Hello everyone,
I would like to perform a 2-way manova test, but I'm having some issues.
I implemented like this
Y<-cbind(Resp1,Resp2,Resp3,,Respn)
model<-manova(Y "tilda" FactorA*FactorB)
summary.aov(model)
1. I don't know at what level I have to do the Type I error correction. Is
it on
Hi all:
I am trying to use the BiodiversityR package in Rcommander since I need to
box-cox transform some data. However, even when trying with the example
files, I get this error just after selecting the box cox transformation in
the Menu, and Rcommander and Rstudio just shut down. What is it? Wh
responding to my own question, I see in ?svm man it states fitted() and
predict() can do the same thing:
# test with train data
pred <- predict(model, x)
# (same as:)
pred <- fitted(model)
On Nov 21, 2012, at 1:08 AM, signal wrote:
> Did you ever receive a response to this? I did not see one
On Nov 20, 2012, at 19:45 , Jeff Newmiller wrote:
> a) I would advocate marking "<<-" as "not recommended". Anyone who needs this
> reference probably should avoid this operator.
Could we say "not for beginners"? I mean, it has legitimate uses. If we say
"not recommended", people will remember
I am using 32 bit R - 2.15.2 version and working on package ltm. The
program does not give me any warning message when I run tpm command for a
dataset. If run tpm command for the same dataset in 64-bit R 2.15.1
version, I get the warning message shown below.
Can someone suggest why is no warning m
Hi all,
I'm wondering if there's a way that I can perform McNemar's test for a small
dataset easier.
I know this may be different from the usual way, but I'm hoping to throw it
out there for help.
For now, my orginnal dataset looks something like this...
Chemical shifts Pre_yes Pre_no Pos
Did you ever receive a response to this? I did not see one public.
I would think that if your dataset was of a large enough size, that 10-fold
validation would show an improvement over N:N.
Also, any ideas if there is any difference really in using fitted() vs.
predict() in your second step? I am
hi,
i have an ordered probit model where i estimate the probability of survey
participants to have selected a certain category of a censored latent
variable from a survey (the latent variable is the evolution of consumer
prices). the latent variable is of course continuous, the survey however
jus
Thanks for the feedback. By discrete, I meant a categorical trait (diel
activity). I've looked at the discrete models in geiger, but I had to ask
about Ornstein-Uhlenbeck because one of my advisors suggested it.
--
View this message in context:
http://r.789695.n4.nabble.com/Discrete-trait-Ornst
I don't know the difference between rank and order.For example:
> x=c(10,30,30,20,10,20)
> x[rank(x,ties.method="first")]
[1] 10 10 20 30 30 20
> x[order(x)]
[1] 10 10 20 20 30 30
the result is quite different,
x[rank(x,ties.method="first")]
[1] 10 10 20 30 30 20
It is not sorted,why?
--
View
https://stat.ethz.ch/pipermail/r-sig-geo/2012-November/016757.html
>> summary: How to overlay a geographical map on each panel in a lattice
>> (or Trellis), e.g., of levelplot's?
https://stat.ethz.ch/pipermail/r-help/2012-November/329716.html
> you need to launch the library 'latticeExtra'
That'
Hello,
I think you need to launch the library 'latticeExtra'. I forgot to
mention it. Sorry.
> library(latticeExtra)
Regards,
Pascal
Le 21/11/2012 14:29, Tom Roche a écrit :
https://stat.ethz.ch/pipermail/r-sig-geo/2012-November/016757.html
summary: How to overlay a geographical map on e
https://stat.ethz.ch/pipermail/r-sig-geo/2012-November/016757.html
>> summary: How to overlay a geographical map on each panel in a lattice
>> (or Trellis), e.g., of levelplot's?
https://stat.ethz.ch/pipermail/r-help/2012-November/329714.html
> Does [this] match what you are looking for?
Alas, n
Hello,
Your image is projected, not your panels.
Does it match what you are looking for?
wld <- map('world', xlim=c(west.lon.deg,east.lon.deg),
ylim=c(south.lat.deg,north.lat.deg),plot=FALSE)
wld <- data.frame(lon=wld$x, lat=wld$y)
state <- map('state', xlim=c(west.lon.deg,east.lon.deg),
y
r-help lattice adepts:
I have a question which is somewhat geospatial, so I posted to r-sig-geo
rather than here:
https://stat.ethz.ch/pipermail/r-sig-geo/2012-November/016757.html
> summary: How to overlay a geographical map on each panel in a lattice
> (or Trellis), e.g., of levelplot's? Note
May may also find this helpful, especially if you know LaTex:
http://yihui.name/en/2011/04/produce-authentic-math-formulas-in-r-graphics/
To: bgnumis ; "r-help@r-project.org"
Sent: Tuesday, November 20, 2012 6:22 PM
Subject: Re: [R] Greek letters on title
T
Mark-
Thank you for your help.
Pradip
Pradip K. Muhuri, PhD
Statistician
Substance Abuse & Mental Health Services Administration
The Center for Behavioral Health Statistics and Quality
Division of Population Surveys
1 Choke Cherry Road, Room 2-1071
Rockville, MD 20857
Tel: 240-276-1070
Fax: 240
Try this:
titleline=expression(paste("Time evolution with ", alpha, "=0.2"))
plot(x, main=titleline,col="orange")
--Mark J. Lamias
From: bgnumis
To: r-help@r-project.org
Sent: Tuesday, November 20, 2012 3:47 PM
Subject: [R] Greek letters on title
Hi all,
Hello Tania,
You may want to read MCMCpack's paper;
http://www.jstatsoft.org/v42/i09/paper
and one of the best book in the field:
http://www.amazon.com/Markov-Practice-Chapman-Interdisciplinary-Statistics/dp/0412055511
Also look on CRAN view on Bayesian Inference
Best,
-m
On Tue, Nov 20, 201
Hello,
Inline.
Em 20-11-2012 22:03, Brian Feeny escreveu:
I have a dataset that has many columns which are NA or constant, and so I
remove them like so:
same <- sapply(dataset, function(.col){
all(is.na(.col)) || all(.col[1L] == .col)
})
dataset <- dataset[!same]
This works GREAT (thanks
HI,
Try this:
plot(1,main= expression(paste("Time evolution with ", alpha,"= 0.2")))
A.K.
- Original Message -
From: bgnumis
To: r-help@r-project.org
Cc:
Sent: Tuesday, November 20, 2012 3:47 PM
Subject: [R] Greek letters on title
Hi all,
I want to plot a series "x" and I want to pu
On 20.11.2012 21:47, bgnumis wrote:
Hi all,
I want to plot a series "x" and I want to put on title "Time evolution with
alpha=0.2", e.g.,
plot(x, main="Time evotion with alpha=0.2",col="orange")
Is there any posibility to put the greek letter and avoid written the word?
Yes, see ?plotmat
I have a dataset that has many columns which are NA or constant, and so I
remove them like so:
same <- sapply(dataset, function(.col){
all(is.na(.col)) || all(.col[1L] == .col)
})
dataset <- dataset[!same]
This works GREAT (thanks to the r-users list archive I found this)
however, then
This is how I learned everything about knitr:
http://yihui.name/knitr/
Yihui is great and his site gives you pretty much all the information you need
to get you started.
From: "Muhuri, Pradip (SAMHSA/CBHSQ)"
To: 'R. Michael Weylandt'
Cc: "r-help@r-project
Hi,
I carried out an experiment, using a repeated measures design, in which I
broadcast 6 playbacks to 15 nests. I am trying to run a posthoc pairwise
comparison on a binomial GLMM with missing data points to determine which
playback treatments differ.
The response variable (Response) is binary
Hi all,
I want to plot a series "x" and I want to put on title "Time evolution with
alpha=0.2", e.g.,
plot(x, main="Time evotion with alpha=0.2",col="orange")
Is there any posibility to put the greek letter and avoid written the word?
Many thanks in advance.
[[alternative HTML version
Surely you jest!
-- Bert
On Tue, Nov 20, 2012 at 1:52 PM, Tania Patiño wrote:
> Hello all, could you tell wehere I can find information related to MCMC
> (Monte Carlo).
> And some examples about this topic.
>
> Thanks,
>
> Tania
>
> [[alternative HTML version deleted]]
>
> __
Hello all, could you tell wehere I can find information related to MCMC
(Monte Carlo).
And some examples about this topic.
Thanks,
Tania
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/lis
On 12-11-20 4:35 PM, Prof Brian Ripley wrote:
On 20/11/2012 19:46, Duncan Murdoch wrote:
On 20/11/2012 2:30 PM, Brian Feeny wrote:
I am new to R, so I am sure I am making a simple mistake. I am
including complete information in hopes
someone can help me.
Basically my data in R looks good, I w
On 20/11/2012 19:46, Duncan Murdoch wrote:
On 20/11/2012 2:30 PM, Brian Feeny wrote:
I am new to R, so I am sure I am making a simple mistake. I am
including complete information in hopes
someone can help me.
Basically my data in R looks good, I write it to a file, and every
value is off by 1.
I'm using /parApply/() function in "snow" package for parallel computing
(boostrapping repeating calculation), as the follows:
MyBoostrapping <- function( i ){
.
}
cl <- makeCluster( ncluster, type = "SOCK")
i.circle <- as.matrix( 1:128, , 1)
parApply( cl, i.circle, 1, FUN = MyBoostrappi
What about something like this:
#Create dummy data
mydf=data.frame(matrix(rnorm(1000), ncol=100))
#Obtain summary stats
my.vars=apply(mydf, MARGIN=2, FUN=var)
my.std=sqrt(my.vars)
#Plot summary stats
plot(my.vars, col="red")
points(my.std, col="blue")
From
HI,
May be this:
RiskTest<-ifelse(EvHint==1 & MinTex==1,1,0)
RiskTest
# [1] 0 0 0 1 0 1 1 0 0 0 0 1 0 0 0 0 0 0 0 0
A.K.
- Original Message -
From: Virgile Capo-Chichi
To: r-help@r-project.org
Cc:
Sent: Tuesday, November 20, 2012 2:08 PM
Subject: [R] Using if
Dear R users,
As a new
Hello,
You are seeing the levels of a factor but saving its values. Internally,
factors are coded as consecutive integers starting at 1, and that's what
is saved to file using write.table. To have the levels "0", "1", etc and
not the corresponding values 1, 2, etc, try
levels(prediction)[pre
Tena koe
If the vectors are long and time is an issue, it might be better to avoid the
use of ifelse().
Try:
set.seed(0)
EvHint <- rbinom(10^7, 1, 0.5)
MinTex <- rbinom(10^7, 1, 0.5)
system.time(RiskTest0 <- ifelse(EvHint==1 & MinTex==1, 1, 0))
system.time({
RiskTest1 <- rep(0, length(EvHint))
R
A followup to my own post, I believe I figured this out, but if I should be
doing something different please correct:
> prediction.out <- levels(prediction)[prediction]
> write(prediction.out, file="prediction.csv")
This gives me my correctly adjusted values
Brian
On Nov 20, 2012, at 2:30 PM,
On 20/11/2012 2:30 PM, Brian Feeny wrote:
I am new to R, so I am sure I am making a simple mistake. I am including
complete information in hopes
someone can help me.
Basically my data in R looks good, I write it to a file, and every value is off
by 1.
Here is my flow:
> str(prediction)
Fa
On Nov 20, 2012, at 10:24 AM, Tom Roche wrote:
>
> https://stat.ethz.ch/pipermail/r-help/2012-November/329509.html
>>> - without the line above commented out, strip values are (correctly)
>typo, should be "incorrectly" ^
>>> all 1.123
>
>>> + with the
Anyway, need to go home. If you really only want to plot the values of all
variables, and its for some reason not important what value belongs to what
exact variable:
plot(variances,ylim=range(variances,sdevs)) # black circles
points(sdevs,col=2,pch=3) #red crosses
On 20.11.2012, at 19:32, Elli
I am new to R, so I am sure I am making a simple mistake. I am including
complete information in hopes
someone can help me.
Basically my data in R looks good, I write it to a file, and every value is off
by 1.
Here is my flow:
> str(prediction)
Factor w/ 10 levels "0","1","2","3",..: 3 1 10
Replying to post on Nabble:
so, basically first you need these values for each variable, yes?
m<-data.frame(a=1:3,b=4:6,c=7:9)
variances<-sapply(m,var)
sdevs<-sapply(m,sd)
but i still don't know what you want to show. Just plot the values per
variable? That won't be properly visible in just one
Try this (convert the logical TRUE to the value 1):
> EvHint<-c(0, 0, 0, 1, 0, 1, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 0, 1, 0, 0)
> MinTex<-c(0, 0, 1, 1, 0, 1, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 1, 0)
>
> RiskTest <- (EvHint == 1 & MinTex == 1) + 0L
> rbind(EvHint, MinTex, RiskTest)
[,1] [,2]
> In SPSS, my syntax would look like
>
> Compute RiskTest=0.
> if (EvHint=1 & MinTex=1) RiskTest=1.
RiskTest <- EvHint == 1 & MinTex == 1
will create a logical vector, one with values TRUE and FALSE.
If you really want 1 and 0 then add RiskTest <- as.integer(RiskTest),
but using logicals instea
Hi,
Thanks for providing a reproducible example.
On Tue, Nov 20, 2012 at 2:08 PM, Virgile Capo-Chichi
wrote:
> Dear R users,
>
> As a new comer to R, I would like to create a new variable using if
> statements but don't know how to do it. Basically, I have two variables
> (EvHint and MinTex). I
?ifelse
Quite distinct from if () {} else {}.
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#. ##.#. Live Go...
Live: OO#.
Dear R users,
As a new comer to R, I would like to create a new variable using if
statements but don't know how to do it. Basically, I have two variables
(EvHint and MinTex). I want to create a third variable called RiskTest.
In SPSS, my syntax would look like
Compute RiskTest=0.
if (EvHint=1 &
Hi All.
I'm using parApply() function in "snow" package for parallel computing
(boostrapping repeating calculation), as the follows:
MyBoostrapping <- function( i ){
.
}
cl <- makeCluster( ncluster, type = "SOCK")
i.circle <- as.matrix( 1:128, , 1)
parApply( cl, i.circle, 1, FUN = MyBoo
I have a data set consisting of 364 variables and I need to graph the
standard deviation and variance of each variable as only the function sd ()
or var () is not enough. And I want to know how I can graph this?
--
View this message in context:
http://r.789695.n4.nabble.com/Deviation-standard-v
On Nov 20, 2012, at 3:15 AM, riodementa wrote:
> I want to represent a Raster map of class "asc", and in the same window a
> list of points with the funcion points(x,y)..
>
> I considered two options:
> 1. With image.plot(map) and then use points(x,y).
>It works, and the points are in the co
Some issues:
a) I would advocate marking "<<-" as "not recommended". Anyone who needs this
reference probably should avoid this operator.
b) The $ operator does an approximate match with the name. [["name"]] does an
exact match.
c) Matrices are not data frames. Their indexing by the "[" operat
On 20/11/2012 12:39 PM, Omphalodes Verna wrote:
Dear list!
I have question of 'correct function formation'. Which function (fun1 or fun2; see below) is written more correctly? Using ''structure'' as output or creating empty ''data.frame'' and then transform it as output? (fun1 and fun1 is just
On 20/11/2012 12:54 PM, Gang Chen wrote:
I wrote an R program that does heavy computations with hundreds of
lines of code. It's running fine both interactively and in batch mode
on a Mac OS X computer. The program also has no problem running on a
Linux system (Fedora 14) interactively. However, w
At least for me this is not enough information to go on Elli.
What exactly is the problem? Can you post example data?
On 20.11.2012, at 18:39, Elli wrote:
> How I can plot the standard deviation and variance separately or is there a
> graph where I can show the two?
>
>
>
> --
> View this mes
Thanks for the pointer!
Unfortunately it doesn't look like a memory issue: /var/log/messages
contains nothing about memory problems. And the Linux system has
enough RAM for this computation.
Gang
On Tue, Nov 20, 2012 at 1:03 PM, Milan Bouchet-Valat wrote:
> Le mardi 20 novembre 2012 à 12:54 -05
https://stat.ethz.ch/pipermail/r-help/2012-November/329509.html
>> - without the line above commented out, strip values are (correctly)
typo, should be "incorrectly" ^
>>all 1.123
>> + with the line above commented out, strip values are (correctly)
>>
For me this worked:
install.packages('rJava',,'http://www.rforge.net/')
--
View this message in context:
http://r.789695.n4.nabble.com/Can-t-install-rJava-tp3948460p4650191.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-pr
I made an update/reboot of Tom Short's classic and public domain "R
Reference Card". His is from late 2004 and I've found myself giving it to
new R users with additional notes about packages.
If anyone knows how to reach Tom, that would be great. I am titling this
reboot "Short R Reference", in
This question is at best about how R is configured on your computer, but far
more likely the problem lies in your operating system, which you have not
identified and details of which are off-topic here anyway.
If you use getwd() to identify which directory you are in, or pay attention to
which
Le mardi 20 novembre 2012 à 12:54 -0500, Gang Chen a écrit :
> I wrote an R program that does heavy computations with hundreds of
> lines of code. It's running fine both interactively and in batch mode
> on a Mac OS X computer. The program also has no problem running on a
> Linux system (Fedora 14)
Hello everybody,
i'm trying to run a lme but am having a problem.
My model have many response variables and when i run the anova, the number
of interactions (up to six) is great and the p-values of all variables not
appear.
I wanted to know if i could to control the number of interactions of the
How I can plot the standard deviation and variance separately or is there a
graph where I can show the two?
--
View this message in context:
http://r.789695.n4.nabble.com/Deviation-standard-variance-tp4650181.html
Sent from the R help mailing list archive at Nabble.com.
___
Hi,
i am trying to learn something about multilevel analysis using a great
"Discovering statistics using R". I constructed some sample data and then
tried to fit a model. Generally model fits well, however when trying to fit
the same model using z-score (standarizded) variables i got an error:
Er
I wrote an R program that does heavy computations with hundreds of
lines of code. It's running fine both interactively and in batch mode
on a Mac OS X computer. The program also has no problem running on a
Linux system (Fedora 14) interactively. However, when I try it on the
terminal in batch mode
Hello,
I believe it's a matter of personal taste. I find fun2 more readable,
others may not agree.
Rui Barradas
Em 20-11-2012 17:39, Omphalodes Verna escreveu:
Dear list!
I have question of 'correct function formation'. Which function (fun1 or fun2; see below) is written more correctly? Us
Dear list!
I have question of 'correct function formation'. Which function (fun1 or fun2;
see below) is written more correctly? Using ''structure'' as output or creating
empty ''data.frame'' and then transform it as output? (fun1 and fun1 is just
for illustration).
Thanks a lot, OV
code:
i
Dear All,
I was just installing 'linkcomm' and had the following message which I
have not seen before and don't really understand:
NOTE: To use linkcomm, you require read and write permissions in the
current directory (see: help("getwd"), help("setwd"))
Having looked at these help pages I'm none
As long as all your names of list elements are in the same format,
this should do it:
mylist[order(names(mylist))]
Thanks for the reproducible example,
Sarah
On Tue, Nov 20, 2012 at 11:40 AM, Simon Kiss wrote:
> Dear colleagues,
> Is there a way to order list items by date? I have a series of
o <- order(as.Date(names(mylist)))
myListInDateOrder <- mylist[o]
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf
> Of Simon Kiss
> Sent: Tuesday, November 20, 2012 8:41 AM
Dear colleagues,
Is there a way to order list items by date? I have a series of surveys in a
list where the name of each list item is the date the survey was taken but the
list items are out of order. Each data frame has a variable in it with the
survey date as well, if that helps.
Yours, Simon
Hi Rui, thank-you very much!
That worked perfectly.
Irucka
<-Original Message->
>From: Rui Barradas [ruipbarra...@sapo.pt]
>Sent: 11/20/2012 5:42:36 AM
>To: iruc...@mail2world.com
>Cc: r-help@r-project.org
>Subject: Re: [R] help on matrix column removal based on another matrix
results
On Mon, Nov 19, 2012, at 18:26, David Winsemius wrote:
> My guess is that you do not understand the meaning of a "random
> factor". I certainly did not when I first encountered it. All my
> training had been with ordinary regression and analysis of variance.
> These are methods for what in mi
On Mon, Nov 19, 2012, at 16:31, Bert Gunter wrote:
> I believe that you need to consult a local statistician, as there are
> likely way too many statistical issues here that you do not fully
> understand. Alternatively, try posting to a statistical list like
> stats.stackexchange.com, as I think mo
Suppose you have the following code:
## Start code##
data(Chem97, package="mlmRev")
densityplot(~gcsescore | factor(score), groups=gender, data=Chem97,
auto.key=TRUE, plot.points=FALSE, ref=TRUE,
panel=function(x,...){
panel.densityplot(x,.
Hi,
I am developing a Gui in R for a Statistical Purpose.
i am wondering to know whether there is any option in R for centering the
objects in a window when a window is maximized.
All the gaps, positions and sizes are to be scaled up properly on
maximizing, giving an same view as it gives under
Is this homework?
R has a no homework policy.
-- Bert
On Tue, Nov 20, 2012 at 12:33 AM, Tonja Krueger wrote:
>
>Hi all!
>I'm sure this is a stupid question but I can't find an answer. How can I
> fit
>the Gumbel distribution to my data using The Method of Moments in R?
>Thank yo
Dear Michael,
I really appreciated that you have sent me the link info - Jeromy Anglim's
Blog. I was exactly looking for this kind of resources about R Markdown and
knitr. All this would be of immense help.
Thank you so much.
Pradip
Pradip K. Muhuri, PhD
Statistician
Substance Abuse & Mental
Thanks, Michael.
Pradip
Pradip K. Muhuri, PhD
Statistician
Substance Abuse & Mental Health Services Administration
The Center for Behavioral Health Statistics and Quality
Division of Population Surveys
1 Choke Cherry Road, Room 2-1071
Rockville, MD 20857
Tel: 240-276-1070
Fax: 240-276-1260
e-ma
I want to represent a Raster map of class "asc", and in the same window a
list of points with the funcion points(x,y)..
I considered two options:
1. With image.plot(map) and then use points(x,y).
It works, and the points are in the correct place, but when I maximize
the plot the points are mov
Dear all,
I am trying to fit a double gaussian to some data using the mixdist package:
--- begin code ---
library(mixdist)
time <- seq(673,723)
counts <-
c(3,12,8,12,18,24,39,48,64,88,101,132,198,253,331,419,563,781,1134,1423,1842,2505,374,6099,9343,13009,
15097,13712,99
Hello everyone,
I have estimated system of three linear equations with one non-linear
restrictions with nlsystemfit. I was wondering how I can calculate the
R-squared (or some alternative coefficient of determination) for the
whole system. This is automatically given by linear systemfit but no
Thank you very much, this works!
--
View this message in context:
http://r.789695.n4.nabble.com/lattice-defining-grouping-variable-only-for-the-upper-lower-panel-with-splom-tp4650033p4650144.html
Sent from the R help mailing list archive at Nabble.com.
_
Hi all!
I'm sure this is a stupid question but I can't find an answer. How can I fit
the Gumbel distribution to my data using The Method of Moments in R?
Thank you for helping me,
Tonja
__
R-help@r-project.org mailing list
https://stat.eth
On Tue, Nov 20, 2012 at 2:07 AM, Muhuri, Pradip (SAMHSA/CBHSQ)
wrote:
>
> Hello,
>
> I would like to learn how to set up Github/repository and upload/update files
> and am looking for "Github for Dummies". Any help will be appreciated.
>
I believe Hadley has done some github integration work:
h
On Tue, Nov 20, 2012 at 1:57 AM, Muhuri, Pradip (SAMHSA/CBHSQ)
wrote:
> Hello,
>
> I am an Intro-level R and ggplot2 user and looking for resources to self
> teach dynamic report generation in R using knitr. Any advice would be highly
> appreciated.
http://jeromyanglim.blogspot.co.uk/2012/05/ge
There are multiple issues here. First of all, you should simplify your code to:
metacor(cor, n, title="title", complab="comparison", outclab="outcome")
The rest of your call to metacor() is just using the defaults, so no need to
repeat all of that in your call and apparently one of these argumen
Dear Peter,
There are several packages that try to address this type of problem (although
the remarks made
by Max are something that we should always keep in mind), and I also recommend
those with perform
some form of regularized, penalized or shrunken linear discriminant analysis
with a prelim
Hello,
Try removing the square parenthesis from the left hand side,
Vsim <- Vsim[, NSErr > 0.6]
Hope this helps,
Rui Barradas
Em 20-11-2012 04:07, Irucka Embry escreveu:
Hi Rui, how are you?
I want to thank you for your assistance again.
I'm sorry, but the code that you provided for me did
very good idea!
thanks a lot.
Vincent
2012/11/20 Yves Reecht
> Hi Vincent,
>
> This is probably because Rcmdr redefine the tclvalue command (check the
> message frame of the Rcmdr window).
> You can try:
>
> tcltk::tclvalue(tkget(levels.list2,"4"))
>
> HTH,
> Yves
>
>
> Le 20/11/2012 11:25
Hi Vincent,
This is probably because Rcmdr redefine the tclvalue command (check the
message frame of the Rcmdr window).
You can try:
tcltk::tclvalue(tkget(levels.list2,"4"))
HTH,
Yves
Le 20/11/2012 11:25, vincent guyader a écrit :
> I everyone,
>
> i have a little problem with tklistbox,t
I everyone,
i have a little problem with tklistbox,the " " character and Rcmdr.
Please look at this code
require(tcltk)
tt<-tktoplevel()
levels.list2 <-tklistbox(tt,selectmode="multiple",exportselection="FALSE",
height=4, yscrollcommand=function(...)tkset(levels.list2.scroll,...))
levels.list2.s
On Mon, Nov 19, 2012 at 9:39 PM, Christophe Genolini
wrote:
> Hi the list,
>
> I am a member of the organizing comity of the French Statistics Association
> (SFdS)'s conference. We
> are looking for sponsors. Some software (SAS, RITME, ...) are represented. Do
> you know if there is
> any possib
On 19.11.2012 23:34, Ben Bolker wrote:
genome.wustl.edu> writes:
I created a 3d scatter plot and am trying to change the color of outer box
lines with box3d.
Anybody can help me to figure out how to do this?
My example is:
library(scatterplot3d)
x=seq(1:6)
y=seq(7:12)
z=x*2
scatterplot
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