Hi Ana,
Check section 4 of http://www.jstatsoft.org/v40/i03/paper for more
alternatives.
HTH,
Jorge.-
On Mon, Dec 12, 2011 at 9:39 PM, Ana <> wrote:
> How do I sum 15 years to my dataset?
>
> original dataset
> datesval
> 12001-01-121.2
> 22001-02-121.2
> 32
If "adding x years to a date" means "increase the part of a date by
x", then it should be easiest to manipulate the character representation
of your date.
dates <- as.Date(c("2001-01-12","2001-02-12","2001-03-12"))
addYear <- function(d,addyears) {
Y <- as.numeric(strftime(d, "%Y"))
"Does not support natively" isn't accurate. It is common to import date/time
values as character and then use strptime or as.Date or other conversion
function as desired. This may at first seem tedious, but it does provide
flexibility.
wwreith wrote
>
> General goal: Write R code to find the inverse matrix of an nxn positive
> definite symmetric matrix. Use solve() to verify your code works.
>
> Started with a 3x3 matrix example to build the code, but something dosen't
> seem to be working. I just don't know where I am going w
Dear Uwe and David,
Yes, definitely i was wrong. The expression in R should be:
glm(cbind(FD, 12 - FD) ~ Fsize, family=binomial, data=subFS)
Call: glm(formula = cbind(FD, 12 - FD) ~ Fsize, family = binomial,
data = subFS)
Coefficients:
(Intercept)Fsize
0.6381 -0.1203
Please,
I am receiving lot of e-mails that I do not want.
Please could you delete my e-mail.
Thank,
Judit
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Thomas Adams
Sent: Monday, December 12, 2011 3:22 PM
To: Bert Gunter
Cc: r-he
I need to force the GWR(geographic weighted regression) to the origin(0,0).
Could you tell me what is the code?
I tried writing -1 as in the lm but it does not work.
Thanks in advance,
Judit
[[alternative HTML version deleted]]
__
R-help@r-proj
Hello, and please advise regarding any errors/omissions on my part.
However, the documentation for R's tcplot function in the evd package
appears to contain an error. I am using evd version 2.2-4 in R 2.14.0
with Windows XP.
> data(portpirie)
> mrlplot(portpirie) ## No Error
> tlim <- c(3.6, 4.
2011/12/12 Uwe Ligges :
> On 12.12.2011 17:44, Tony Stocker wrote:
Sorry for the double post but the first message was held for so long
that I figured there was a problem with the email address I was using
so I unsubscribed that one and resubscribed the other one.
>>
>> Hello,
>>
>> I am dealing
On 12/13/2011 12:14 PM, Ryan Utz wrote:
My vectors names are neatly stored in a character vector of their own. This
happens based on how they were imported. So, say I have vectors a, b and c,
all with numeric-only contents. Then I have another vector, say z, that
looks like this:
z<-c("a","b","c
General goal: Write R code to find the inverse matrix of an nxn positive
definite symmetric matrix. Use solve() to verify your code works.
Started with a 3x3 matrix example to build the code, but something dosen't
seem to be working. I just don't know where I am going wrong.
##Example matrix I fo
It depends how your dates are stored, but generally you can just add
365*15 to them. E.g.,
print(x <- Sys.Date())
print(x + 365*15)
So for you,
dataset$dates <- dataset$dates + 365*15
Michael
On Mon, Dec 12, 2011 at 9:39 PM, Ana wrote:
> How do I sum 15 years to my dataset?
>
> original datas
How do I sum 15 years to my dataset?
original dataset
datesval
12001-01-121.2
22001-02-121.2
32001-03-121.2
result
datesval
12016-01-121.2
22016-02-121.2
32016-03-121.2
_
Hi folks!
I am trying to read a large XML file from the Fed that contains quarterly
Flow of Funds data since the 1950s. It contains lots of individual tables
in something called the "Statistical Data and Metadata eXchange format"
(SDMX format).
I am not sure if I need something specific to the
Dear All,
I am fitting a simple GAM model using the "gam" function in the "mgcv"
package. The only independent variable is a continuous variable
representing the time of the event (in year and month) coded so that
"0" represents January 1960, "1" represents February 1960, etc. Now
when I try to pl
Please read the posting guide and provide a (small) reproducible example
of your data.
The statement "...output does not seem good." is not very useful.
Please explain what you would like the polygon area to look like, and
why you don't like the way it came out. Links to posted images of the
If you have already made numeric vectors called "a", "b", and "c"
a <- 1:10
b <- sqrt(1:200)
c <- log2(1:500)
and a character vector "z" containing their names
z <- c("a", "b", "c")
then make a list containing the data with them with
dataList <- lapply(z, get, envir=environment())
Hi,
So far as I can tell, the 'col.ticks' parameter for axis() only uses the
first value provided. E.g.:
plot(0:1,0:1, col.ticks=c('blue','red','green')) #all ticks are blue
Just wondering if there's a different option in the basic plot commands
that can handle multiple colors, and also wh
Here is an example. It requires a bit of extra work, but that's the beauty of R
-- you can essentially customize a graph to your taste with low-level
functions. I also added the prediction interval using the addcred argument (as
suggested by Michael), since it gives the same information as that
Hi All,
I am pretty new for RODBC. I want to save my table to a DB, so I
used something like
sqlSave(db, a, 'Forecast_Result', rownames = FALSE);
But I got an error
Error in sqlSave(db, a, "Forecast_Result", rownames = FALSE) :
table 'Forecast_Result' already exists
Yes, that tab
Try the RColorBrewer package, with function ?brewer.pal
You probably want a Qualitative palette, the details are in that
function's help page.
Cheers, Mike.
On Tue, Dec 13, 2011 at 10:14 AM, Etienne B. Racine wrote:
> I'm looking for a palette that would maximize the discrepancy with
> neighbou
Thomas:
I stand corrected. Thank you.
-- Bert
On Mon, Dec 12, 2011 at 2:21 PM, Thomas Adams wrote:
> Bert,
>
> I may be mistaken, but I thought Ryan wrote "write code that automatically
> imports data from different files (with different lengths-just one
> variable)", so, I was referring to doi
On 2011-12-12 15:14, Ryan Utz wrote:
Thanks for the help, everyone. However, no solution yet...
My vectors names are neatly stored in a character vector of their own. This
happens based on how they were imported. So, say I have vectors a, b and c,
all with numeric-only contents. Then I have anot
Thanks for the help, everyone. However, no solution yet...
My vectors names are neatly stored in a character vector of their own. This
happens based on how they were imported. So, say I have vectors a, b and c,
all with numeric-only contents. Then I have another vector, say z, that
looks like this
I'm looking for a palette that would maximize the discrepancy with
neighbouring elements.
I have a raster image of objects tagged with integers. I'd like to
highlight the different objects by using a palette that would maximize this
difference with neighbours as close numbers tend to be neighbours
Ryan,
Do you necessarily have to use "list"? Have you tried the usecols=TRUE option
in boxplot?
Cheers,
--Kelly V.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Ryan Utz
Sent: Monday, December 12, 2011 1:24 PM
To: r-help@r-proje
Dear R users,
I know that it was considered many times but having searched through dozens
of posts I have only added to my confusion. My question is - is it possible
to correctly analyse simple mixed (fully)crossed (factorial) 2-way ANOVA?
Assume we have factor A (fixed) and B (random). In the mo
Bert,
I may be mistaken, but I thought Ryan wrote "write code that
automatically *imports
data* from different files (with different lengths-just one variable)", so,
I was referring to doing something with the data before it gets into R. I
understand that one should not need to write out data and
Sorry -- previous versiuon prematurely sent. Full version is:
Yikes! You should never have to do this sort of thing (writing stuff
out to files, etc.)
What is wanted, I believe, is ?do.call as in
do.call(boxplot, z)
where z is list(a,b,c) as Sarah described.
However, I think you might
On 13/12/11 04:39, threshold wrote:
Indeed in txt it looks fine. Anyway, I must stay without 0 because csv is THE
format.
It may well be the case that csv is THE format, but csv is not the problem.
Excel is the problem.
The solution is: Don't use Excel!!! (This is excellent advice in any
c
Ryan,
I think you could do what you want by having the vector data written to
separate files; then create a file containing the individual file names. In
R, read the file containing the list of file names and loop through this
reading in the individual vector files. Maybe this is an inelegant, bru
Hi,
On Mon, Dec 12, 2011 at 4:24 PM, Ryan Utz wrote:
> Hello,
>
> I'm attempting to write a code that automatically imports data from
> different files (with different lengths-just one variable) and makes tidy
> box plots for comparison. I can successfully import the data and create a
> list of t
Hello R folks,
Iâm looking to produce a confusion matrix using the command:
cmx(PData,threshold=0.49,na.rm=FALSE) for a logistic regression model (1 is
habitat, 0 is nonhabitat).
To compile my PData data file (csv file) (as in the example above), Iâm using
the output of the predict(glm) f
Hello,
I'm attempting to write a code that automatically imports data from
different files (with different lengths-just one variable) and makes tidy
box plots for comparison. I can successfully import the data and create a
list of the vectors I want to compare. But I cannot, for the life of me,
fi
Greetings!
I'm having an issue with the windrose produced by the windrose
function from the circular package. For our weather stations in North
Carolina I'm helping with a script which takes hourly wind speed and
direction data to create windroses for our end users. One of the
stations in the mo
On Dec 12, 2011, at 3:51 PM, Uwe Ligges wrote:
1. The formula you used is not for a logistic but an ordinal
regression (since you are using the default gaussian family rather
than family="binomial" or whatever.
this this then produce one version of the "Armitage linear test of
trend"?
On Dec 12, 2011, at 3:38 PM, Uwe Ligges wrote:
On 12.12.2011 19:36, Brian Jensvold wrote:
I am doing a logistic regression, and by accident I included a field
which has the 2digit abbreviation for all 50 states labeled "st".
I was
surprised to see that the glm did not come up with an erro
1. The formula you used is not for a logistic but an ordinal regression
(since you are using the default gaussian family rather than
family="binomial" or whatever.
2. R (nor any other software) can deal with perfect separation (nor
quasi-separation) of classes, since the problem is not well de
On 12.12.2011 19:36, Brian Jensvold wrote:
I am doing a logistic regression, and by accident I included a field
which has the 2digit abbreviation for all 50 states labeled "st". I was
surprised to see that the glm did not come up with an error message but
instead appears to have automatically
On 12.12.2011 17:44, Tony Stocker wrote:
Hello,
I am dealing with data stored in a database as a 'time' object. I
export the data from the database to a text file and utilize the
'time_to_sec()'
I get
> time_to_sec
Error: object 'time_to_sec' not found
If it is in a package, please tell u
Please post only once!
Uwe Ligges
On 12.12.2011 20:32, Tony Stocker wrote:
Hello,
I am dealing with data stored in a database as a 'time' object. I
export the data from the database to a text file and utilize the
'time_to_sec()' function of the database to convert the human readable
time (HH
I would recommend using data.frame(var1, var2, ...)
and not cbind.data.frame(var1, var2, ...). I consider
it bad form to directly call a method of a generic function.
Sometimes it leads to errors, as a method should be
free to assume that its inputs are of the class it
was declared to accept. In
I'm glad that worked for you. It's a good idea to reply to the
list, as well as me, so that there's public acknowledgment of
a working solution, and so that the answer appears in the
archives.
Sarah
On Mon, Dec 12, 2011 at 2:56 PM, Jose Bustos Melo wrote:
> Thank you Sarah!!... that works well,
I really like your varclus function Frank. I have a question about the
quartimax rotation of the 1st two eigen vectors as the SAS VARCLUS algorithm
dictates. According to the SAS user guide example of VARCLUS the only thing
needed to perform the cluster analysis is the variable correlation matrix
Hello,
I am dealing with data stored in a database as a 'time' object. I
export the data from the database to a text file and utilize the
'time_to_sec()' function of the database to convert the human readable
time (HH:MM:SS) to seconds so that I can use R to do analysis and
create charts of the d
Dear Jose,
Am Montag, den 12.12.2011, 19:44 + schrieb Jose Bustos Melo:
> Hello everyone,
>
> I want make a variable selection from a dataframe, but when I build this new
> object (using cbind) the new table (which is a matrix) I lost all the
> original factor names in the variables. I get
Without a reproducible example it's impossible to say for certain,
but I'd try
cbind.data.frame() instead of cbind().
You need to have a data frame, not a matrix, for the result.
Sarah
On Mon, Dec 12, 2011 at 2:44 PM, Jose Bustos Melo wrote:
> Hello everyone,
>
> I want make a variable selectio
Hello everyone,
I want make a variable selection from a dataframe, but when I build this new
object (using cbind) the new table (which is a matrix) I lost all the original
factor names in the variables. I get 1,2,3
Someone would be so kind and tell me if there's is a ny way to get variable
--begin inclusion --
I have a matched-case control dataset that I'm using conditional
logistic regression (clogit in survival) to analyze. I'm trying to
conduct k-folds cross validation on my top models but all of the
packages I can find (CVbinary in DAAG, KVX) won't work with clogit
models. Is t
...
On Mon, Dec 12, 2011 at 7:00 AM, Jinsong Zhao wrote:
> Apart from the data set here, is there a way to do multiple comparison on
> the interaction of one way analysis of covariance?
>
Interaction in ancova usually means the slopes are different.
...
BTW, when loading HH package, the TukeyH
Kevin,
Your problem seems to have three restrictions: (1) abs(x[i] - x[i-1]) >=
delta (2) y[i] >= x[i]
and (3) minimize sum(y-x). If this is the case I believe I have a better
solution, with a smaller sum
and in much less time.
The problem is restriction (2). If the diffs are negative you can't su
Hello,
I am dealing with data stored in a database as a 'time' object. I
export the data from the database to a text file and utilize the
'time_to_sec()' function of the database to convert the human readable
time (HH:MM:SS) to seconds so that I can use R to do analysis and
create charts of the d
Kevin,
I'm sorry, but my code has a bug
The correction is:
1) delete the two lines with 'ix'
2) replace them with
for(i in 2:n)
if(abs(x[i] - x[i-1]) < delta) x[i] <- x[i-1] + delta
That's it. The problem is that it's back to slowness.
Sorry, once again,
Rui Barradas
right,
Table <- data.frame(matrix(0,8,3))
day = "Monday"
Table[1,1]=day
Table[1,2]=3
works, thanks a lot. robert
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Dear Paul and Sarah
Thanks for the suggestion. I have provided my data here in to make the results
reproducable. I am actually trying to do interpoliation of climate data where
x1 and x2 are my latitude and longitude and sum64-sum 368 are my rainfall
observations which I need to regress against
I am doing a logistic regression, and by accident I included a field
which has the 2digit abbreviation for all 50 states labeled "st". I was
surprised to see that the glm did not come up with an error message but
instead appears to have automatically broken down this field into
individual fields (
Hello,
I'm currently trying to convert a slow and ugly script I made, so that it's
faster and can be computed on a computer grid with the multicore package.
My problem is that I don't see how to turn some loops into an "apply-able"
function.
Here's an example of my loops :
I got a list of datafra
Hi Ryan,
My name is Frederic Andrieu and I work for Mango Solutions in the UK. It looks
like you have swapped the a and c in this for loop statement:
This "for (c in a(1:2000)) {" should be this "for (a in c(1:2000)) {"
Which is why the for loop is not running, I would suggest something like th
I don't know why you had "c in a(1:2000))"
c is a function see ?c ...
and you want "a" (the row number in SQL_Code) to change with each iteration
in the loop.
Perhaps this might work (I'm not saying this is the best option, just a
potential fix for what you have):
for (a in 1:2000) {
Dataset
Thanks!
Another question also related to the same type of files:
How can I transform it into a time series
as.ts()
I also endup having the same problem, the dates are transformed into a
list of numbers
My file looks like this
datesval
12001-01-121.2
22001-02-12
At 15:09 11/12/2011, you wrote:
Dear Michael,
Thanks for the email. This is the kind of forest plot, I want to replicate
http://www.biomedcentral.com/1471-2334/11/122/figure/F2
It would be helpful to cc to r-help in case someone else there knows better.
If you follow my suggestion you get a
There are methods of the "c" function for things of class "POSIXlt" and "Date"
so do.call("c", dataList) works instead of unlist:
> dateList <- list(LastWeekend=as.POSIXlt(sprintf("2011-12-%d", 10:11)),
+ Today=as.POSIXlt("2011-12-12"))
> z <- do.call("c", dateList)
> z
how can I keep the date info after doing unlist to a list of dates?
I have a list of dates were observations were made for each station in
each month
list.obs[[station]][month]
[1] "1979-01-01" "1979-01-10" "1979-01-25"
[1] 0 1 2 3
when i try to unlist i loose the date info.
w
Ah. I did a Silly Thing, and thank you for all the responses helping me track
it down.
The issue lay not in the for (i in 1:C) but in the line VectorName[i] <- ...
That's the one that didn't like 0.
Thomas
From: Enrico Schumann [enricoschum...@yahoo.de]
That's not a reproducible example. Paul suggested a list of formulas,
but I recommended creating a list of y variables.
In your attempt, you didn't include the y in the name of the dependent
variable; that's probably why it doesn't work.
Look at this:
> y.list <- list(y1=runif(10), y2 <- runif(1
Dear Paul and Sarah
Thanks for the suggestion. I have provided my data here in to make the results
reproducable. I am actually trying to do interpoliation of climate data where
x1 and x2 are my latitude and longitude and sum64-sum 368 are my rainfall
observations which I need to regress against
Am Montag, den 12.12.2011, 09:41 -0500 schrieb R. Michael Weylandt :
> Why can't you just replace "temp/data" with filename (no quotes)? I'm not
> sure I get the question...
… no I am feeling silly and I do not know where I screwed up before.
Here is the full working example.
#!/usr/bin/
Matrix (which is secretly a vector) can only have one mode
(numeric/factor/character/etc.) for all its elements. If you need
multiple types, go to a data frame
Michael
On Mon, Dec 12, 2011 at 10:39 AM, threshold wrote:
> Indeed in txt it looks fine. Anyway, I must stay without 0 because csv is
Hi Jim,
Thanks so much for your help. I have read several of your responses on this
mailing list and they have helped me out quite a bit as I have gotten more
and more used to R.
I am still a little confused here by your response.
I think you understood my requirements correctly.
In your words
The dput() command is essential in doing so.
Michael
On Dec 11, 2011, at 8:50 AM, Tal Galili wrote:
> Yes -
> E-mail us reproducible code...
>
>
> Contact
> Details:---
> Contact me: tal.gal...@gmail.com | 972-52-7275845
>
Indeed in txt it looks fine. Anyway, I must stay without 0 because csv is THE
format.
I got another question. why for
Table <- matrix(0,8,3)
day = "Monday"
Table[1,1]=day
all other elements become characters too?
Thanks, robert
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Hi Michael,
As far as I know, there is no Arima function in R that allows multiple
seasonal patterns. There's 2 approaches you can take:
1. Use a matrix of dummy variables (e.g. jan/feb/mar/...dec and
mon/tues/wed/...sun) as an xreg term in the arima function.
2. Use a matrix of Fourrier terms to
Hi everybody,
I have a matrix with 3 columns (Date, MeanArea and SdArea). I want to draw a
figure showing the variable MeanArea in terms of the Date. But instead to
use the variable SdArea as bar error, I want to use “polygon error”. I use
this code but the output does not seem good.
Polyhttp://r.
Hello R-Experts,
I've got a question, concerning the automation of a number of regressions
(lm) with the help of a loop (for i in ).
The situation is as follows (the code follows after that):
I have my data in an access database. I have historical data for 2000 parts,
for each of this parts I
On Mon, Dec 12, 2011 at 2:19 AM, tony333 wrote:
> i use library(ncdf) to read this file as follow
> library(ncdf)
> sst.nc = open.ncdf(title)
> lonall = get.var.ncdf(sst.nc,'lon')
> latall = get.var.ncdf(sst.nc,'lat')
> precip = get.var.ncdf(sst.nc,'pre')
> close(sst.nc)
> if i use this method my
Dear R users,
I want to test for serial correlation in each equation of VAR.
The multivariate version of this test, for a vector X of class VAR for
instance is
var.ser<-serial.test(X,lags.pt=16,type="PT.adjusted") ### in the vars
package
Would any of you suggest me how to modify this to test fo
Please sign yourself out, using the linke that appears at the bottom of
each and every message from the list.
On Mon, Dec 12, 2011 at 9:48 AM, Kaigang Li wrote:
>
> [[alternative HTML version deleted]]
>
> __
> R-help@r-project.org mailing list
>
Thanks a lot. I didn't find that. I prefered the option with class
discovery package which we have to install from OOMPA project.
barbara
On 12 December 2011 11:58, Sarah Goslee wrote:
> Did you try this:
>
> http://r.789695.n4.nabble.com/coloring-leaves-in-a-hclust-or-dendrogram-plot-td795496.h
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, r
Why can't you just replace "temp/data" with filename (no quotes)? I'm not sure
I get the question...
Michael
On Dec 12, 2011, at 5:26 AM, Paul Menzel
wrote:
> Dear R folks,
>
>
> I have several data sets I want to process automatically using R. I
> found littler [1] and thought this will do
This question is perhaps best asked on the specialized Bioconductor mailing
list. The audience there is quite knowledgeable and will certainly be able to
help.
Michael
On Dec 11, 2011, at 8:08 AM, ali_protocol
wrote:
> Dear all,
>
> Is there anyway too generate MA plot for 2 qPCR assays (a
On Dec 12, 2011, at 7:23 AM, threshold wrote:
Dear R users, I got the following problem. Given that
data[3,2]
[1] "010252"
Code:
intro <- data.frame()
intro[1,1] <- as.character(data[3,2])
write.csv(intro, file='intro.csv')
In 'intro.csv' file I am loosing the 0 in frot of 10252, which I
I was wondering if there is way to place constraints upon the "plinear"
algorithm of nls, or rather is there a manner in which this can be achieved
because nls does not allow this to be done.
I only want to place constraints on one of the nonlinear parameters, a, such
that it is between 0 and
Thank you! I'm going to look into that straight away.
Manu
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Hi
>
> Dear R users,
>
> I am using the code below to generate a fitted value of b. I have about
> 300 different values for for y (y1, y2, ...y300) which means I will have
> to write the code below 300 times to generate the 300 different fitted
> values for y. Is there a short way of doing t
On 12/12/2011 10:19 AM, tony333 wrote:
> i use library(ncdf) to read this file as follow
> library(ncdf)
> sst.nc = open.ncdf(title)
> lonall = get.var.ncdf(sst.nc,'lon')
> latall = get.var.ncdf(sst.nc,'lat')
> precip = get.var.ncdf(sst.nc,'pre')
> close(sst.nc)
> if i use this method my pc freeze
On 12/12/2011 10:39 AM, Alexander wrote:
> Hello,
> I am trying to write a script to analyse R scripts, which contain only
> functions. Therefor, I want to test the R script if it contains onyl correct
> code. Is there a nicer and more efficent function than
>
> test <- try(source("someRscript"))
>
threshold wrote on 12/12/2011 06:23:33 AM:
> Dear R users, I got the following problem. Given that
>
> > data[3,2]
> [1] "010252"
>
> Code:
> intro <- data.frame()
> intro[1,1] <- as.character(data[3,2])
> write.csv(intro, file='intro.csv')
>
> In 'intro.csv' file I am loosing the 0 in frot of
On 12/12/2011 10:39 AM, Alexander wrote:
> Hello,
> I am trying to write a script to analyse R scripts, which contain only
> functions. Therefor, I want to test the R script if it contains onyl correct
> code. Is there a nicer and more efficent function than
>
> test <- try(source("someRscript"))
>
On 12/12/2011 01:16 PM, Mintewab Bezabih wrote:
> Dear R users,
>
> I am using the code below to generate a fitted value of b. I have about 300
> different values for for y (y1, y2, ...y300) which means I will have to write
> the code below 300 times to generate the 300 different fitted values f
This isn't a reproducible example, so I can't provide code,
but I would put all the y variables in a list and use lapply().
Sarah
On Mon, Dec 12, 2011 at 8:16 AM, Mintewab Bezabih
wrote:
> Dear R users,
>
> I am using the code below to generate a fitted value of b. I have about 300
> different
?prop.test
The very first line in the help file on the function prop.test():
"prop.test can be used for testing the null that the proportions
(probabilities of success) in several groups are the same ..."
How to interpret the results of the prop.test() you ran? The proportion
preferring
Dear R users,
I am using the code below to generate a fitted value of b. I have about 300
different values for for y (y1, y2, ...y300) which means I will have to write
the code below 300 times to generate the 300 different fitted values for y. Is
there a short way of doing that ?
Many thanks
PEL wrote on 12/07/2011 02:37:42 PM:
> Hi all,
>
> I have dataframe that was created from the fusion of two dataframes.
Both
> spanned over the same time intervall but contained different
information.
> When I put them together, the info overlapped since there is no holes in
the
> time interva
Dear R users, I got the following problem. Given that
> data[3,2]
[1] "010252"
Code:
intro <- data.frame()
intro[1,1] <- as.character(data[3,2])
write.csv(intro, file='intro.csv')
In 'intro.csv' file I am loosing the 0 in frot of 10252, which I need. Is
there a way to keep the full character sav
Dear Mr. Ripley,
your answer perfectly fits my needs, thank you very much.
(And yes, rounding 5 to even is what I wanted).
Prof Brian Ripley wrote
>
> t2 <- strptime(timeStamp, format="%d.%m.%Y %H:%M")
> t2$min <- round(t2$min, -1)
>> format(t2, "%d.%m.%Y %H:%M")
> [1] "31.03.2011 09:30" "31.03
Hi Jim,
I think this will work well for what I need it for - thanks a lot!
I would still be interested (for interest sake) if anyone knows how to
get this to work using sunflower plot.
Thanks again,
Nicola
-Original Message-
From: Jim Lemon [mailto:j...@bitwrit.com.au]
Sent: 12 Decem
Dear statistician experts,
Sorry if this is a trivial question, or the old same question (i don't know
what is the efficient key word for this issue).
In order to understand the calculation of parameter of logistic regression,
I did an exercise through spreadsheet following the procedural example
Dear,
I am using the solnp command (package Rsolnp) for a problem with
equality and inequality constraints.
I am not getting convergence for my problem but apart that I get 1
warning per iteration saying: ?In cbind(temp, funv) : number of rows
of result is not a multiple of vector length
On Dec 11, 2011, at 10:19 PM, jalfaro wrote:
Hello,
Were you ever able to find a solution to your problem?
I have been trying on and off to solve this problem for several
months now.
I would love to hear if you found a solution.
Neither the person who posted the problem a year ago or you h
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