Did you look at the help page that Uwe directed you to? At least one
of the examples on that page demonstrates adding text to a barplot.
But before you do that you should read through the discussion here:
http://tolstoy.newcastle.edu.au/R/e2/help/07/08/22858.html on why you
might not want to add t
On 05/27/2012 04:30 AM, Manish Gupta wrote:
My Question is how to write height length on each bar.
Hi Manish,
If don't have stacked bars, it is fairly simple:
barpos<-barplot(height,...)
text(barpos,height,labels=height)
usually with a bit of fooling around with the cex argument. If you want
could be. how would you know?
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#.. Pl
is this is time series ?
x
1 2
2 2
3 2
4 2
5 2
6 2
7 2
8 2
9 2
10 2
11 2
12 2
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Thanks Ozgur. I will definitely try them out.
Cheers,
Kel
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Hi Sven,
The function is working perfectly fine for me. Could it be due to package
masking the function? Sometimes, these problems will get solved by restarting
R console. It happened to me a couple of times.
A.K.
- Original Message -
From: Sven D
To: r-help@r-project.org
Cc:
Se
Yes,sir index of above/below numbers is time (both dataset are same)
x
1 0.8890464
2 1.2272616
3 1.2272616
4 1.3578511
5 1.3578511
6 1.1070461
7 1.4424190
8 1.2277843
9 1.3578511
10 0.9708839
11 0.8221709
12 1.3578511
13 0.3588158
14 0.7742342
15 0.8221709
16 0
HI Luke,
It would be better to ask this question on R mixed models
(r-sig-mixed-mod...@r-project.org). Just for curiosity (as I am doing a
similar kind of light/dark response in insects), I am interested in the
response variable (y) using cbind(). If I understand it correctly, you are
using
My Question is how to write height length on each bar.
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R-help@r-pro
Thanks Don
Please forgive my poor mail-liost etiquette.
I had a couple of errors:
1) the counter logic in the loop was "i in name list", my typo in the post.
2) There were typos in the variable list that caused the loop to crash when
they were encountered.
Thanks for your help, really apprecia
Hi group,
I've been thinking of calculating euclidean distance between each column of
a data frames that each consists of standardized numerical columns.
However, I don't know if there's a way of summarizing the overall distance
by some kind of metrics. If anyone know a proper way of doing so an
Hi, I was reviewing a manuscript where a linear mixed model was used. The data
is simple: a response variable "y" was measured for each subject over 3 time
points (visit 1, 2 and 3) that were about a week apart between 2 visits. The
study is a non-drug study and one of the objectives was to eval
It sounds like you want something of the form
plot(distance, data, type = "h")
But the lines might be too thin: try adding lwd = NUM to increase the
thickness.
Hope this helps,
Michael
On Sat, May 26, 2012 at 11:26 PM, jack hietpas wrote:
> Hello- I am having trouble making a barplot...
>
> Th
Hello- I am having trouble making a barplot...
The y-values are:
data=c(-0.0002129061,0.00,-0.0002699561,0.0163883061,0.04).
The x-values are distance=c(0, 71, 172, 206, 292).
The desired x-range is 0 and ~300+ (kilometers), range=seq(0,300,1)
I would like to make a bar plot with
You don't, at least not for building libraries. Do it at the command line
before you invoke the R commands. If you are using Cygwin, then be sure to use
the Bash shell export command to set the variables.
---
Jeff Newmiller
Hi R- USER,
I have been struggling to compute path analysis in R. I installed package "sem"
and I tried to run the analysis but could not get a diagram.
I have very big data set, here I just copied a sample of my data and I wanted
to see how I can do the path analysis and get the patch diagram
Hi all,
Could you please tell me how do I modify the environment variable (as
below), from within R session?
LD_LIBRARY_PATH=$LD_LIBRARY_PATH:/mypath
export LD_LIBRARY_PATH
Thanks a lot!
[[alternative HTML version deleted]]
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R-help@r-projec
Luke Duncan gmail.com> writes:
>
> Dear R gurus
>
> I am running a GLMM that looks at whether chimpanzees spend time in shade
> more than sun (response variable 'y': used cbind() on counts in the sun and
> shade) based on the time of day (Time) and the availability of shade
> (Tertile). I've in
Odd... it doesn't throw an error for me.
Two things possibly come to mind, but I don't know enough of the XML
internals to know if they're reasonable. First is that something seems
funny about your version number -- mine is simply XML_3.9-4 (no added
"-1"); do you have any idea why yours would be
Thanks Uwe, I had tried this before but hearing it again made me realize what I
was doing incorrectly. I still can't get it to work with grid.draw(), but here
is the solution with ggplot():
library(ggplot2)
library(grid)
library(maps)
library(mapproj)
library(png)
library(RgoogleMaps)
counties
Hi,
You can try
rdist function under the package fields, or
dist package under stats package.
Best
Ozgur
-
Ozgur ASAR
Research Assistant
Middle East Technical University
Department of Statistics
06531, Ankara Turkey
Ph: 90-312-2105309
http://www.stat.
You could encapsulate this idiom in a function:
untilOK <- function (expr, silent = TRUE, maxIter = 1000,
quotedExpr = substitute(expr), envir = parent.frame())
{
while ((maxIter <- maxIter - 1) >= 0 && inherits(tmp <-
try(eval(quotedExpr,
envir = envir), silent = silent), "try
On 26.05.2012 18:07, Manish Gupta wrote:
Hi,
How to assign height value on bar plot for each bar?
See ?barplot.
Uwe Ligges
http://r.789695.n4.nabble.com/file/n4631457/Barplot.png
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You could put the try() into a while loop, inside for for or lapply loop,
as in:
> f <- function(x){ stopifnot(x>0.5) ; x }
> o <- numeric(100); for(i in seq_along(o)) { while(inherits(try(tmp <-
> f(runif(1)), silent=TRUE), "try-error")) {} ; o[[i]] <- tmp }
> range(o)
[1] 0.5000588 0.9991261
B
Hi,
How to assign height value on bar plot for each bar?
http://r.789695.n4.nabble.com/file/n4631457/Barplot.png
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I'm fitting a lme growth curve model with two predictors and their
interaction as predictors. The multilevel model is nested so that level 1 is
time within the individual, and level 2 is the individual. I would like to
plot the mean group-level trajectories at plus and minus 1 SD from the mean
of
On May 26, 2012, at 7:50 AM, R. Michael Weylandt wrote:
Thank you for your list of numbers. Next time I run out I'll know
where to find some.
Now what exactly is your question? Any series of data can be a time
series -- it's just a matter of interpretation.
After I stopped chuckling at Micha
Hello All,
i was trying to simply run the readHTMLTable on the example published in the
package. And on a page I was working on. So running:
u = "http://en.wikipedia.org/wiki/List_of_countries_by_population";
tables = readHTMLTable(u)
returns the following error:
Error in tb[["thead"]] : subscr
Hi there,
I would like to ask something about how to avoid a possible error message
within a for loop. I am running a simulation and in some repetitions there may
be an error that will cause a crash and stop the whole procedure, what I want
is to simply move on to the next iteration automati
Hi all,
given this example
#start
a<-c(0,70,50,100,70,650,1300,6900,1780,4930,1120,700,190,940,
760,100,300,36270,5610,249680,1760,4040,164890,17230,75140,1870,22380,5890,2430)
length(a)
b<-c(0,0,10,30,50,440,1000,140,70,90,60,60,20,90,180,30,90,
3220,490,20790,290,740,5350,940,
Hello,
Try the following.
(i've changed the color of the first ecdf.)
loga <- log10(a+1) # do this
logb <- log10(b+1) # only once
f.a <- ecdf(loga)
f.b <- ecdf(logb)
# (2) max distance D
x <- seq(min(loga, logb), max(loga, logb), length.out=length(loga))
x0 <- x[which( abs(f.a(x) - f.b(x)) ==
Hello,
You can't.
A collection of observations does not make a time series, you need an
index variable, such as time.
Rui Barradas
Em 26-05-2012 10:13, sagarnikam123 escreveu:
i have following numbers
0.889046409368551
1.22726162946495
1.22726162946495
1.
On 25.05.2012 21:50, dga...@huskers.unl.edu wrote:
Greetings R experts,
I am running a simple lda on some simulation data of mine to show an
illustration of my multivariate response data, since it is a simulation I have
a very large amount of data and the default on plot seems to plot the cat
On 24.05.2012 23:04, Patrick Nicholson wrote:
I am running 64-bit R 2.15.0 on a Windows Server 2008 R2 Amazon EC2 instance.
grid does not produce output. For example, the following code should print the
R logo to the window() device:
library(grid)
library(png)
img.path<- system.file("img", "
On 25.05.2012 22:52, servet cizmeli wrote:
Dear all,
I have a dataset of spectral measurements of sunlight. One row for each
different observation, one column for each spectral channel.
I would like to select the spectral curves drawn with matplot() (I only
know matplot() as a way of easily d
On 26.05.2012 08:17, Jhope wrote:
Hi R-listers,
I am having trouble plotting the values for the R2 line, lowess smooth,
smothered conditional spread, outlier identification.
I have tried the function text and legend but was unsuccessful. Please see
below.
Your help would be appreciated. Thank
On 26.05.2012 00:33, cgenolin wrote:
Hi the list,
Do you know if getGraphicsEvent can detect the use of keys combinaison like
"shift+arrow" or "Crlt+arrow" ?
Some key combinations, but not those mentioned above.
Just write a simple test:
getGraphicsEvent(onKeybd = function(key) cat(key, "\
I'm not sure there's a direct way to do it, but you could most likely use
abline(v = 0)
to add one to a plot. E.g.,
barplot(sample(-5:5), horiz = TRUE); abline(v = 0, lwd = 3, col = 2)
Michael
On Fri, May 25, 2012 at 10:55 PM, Manish Gupta
wrote:
> continued to previous mail .
Thank you for your list of numbers. Next time I run out I'll know
where to find some.
Now what exactly is your question? Any series of data can be a time
series -- it's just a matter of interpretation.
Michael
On Sat, May 26, 2012 at 5:13 AM, sagarnikam123 wrote:
> i have following numbers
>
>
On May 26, 2012, at 3:09 AM, Dunken wrote:
Hi!
I am working with a regression of a log-log model that suffers from
heteroskedasticity. I have calculated the "White standard errors". I
would
like to use these "White standard errors" in a RESET test instead of
the
originally OLS standard er
On 24.05.2012 12:58, abhagwat wrote:
I figured out how to use quotes and parentheses when using Rscript -e (on a
bash shell):
Rscript -e write\(1,\"a.txt\"\)
--> Question 1: why do the parentheses need to be escaped in the shell?
(More a shell than an R question)
Because the shell shopudl n
On 26.05.2012 07:34, bantex wrote:
But after looking through rollapply I still don't seem to be able to
implement it to my problem.
Could you make it more explicit for me to understand?
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html and provide commented,
min
On 23.05.2012 17:20, Jean V Adams wrote:
I'm trying to understand how a latent state matrix is updated by the MCMC
iterations in a WinBUGS model, using the package R2WinBUGS and an example
from Kery and Schaub's (2012) book, "Bayesian Population Analysis Using
WinBUGS". The example I'm using is
On 25.05.2012 16:42, Ken wrote:
Matthew Ouellette gmail.com> writes:
Hi all,
I'm just a beginner with R but I have not been able to search for any
relevant answer to my problem. I apologize if it has in fact been asked
before.
Recently I've realized that I need to combine hundreds of pair
Please ask BioC related questions on the BioC mailing list.
Best,
Uwe Ligges
On 23.05.2012 11:44, Parisa wrote:
Hi,
I am following the protocol outlined here for analysis of single channel
Agilent microarray data:
http://matticklab.com/index.php?title=Single_channel_analysis_of_Agilent_microa
i have following numbers
0.889046409368551
1.22726162946495
1.22726162946495
1.35785109728356
1.35785109728356
1.10704609982913
1.4424189950435
1.2277843378837
1.35785109728356
0.970883941918588
Hello Martin,
thank you for your reply.
Yes, it is maybe an architecture clash, we run win 7 64 bit and java 32 bit.
But R is 32-bit and the path variable is set to the 32-bit java folder. So
maybe the problem don't lies there.
Best regards
Rainer
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Hi!
I am working with a regression of a log-log model that suffers from
heteroskedasticity. I have calculated the "White standard errors". I would
like to use these "White standard errors" in a RESET test instead of the
originally OLS standard errors calculated by the regression. How can I
transfo
Hi R-listers,
I am having trouble plotting the values for the R2 line, lowess smooth,
smothered conditional spread, outlier identification.
I have tried the function text and legend but was unsuccessful. Please see
below.
Your help would be appreciated. Thanks in advance.
Jean
library(car)
Dear R gurus
I am running a GLMM that looks at whether chimpanzees spend time in shade
more than sun (response variable 'y': used cbind() on counts in the sun and
shade) based on the time of day (Time) and the availability of shade
(Tertile). I've included some random factors too which are the chi
On 05/26/2012 12:26 PM, Manish Gupta wrote:
If i assign a vector with same small width for each bar (here) still both are
same broad. I think it takes ratio for whole area. Is there any other
parameter to control it.? Any working example will help me.
Hi Manish,
If you are using the "barplot"
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