On Jan 25, 2013, at 2:29 PM, emorway wrote: > I played around with your example on the smaller dataset, and it seemed like > it was doing what I wanted. However, applying it to the larger problem, I > didn't get a resized 2D dataset that preserved the order I was hoping for. > Hopefully the following illustrates the larger problem: > > x<-matrix(0,nrow=29328,ncol=7) > > # Now set the 70,000th element to 1 to find out where it ends up? > # Iterating on columns first, then rows, the 70,000th element is > # at index [10000,7]
In an R matrix the "70,000"th element of a matrix with those dimensions would be in the 3rd column. > > x[10000,7]<-1 That's not the 70000th element. its the (29328*6+1)th element. Given your demonstrated misconceptions about R matrices and their column-major ordering I do not think I need to proceed further. Do some more self-study on R matrices. > y<-t(matrix(x,nrow=546)) > dim(y) > # [1] 376 546 > > # Does 1 appear at index [129,112] as I expect > # (128 complete rows x 546 cols = 69888 + 112 = 70,000) thus, row 129, col > 112 > y[129,112] > # [1] 0 > > # No, so where is it? > grep(1,y) > # [1] 123293 > > Where is that? > > > > -- > View this message in context: > http://r.789695.n4.nabble.com/resizing-data-tp4656653p4656662.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. David Winsemius Alameda, CA, USA ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
