't understand what you are looking for, but
https://gist.github.com/ is similar to pastebin, and it does have R
syntax highlighting.
Best,
Ista
On Thu, Jan 24, 2013 at 8:37 PM, C W wrote:
> I ran across this page for C, Java, etc. No R.
>
> http://pastebin.com/
> It looks similar and
Hello PIKAL Petr!
On Fri, 25 Jan 2013 10:09:54 + you wrote:
> Hi
>
> Attachment did not went through. Can you show us result of
> dput(head(data)) or output from str(data)?
>
> Anyway I wonder how time can became temperature. R is smart but I do
> not believe that during import it somehow ge
Thank you Petr!
--
View this message in context:
http://r.789695.n4.nabble.com/Help-with-adding-dates-string-as-rownames-to-matrix-tp4656611p4656617.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
ht
On 25-01-2013, at 10:25, marcoguerzoni wrote:
> dear all,
>
> thank you for reading.
>
> I have a dataset of artists and where and when they had an exhibition.
> I'd like to create an affiliation network in the form of matrix, telling me
> which aritist have been in the same at the same time
Hi
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of kevj1980
> Sent: Friday, January 25, 2013 11:22 AM
> To: r-help@r-project.org
> Subject: [R] Help with adding 'dates' string as rownames to matrix
>
> Hi, I need help with t
HI, All,
I have three dabases:
analysis_tool.accdb is linked into sellout.mdb and audit.accdb.
whenever I use this database, I need to firstly open "analysis_tool", then
press "External data"->"Linked Table Manager" to link the other two databases.
Now I want to load the data from those databa
Hi, I need help with two related issues:
1. I wish to drop repeating text "BST" from the below 'dates' string:
[1] "2005-04-01 BST" "2005-04-04 BST" "2005-04-05 BST" "2005-04-06 BST"
"2005-04-07 BST" "2005-04-08 BST" "2005-04-11 BST" "2005-04-12 BST"
"2005-04-13 BST" "2005-04-14 BST" "
2. I the
Hello, Marco,
I am not quite sure if understand correctly what you want, but maybe
DF <- data.frame( Artist, Begin, End, Istitution)
AtSameInst <- outer( DF$Istitution, DF$Istitution, "==")
Simultaneously <- with( DF, outer( Begin, End, "<=") |
outer( End, Begin, "<=
Hi
Attachment did not went through. Can you show us result of dput(head(data)) or
output from str(data)?
Anyway I wonder how time can became temperature. R is smart but I do not
believe that during import it somehow gets a local temperature at given time
and put it in your data.
Regards
Petr
Hi
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of David Studer
> Sent: Friday, January 25, 2013 9:28 AM
> To: r-help@r-project.org
> Subject: [R] Recoding variables (without recode() )
>
> Hi everybody!
>
> I have a rather
If names() is not what you need, then you have to explain your problem
better.
Ivan
--
Ivan CALANDRA
Université de Bourgogne
UMR CNRS/uB 6282 Biogéosciences
6 Boulevard Gabriel
21000 Dijon, FRANCE
+33(0)3.80.39.63.06
ivan.calan...@u-bourgogne.fr
http://biogeosciences.u-bourgogne.fr/calandra
Le
Hello,Thanks a lot for your help.
each index represents the different price band. I more prefer to use price band
info as "0-10" instead of 1...
I just can not find the way to do it.
Kind regards,
Tammy
> Date: Fri, 25 Jan 2013 10:46:45 +0100
> From: ivan.calan...@u-bourgogne.fr
> To: r-h
Hi,
Not sure this is what you need, but what about list.files()?
It can get you all the files from a given folder, and you could then
work this list with regular expressions for example.
HTH,
Ivan
--
Ivan CALANDRA
Université de Bourgogne
UMR CNRS/uB 6282 Biogéosciences
6 Boulevard Gabriel
210
Hi Tammy,
Are you just looking for names()?
Not sure, but it can be troublesome to have "-" in a name.
HTH,
Ivan
--
Ivan CALANDRA
Université de Bourgogne
UMR CNRS/uB 6282 Biogéosciences
6 Boulevard Gabriel
21000 Dijon, FRANCE
+33(0)3.80.39.63.06
ivan.calan...@u-bourgogne.fr
http://biogeoscience
names(X) <- c("0-10", "11-20")
MW
On Fri, Jan 25, 2013 at 9:39 AM, Tammy Ma wrote:
>
> HI,
>
>
> I have the array list:
>
> X<-vector("list", 2)
>
> X[[1]] : data frame 1
> X[[2]]: dataframe2
>
>
> now i want to change index 1 and 2 into: "0-10" , "11-20" ,.
>
> finally I want to have
> X[["0
HI,
I have the array list:
X<-vector("list", 2)
X[[1]] : data frame 1
X[[2]]: dataframe2
now i want to change index 1 and 2 into: "0-10" , "11-20" ,.
finally I want to have
X[["0-10"]]:dataframe1
X[["11-20"]]:dataframe2
how do I get them?
Thanks a lot.
Kind regards,
Tammy
dear all,
thank you for reading.
I have a dataset of artists and where and when they had an exhibition.
I'd like to create an affiliation network in the form of matrix, telling me
which aritist have been in the same at the same time.
I manage to do it, but given that I have 96000 observation th
Hi:
I use R 2.15.0 and RStudio 0.95.265. Platform: Windows 7 - 32b
When I predict some series with the x12 package (Version Number 0.3 Build
192) with the code...
forec <- x12(serie, x12path="D:/WinX12/X12a/x12a.exe", decimals=5,
automdlT, outlier="all")
... where "serie" is this "ts o
On Fri, Jan 25, 2013 at 6:11 AM, Ray Cheung wrote:
> Dear Michael,
>
> Thanks for your codes. However, lapply does not work in my case since I've
> some files missing in the data (say, the file data101.dat). Do you have any
> suggestions on this?? Thank you very much.
>
You could simply add a tes
Probably formatR/knitr is more robust but this one has an option for S
http://hilite.me/
-m
On 25 January 2013 02:37, C W wrote:
> I ran across this page for C, Java, etc. No R.
>
> http://pastebin.com/
> It looks similar and more than what I was looking for, just saying.
>
> Mike
>
>
> On Wed,
Hi everybody!
I have a rather simple question:
# play data
persId<-c(1,2,3,1,4,5,2)
varA<-c(11,12,13,12,14,15,10)
df<-as.data.frame(cbind(persId, varA))
Now I'd like to create a new columns (df$new)
according to the value of df$VarA. For example
df$new1 should be 1 if df$varA==2 or df$new2 shou
Dear Duncan, dear Rui,
thanks for your replies. You are correct regarding the additional
paranthesis. I probably copied the wrong code. I, however, get this
inlinedocs error with the correct version. After contacting the package
maintainer I think this is now added to inlinedocs list of bugs.
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