> RSiteSearch("cross product")
> library(pracma)
> ?cross
>
> Speed is usually desired in the context of many similar computations, and
is
> normally achieved in R by vectorizing computation, so storing the large
> number of 3d vectors together in a structure like a Nx3 matrix so the
code
> can be
Thank you all.
I do have two huge matrix like M1[x,y,z,3] x M2[x,y,z,3].
I'll try it.
Best,
Bai
On Fri, Jul 8, 2011 at 11:56 PM, Jeff Newmiller
wrote:
> RSiteSearch("cross product")
> library(pracma)
> ?cross
>
> Speed is usually desired in the context of many similar computations, and is
> norm
The problem arises in the computation of U where (-dummy+1) turns negative
(the eighth and higher index values of "dummy"). You raise a negative number
to a non-integer power, for example, (-pi)^exp(1), which fails because you
would not be able to tell, which sign the resulting number should have.
Dear all,
I have a data frame which is like-
V1 V2 V3 V4
9 2 ., a\
9 2.$, a`
13 1 , a
13 1 , a
13 1 , a
1
Hi folks,
I have been tormented for some time by Excel's habit of exporting dates
to CSV files as mm/dd/ format even if the dates are formatted
dd/mm/ in the display. What's worse, if there are dates that are of
ambiguous (6/6/2011) and unambiguous (16/6/2011) format in the same
column
It does!! why is this function not mentioned in the "See also" docpage for
"by" (and friends)??? (Also, "ave" should be mentioned there, too.)
do I post this suggestion to add it to r-devel, or is there a way to find
out who is in charge of the docpage for "by"?
regards,
/iaw
On Fri, Jul 8,
Q1. simplify2array(b) gives the transpose of what
I think you want.
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of ivo welch
> Sent: Friday, July 08, 2011 3:43 P
Hi Ivo,
See inline.
On Fri, Jul 8, 2011 at 3:42 PM, ivo welch wrote:
> dear R wizards---more ignorance on my part, exacerbated by too few
> examples in the function documentations.
>
>> d <- data.frame( id=rep(1:3,3), x=rnorm(9), y=rnorm(9))
>
> Question 1: how do I work with the output of "by"?
On Jul 8, 2011, at 6:54 PM, Marius Hofert wrote:
Dear expeRts,
How can I vertically adjust an axis tick label so that it is nicely
aligned with
the other labels?
library(lattice)
xyplot(0~0, xlim=c(0,3), scales=list(x=list(at=c(1,1.1),
labels=c(expression(hat(theta)[italic(n)]),expressio
So i think I am doing mistake in converting ASCII values in col V10 in my data
frame (dfa.).can you please tell me that, is this the right way to convert
ASCII values into decimal-
dfa$V10=lapply(dfa[,4], function(c) as.numeric(charToRaw(c)))
Thanking you,
Warm Regards
Vikas Bansal
Msc Bioin
try this:
> x <- c(36, 40, 10, 4)
> x.m <- matrix(as.integer(intToBits(x)), byrow = TRUE, ncol = 32)[, 1:20]
> x.m <- data.frame(x.m) # convert to data.frame
> x.m
X1 X2 X3 X4 X5 X6 X7 X8 X9 X10 X11 X12 X13 X14 X15 X16 X17 X18 X19 X20
1 0 0 1 0 0 1 0 0 0 0 0 0 0 0 0 0 0
On Jul 8, 2011, at 6:46 PM, Bansal, Vikas wrote:
Yes sir.you are right.after this I use this code to convert ASCII
values in column V10 to decimal numbers-
dfa$V10=lapply(dfa[,4], function(c) as.numeric(charToRaw(c)))
now u will get output something like this-
V7 V8
V9
Dear expeRts,
How can I vertically adjust an axis tick label so that it is nicely aligned with
the other labels?
library(lattice)
xyplot(0~0, xlim=c(0,3), scales=list(x=list(at=c(1,1.1),
labels=c(expression(hat(theta)[italic(n)]),expression(theta)
## aim: move the leftmost expression up so t
Yes sir.you are right.after this I use this code to convert ASCII values in
column V10 to decimal numbers-
dfa$V10=lapply(dfa[,4], function(c) as.numeric(charToRaw(c)))
now u will get output something like this-
V7 V8 V9 V10
dear R wizards---more ignorance on my part, exacerbated by too few
examples in the function documentations.
> d <- data.frame( id=rep(1:3,3), x=rnorm(9), y=rnorm(9))
Question 1: how do I work with the output of "by"? for example,
> b <- by( d, d$id, function(x) coef(lm( y ~ x, data=x ) ))
> b
Happy weekend helpeRs!
As usual, I'm stumped by R...
My plan was to take an integer number, convert it to binary and wind
up with a data.frame where each column is either 1 or 0 so I can see
which bits are changing:
bb<-function(i) ifelse(i, paste(bb(i %/% 2), i %% 2, sep=""), "")
my.dat<-c(36,4
I get something entirely different when I execute that input command
with the attached file:
This is what I see as the first 14 lines for a displayed value for dfa:
> dfa
V7 V8 V9 V10
10 1 G`
20 1 Ta
30 1 Ca
40 1 Aa
50 1 G_
60 1
On 7/7/2011 9:14 PM, michael.laviole...@dhhs.state.nh.us wrote:
Are there any packages with functions that can fit quasi-symmetry and
quasi-indepedence models to square contingency tables?
M. Laviolette
Yes.
See the gnm package for convenience functions that work with
glm() and gnm().
See the
Hello,
Sorry if it's a simple question, this is my first script complex, but can
not find solution in the list
I have many TXT files with daily data of meteorological stations and a
table that connects it with each of these stations. (More than one table per
station and date).
With the Script at
Dear all,
I am really sorry for not giving the input file because in my mail,I did not
explain my problem in a best way.
I have a file that is summary.txt(I have attached it) .we can read this file
using-
dfa=read.table("summar.txt",fill=T,colClasses = "character",header=T)
In V10 column I
Dear all,
I am really sorry for not giving the input file because in my mail,I did not
explain my problem in a best way.
I have a file that is summary.txt(I have attached it) .we can read this file
using-
dfa=read.table("summar.txt",fill=T,colClasses = "character",header=T)
In V10 column I h
At 07:12 09/07/2011, you wrote:
Dear jholtman,
Thanks for the reply & sorry for the been unclear before.
My desire graph is to have multiply plots showing Y1,Y2,Y3 with the same X,
were each plot is month-year (e.g., 5-2001, 6-2001, etc). It ill be great if
each Y can have a different line and
I am trying to create a set of wavelets in frequency space--namely Cauchy
wavelets for an intensity analysis (von Tscharner, 2000). The wavelets are
defined by the following formula:
[(f/cf)^(cf*scale)]*[e^((-f/cf)+1)^(cf*scale)]
where *f *is frequency of length *n*, *cf* is center frequency (de
--- Begin Message ---
Hi Vikas. Apply the logic in the example below in your dataframe
> dta
V1 V1
1 85 32
2 80 33
3 77 11
4 75 56
5 96 43
6 99 12
7 94 32
8 97 44
> dta[,1]>
[1] TRUE TRUE FALSE FALSE TRUE TRUE TRUE TRUE
> which(dta[,1]>)
[1] 1 2 5 6 7 8
> ref <- which(dta[,1]>)
> dt
Dear jholtman,
Thanks for the reply & sorry for the been unclear before.
My desire graph is to have multiply plots showing Y1,Y2,Y3 with the same X,
were each plot is month-year (e.g., 5-2001, 6-2001, etc). It ill be great if
each Y can have a different line and point style.
The Lattice graph
Hi,
I really feel I've looked everywhere, although I know this can't be a hard
problem. I'd like to be able to call the graph below as a function, but I
can't get the function to recognize variables beyond 'dframe'. I've read
through many papers on writing functions in R, but I can't get this to w
Dear sir,
I am struggling with a problem.Please help me.
Now I have a dataframe with these columns-
V7 V8 V9 V10
0 1 G82
0 1 CGT
Hi:
Do you want the N points in the vector closest to a fixed point? If
so, then try this:
f <- function(vec, center, nselect) {
d <- (vec - center)^2
vec[order(d)][1:nselect]
}
v <- rnorm(1000)
f(v, 0, 10)# select the ten points in v closest to zero
Your goal is subject to multip
On Jul 8, 2011, at 2:53 PM, rstudent wrote:
I have only been using R for a very short time and I'm trying to
learn.
What information do you need to help me?
As it says at the bottom of every message to Rhelp:
" read the posting guide http://www.R-project.org/posting-guide.html "
--
Vie
rstudent,
one solution could be given by spliting your graph in two parts:
part_1 <- # take the desired four points subset #
part_2 <- # all rest points not to label
You will also need one vector with your names. I supose:
list <- c("B13", "G13", "K14", "N14")
So
plot(part_1$x, part_1$y)
text
I have only been using R for a very short time and I'm trying to learn.
What information do you need to help me?
--
View this message in context:
http://r.789695.n4.nabble.com/How-to-label-specific-points-on-a-scatterplot-tp3654697p3654903.html
Sent from the R help mailing list archive at Nabble
On Jul 8, 2011, at 3:16 PM, Nipesh Bajaj wrote:
Hi there, given a numeric vector, I can select numbers within a
specific range. However presently, I have something related but
different problem. Suppose I have a numeric vector. Now take an
arbitrary number. Goal to to chose a specific subset wi
Hi there, given a numeric vector, I can select numbers within a
specific range. However presently, I have something related but
different problem. Suppose I have a numeric vector. Now take an
arbitrary number. Goal to to chose a specific subset with a given
length, from that given vector, so that t
Answering
http://r.789695.n4.nabble.com/How-to-generate-heteroscedastic-random-numbers-td3654534.html
I think best way to generated Heteroscedastic data would be, first
fix or assume some DGP of your choice, you may assume any arbitrary
model parameter(s) provided forms of those parameters are l
I noticed that there is a newer version of Tom Short's "cheat sheet" than
the version currently posted on CRAN.
Personally I like the newer version, but maybe keeping the old version is
deliberate. Anyway, I was wondering if there's someone that I can notify
that can update the content.
New vers
On 08/07/2011 2:47 PM, ssathnur wrote:
I want to call in files from subdirectories without changing my working
directory within my script. Is that possible? And if so what would be the
simplest way to do that?
for example, if I do setwd("C:/Users/Hello")
but I have files in C:/Users/Hello/Data1
I want to call in files from subdirectories without changing my working
directory within my script. Is that possible? And if so what would be the
simplest way to do that?
for example, if I do setwd("C:/Users/Hello")
but I have files in C:/Users/Hello/Data1 and C:/Users/Hello/Data2, can I
still ke
Thank you Gerrit for the quick reply! And yes, i'm Matti.
I can get the coeffs now, though i'm not sure whether i'm doing
something wrong or whether poly is just not the right method for what
i'm trying to find. I will look into this more closely and give it
another try.
Is poly best for fit
On Jul 8, 2011, at 2:02 PM, rstudent wrote:
I can use the text() command to label all points but how do you
specify only
to label those four specific points on the graph?
No context, no example, evidence that you read the rest of my message,
no further response.
--
View this message i
I can use the text() command to label all points but how do you specify only
to label those four specific points on the graph?
--
View this message in context:
http://r.789695.n4.nabble.com/How-to-label-specific-points-on-a-scatterplot-tp3654697p3654777.html
Sent from the R help mailing list arch
On Jul 8, 2011, at 1:44 PM, FMH wrote:
Dear All,
I am working on a time series of hourly river flow measurements from
2000 - 2003 and have been trying to compute the extremum index from
the original series as well as a new series from sampling with
replacement . The extremum Index prod
On Jul 8, 2011, at 1:31 PM, rstudent wrote:
Command I am using for the plot:
plot(Raw[][Plate==101]~well[][Plate==101], xlab="Well", ylab="Raw",
main="Plate 101")
I only want to label points on the graph where well equals B13, G13,
K14 and
N14 with the name of the well.
?"%in%"
?text
Dear All,
I am working on a time series of hourly river flow measurements from 2000 -
2003 and have been trying to compute the extremum index from the original
series as well as a new series from sampling with replacement . The extremum
Index produced from the original data series looks fin
Hi,
I have a set of nodes and a dissimilarity matrix for them, as well as a csv
file in which the diss matrix has been converted to [node_1, node_2,
dissimilarity] format. I would like to visualize this as a graph in
Euclidean space (that is, similar nodes clumped together in clusters),
rather th
Another possibility without using subset():
plot(Well[][Plate==101]~Raw[][Plate==101])
This also works to '>=' '<=' and other conditions.
--
View this message in context:
http://r.789695.n4.nabble.com/Simple-conditional-plot-tp3654300p3654666.html
Sent from the R help mailing list archive at
Command I am using for the plot:
plot(Raw[][Plate==101]~well[][Plate==101], xlab="Well", ylab="Raw",
main="Plate 101")
I only want to label points on the graph where well equals B13, G13, K14 and
N14 with the name of the well.
Thank you for your help.
--
View this message in context:
http://r.
On 08/07/2011 12:15 PM, UnitRoot wrote:
Hello,
I have tried to generate numbers randomly which follow normal, Student-t and
skewed Student-t distributions. However, when I check those series for
heteroscedastisity test (ARCH) results are showing that there is no
heteroscedastisity.
As we all know
ty S. Goslee,
It's helpfull to test the condition:
> all.equal(s[4],0.15)
[1] TRUE
instead the previous "FALSE" answer obtained with
>s[4]==0.15
[1] FALSE
but I still need get it to vector r:
Victor Delgado wrote:
>
>
>> for (w in 1:length(s)){
>> r[w] <- dados[,3][dados[,2]==s[w]][1]
>> }
Tried this and received this error:
Error in hist.default(x = integer(0), plot = FALSE) :
invalid number of 'breaks'
--
View this message in context:
http://r.789695.n4.nabble.com/Condional-Density-Plot-from-different-data-tp3080615p3654634.html
Sent from the R help mailing list archive at Na
Hello,
I have tried to generate numbers randomly which follow normal, Student-t and
skewed Student-t distributions. However, when I check those series for
heteroscedastisity test (ARCH) results are showing that there is no
heteroscedastisity.
As we all know, returns (financial returns) usually have
In Windows Vista, here is what I do:
Create a .bat file that calls R to run the script. Then set the task
scheduler to run the batch file. It's a round about way but it works
for me.
# begin example of *.bat file contents
cd C:\R\R-2.13.0\bin
R CMD BATCH "C:\MyBats\MyBat.R" "C:\MyBats\MyO
Hello Dan,
I reckon that you need to path a batch-file to the scheduler, i.e. something
along the lines
R CMD BATCH script.R
shall be included in, say, 'RBatchjob.bat' and this file shall then be called
by the task scheduler.
Best,
Bernhard
> -Ursprüngliche Nachricht-
> Von: r-he
Just to add onto Greg's comments, you may want to review this thread over on
MedStats, since this topic was just discussed extensively this week, initially
as a query about using LOS as a covariate:
http://groups.google.com/group/medstats/browse_thread/thread/f875fdeeaf48dc38?hl=en
It is hig
How are you measuring length of stay? A chi-square test suggests that you have
it categorized, a t-test assumes it is continuous (and relatively symmetric
with the amount depending on sample size).
Do you have any censoring? (patients dying or transferring before discharge) if
so you should lo
On Jul 8, 2011, at 10:55 AM, rstudent wrote:
I just started using R last week.
I have a dataset with 3 columns - Plate, Well and Raw
I need to make a simple plot(Well~Raw) but only when Plate = 101
?subset
# Some plotting paradigms allow you to use a subset = but
any program that had a
In case anyone else is interested... I just found another solution, which has
some pros and cons compared to Dennis' solution...
plot(comparePred(fit.lme, update(fit.lme, y ~ log(age
# Pros - Automatically adds a legend
# Cons - Only works for comparing two models
# Dennis' solution extends t
Are your users willing to install an Excel plug-in? If so, look at the RExcel
project, it does what you describe and the common user thinks they are just
using Excel with a plug-in without realizing that they have installed and are
using a useful tool in the background.
-Original Message--
Try
plot(Well~Raw, subset= Plate==101)
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of rstudent
Sent: Friday, July 08, 2011 8:56 AM
To: r-help@r-project.org
Subject: [R] Simple conditional plot
I just started using R last week.
Looks like FAQ 7.31 to me.
Try all.equal() instead of ==.
Sarah
On Fri, Jul 8, 2011 at 11:06 AM, VictorDelgado
wrote:
> Hi There,
>
> I'm facing one problem to construct a vector using the "for" command:
>
> I have one matrix named 'dados' (same as /data/ from portuguese), for
> example:
>
>> d
On Thu, Jul 7, 2011 at 6:07 PM, Gabor Grothendieck
wrote:
> On Thu, Jul 7, 2011 at 4:23 PM, Victor11 wrote:
>> Dear All,
>>
>> When I use read.xls() in gdata package to read xls files, I noticed an issue
>> and couldn't find any solutions after I serched all previous posts.
>>
>> In the excel fil
On Thu, Jul 07, 2011 at 02:18:17PM -0700, m.marcinmichal wrote:
> Hi,
> Currently I testing the packets that contain built-in features for
> classification. Actually I looked packages such as: e1071, Klar, Caret,
> CORElearn. However, from what I noticed when building a naive Bayesian
> classifier,
You can do:
as.numeric(charToRaw(paste(df[,4], collapse="")))
If you somehow want each row to be its own sequence of integers, you
could do something like:
lapply(df[,4], function(c) as.numeric(charToRaw(c)));
~Matthew Maycock
-Original Message-
From: r-help-boun...@r-project.org [m
Hi There,
I'm facing one problem to construct a vector using the "for" command:
I have one matrix named 'dados' (same as /data/ from portuguese), for
example:
> dados[140:150,]
[,1] [,2] [,3]
[1,] 212.7298 0.14 0.11
[2,] 213.3778 0.14 0.11
[3,] 214.0257 0.15 0.11
[4,] 214.6737 0.1
I just started using R last week.
I have a dataset with 3 columns - Plate, Well and Raw
I need to make a simple plot(Well~Raw) but only when Plate = 101
Thanks for your help.
--
View this message in context:
http://r.789695.n4.nabble.com/Simple-conditional-plot-tp3654300p3654300.html
Sent from
Hello all,
I'm trying to get a specific source file to run at a certain time each day with
WindowsScheduler
http://windows.microsoft.com/en-US/windows7/schedule-a-task
I've tried a number of methods, none of which work:
My best guess was:
1. Associate the script.R file with R in FileTypes.
2. Ca
On Fri, Jul 8, 2011 at 11:16 AM, Federico Calboli
wrote:
> On 8 Jul 2011, at 16:12, Barry Rowlingson wrote:
>
>> On Fri, Jul 8, 2011 at 4:07 PM, Federico Calboli
>> wrote:
>>> On 8 Jul 2011, at 15:56, Spencer Graves wrote:
> Ok, thanks for that. I though that, since R in under GPL-v2, I can o
On Fri, Jul 8, 2011 at 4:16 PM, Federico Calboli
wrote:
> The vast majority of CRAN libraries seem to be released under some sort of
> GPL version. I never seen a license though.
You're right. The GNU people say "should":
http://www.gnu.org/licenses/gpl-howto.html
---
You should also includ
On 08/07/2011 10:56 AM, Spencer Graves wrote:
On 7/8/2011 4:26 AM, Federico Calboli wrote:
> On 8 Jul 2011, at 12:06, Duncan Murdoch wrote:
>
>> On 11-07-08 6:20 AM, Federico Calboli wrote:
>>> HI All,
>>>
>>> I have written and succesfully uploaded a new package. The licence it is under is '
On 7/8/2011 8:07 AM, Federico Calboli wrote:
On 8 Jul 2011, at 15:56, Spencer Graves wrote:
Ok, thanks for that. I though that, since R in under GPL-v2, I
can only release my code under GPL-v2 because the code is written
in R and probably qualifies as a derivative work.
Did you include someone
On Jul 8, 2011, at 9:58 AM, Spencer Graves wrote:
> On 7/8/2011 4:26 AM, Federico Calboli wrote:
>> On 8 Jul 2011, at 12:06, Duncan Murdoch wrote:
>>
>>> On 11-07-08 6:20 AM, Federico Calboli wrote:
HI All,
I have written and succesfully uploaded a new package. The licence it is
On 8 Jul 2011, at 16:12, Barry Rowlingson wrote:
> On Fri, Jul 8, 2011 at 4:07 PM, Federico Calboli
> wrote:
>> On 8 Jul 2011, at 15:56, Spencer Graves wrote:
Ok, thanks for that. I though that, since R in under GPL-v2, I can only
release my code under GPL-v2 because the code is writte
On Fri, Jul 8, 2011 at 4:07 PM, Federico Calboli
wrote:
> On 8 Jul 2011, at 15:56, Spencer Graves wrote:
>>> Ok, thanks for that. I though that, since R in under GPL-v2, I can only
>>> release my code under GPL-v2 because the code is written in R and probably
>>> qualifies as a derivative work.
On 07/08/2011 07:58 AM, Spencer Graves wrote:
On 7/8/2011 4:26 AM, Federico Calboli wrote:
On 8 Jul 2011, at 12:06, Duncan Murdoch wrote:
On 11-07-08 6:20 AM, Federico Calboli wrote:
HI All,
I have written and succesfully uploaded a new package. The licence it
is under is 'GPL' --no version
On 8 Jul 2011, at 15:56, Spencer Graves wrote:
>> Ok, thanks for that. I though that, since R in under GPL-v2, I can only
>> release my code under GPL-v2 because the code is written in R and probably
>> qualifies as a derivative work.
>
> Did you include someone else's GPL-vx code (possibly
Thank you for your suggestion Gabor. I hope they can fix this in later
versions.
Victor
--
View this message in context:
http://r.789695.n4.nabble.com/gdata-read-xls-values-format-problem-tp3652494p3654334.html
Sent from the R help mailing list archive at Nabble.com.
___
On 7/8/2011 4:26 AM, Federico Calboli wrote:
On 8 Jul 2011, at 12:06, Duncan Murdoch wrote:
On 11-07-08 6:20 AM, Federico Calboli wrote:
HI All,
I have written and succesfully uploaded a new package. The licence it is under is 'GPL' --no
version. My assumption is, since all the code is writt
RSiteSearch("cross product")
library(pracma)
?cross
Speed is usually desired in the context of many similar computations, and is
normally achieved in R by vectorizing computation, so storing the large
number of 3d vectors together in a structure like a Nx3 matrix so the code
can be vectorized
Dear all,
I have a file and I am using a code-
df=read.table("Case2.pileup",fill=T,sep="\t",colClasses = "character")
to create a data frame that is df.
now in 4th column I have ASCII values which I want to convert in decimal
values.the data frame is like this-
V1 V2 V3
I'm using the mcexact function from the exactLoglinTest package on data
comparing performance of rapid and laboratory tests for detection of H1N1
flu. My setup is as follows:
ridt.res <- c("A-B-", "A+B-", "A-B+")
pcr.res <- c("Negative", "AH3", "B")
xtab <- expand.grid(ridt = ridt.res, pcr = pcr.
Hey Paolo,
you should specify las BEFORE you send the axis command.
It would also be good to set greater margins, this needs to be set before the
entire plot, thus in following order:
par(las = 3, mar=c(6,2,2,2))
plot(ExtAvgCWV, ann=FALSE, xaxt="n", yaxt="n" )
axis(side =1 , at = tickplaces, l
> -Original Message-
> [mailto:r-help-boun...@r-project.org] On Behalf Of francisco.ahued
> Subject: [R] Return invisible list
>
> x=read.table("data.txt",header=T)
> goa=(x[,3])
> meplot(goa)
>
> I can see the plot, but I would like to see the values of the
> x and y axis.
>
Somethin
Dear all,
I have encountered the following problem where coxme seems to allow
model with only random effect in R 2.11.1 but not in R 2.13.0. Following
is the error message using rat example data. Any comment on this is
appreciated.
In R2.13
> library(coxme)
> rat1 <- coxme(Surv(time, sta
Hi Berry,
True, it works. Thanks for this and teh general advice. I have been doing
things wrong from day 1 and never realised it!
Cheers,
Paolo
On 8 July 2011 13:43, Berry Boessenkool wrote:
>
>
> Hey Paolo,
>
> you should specify las BEFORE you send the axis command.
> It would also be good
Hey,
from what I see, you try to use the par(las=3) function after the plot
command. You should use it before it, though. Somewhat liek this:
ExtAvgCWV = rnorm(200)
ExtAvgDemand = rnorm(200)
ExtGasDays = seq(from = as.Date("2010-8-4", "%Y-%m-%d"), along.with =
ExtAvgCWV, by = "days")
op <- p
Hi,
how about this:
mm<-cbind(V1,V2)
xy<-sapply(1:3,function(x)det(mm[-x,])*(2*(x%%2)-1))
#some checks
all.equal(0,as.vector(xy%*%V1))
all.equal(0,as.vector(xy%*%V2))
Am 08.07.2011 08:27, schrieb Bai:
> Hi, everyone,
>
> I need an efficient way to do vectors cross product in R.
>
> Set vector
It is a warning: it will fall back to the version used in your
unstated version of R. Nothing you show justifies your claim
i can't install the packages
However, most likely you have a problem connecting to the internet at
all: see the FAQ relevant to your unstated OS or ask your local IT
Thank you! Exactly what I wanted.
Ramzi
--
View this message in context:
http://r.789695.n4.nabble.com/How-do-I-overlay-two-trellis-plots-of-lme-fitted-lines-produced-by-plot-augPred-tp3652204p3653988.html
Sent from the R help mailing list archive at Nabble.com.
Dear Prof. Therneau
I was impressed to discover that the 'survConcordance' now handles Surv()
objects in counting format (example below to clarify what I mean). This is not
documented in the help page for the function. I am very curious to see how a
c-index is estimated in this case, using jus
A little more specificity required; sample of the data, do you want
multiple plots each with a single variable, or do you want them all on
one plot as lines/areas/points/etc. Do you want then broken down by
year, month, or some other way. It is easy to generate plots once you
know what you want.
Hello,
I wonder if someone can elaborate on why in the first graph I am able to set
labels vertical to the x-axis but not in the second.
I tried to select the window but it didnt really help.
Many Thanks
Paolo
ExtAvgCWV = rnorm(200)
ExtAvgDemand = rnorm(200)
ExtGasDays = seq(from = as.Dat
i have option prices of 1 month option contract for several days in a csv
file. The data is in chronological order of dates. Within each date, price
quotes for each strike appears (about 30 strikes per month- so there are in
30 rows per day for many days and many months). i want only the quote on t
Dear list,
I am new to R and am using it to develop and test my own neural network
codes.
I need some training datasets that have the prediction results that
should (approximately) appear when the datasets are passed through a
good neural network, in order to test whether my code is working
ac
Hello all,
I am facing difficulty in deciding how to go about analysis of a situation
explained as follows:
I have two variables Y (response) and X (explanatory)
(There are several other potential candidate explanatory variables, but
right now I am looking at only one variable.)
Y is binary taki
Július 7-től 14-ig irodán kívül vagyok, és az emailjeimet nem érem el.
Sürgős esetben kérem forduljon Kárpáti Edithez (karpati.e...@gyemszi.hu).
Üdvözlettel,
Mihalicza Péter
I will be out of the office from 7 July till 14 July with no access to my
emails.
In urgent cases please contact Ms. Ed
Dear All,
I have several objects (imported from excel via using “xlsx”) with the field
names: Month/Year, X, Y1, Y2, Y3.
What is the best library/way to generate a graph which will be consist of
multiple plots (Month/Year) that each contain the X, Y1, Y2, Y3 dataset.
Thanks a lot.
Cheers,
Asher
Hi, everyone,
I need an efficient way to do vectors cross product in R.
Set vectors,
V1 = ai + bj + ck
V2 = di + ej + fk
then the cross product is
V1 x V2= (bf - ce) i + (cd - af) j + (ae - bd) k
As shown here ( http://en.wikipedia.org/wiki/Cross_product ).
Thanks.
Best,
Bai
Hi Jim,
Thanks for your response. I was actually thinking in terms of an executable
file which could return the output back to an excel sheet. I was thinking of
having a small script/executable which would read an excel file get the
values... Run the modelget the prediction and return t
Dear Sir,
When i am trying to set CRAN mirror to install packages, its showing the
following messages, i can't install the packages
> > > chooseCRANmirror()
Warning message:
In open.connection(con, "r") :
unable to connect to 'cran.r-project.org' on port 80.
Best regards
Mahmud
[[alt
Dear r users,
does anyone have a suggestion of a book on graph theory, which may help
designing the analysis of neuroimaging resting-states data?
Thanks,
Guilherme
[[alternative HTML version deleted]]
_
Not sure if I understand your problem completely.
If so, you could try to run an LDA on the x with y as classlabels
factor(rep(1:3, each=10)) and see if it can perfectly separate the classes.
Uwe Ligges
On 06.07.2011 17:31, Aparna Sampath wrote:
Hi All
This might be something very trivia
1 - 100 of 110 matches
Mail list logo
