Ok -let's forget about the dataframe.
Say, I have this (huge) spreadsheet that has some rows and columns, with
unique rownames and column names.
Using R, I wish to FINALLY have a spreadsheet where the values of the
first 10 rows remain in a single row. And, the values of the next 10 rows
remain i
## Dung observations
## Create a sample original data
data <- data.frame(Species=sample(c("W", "G", "R"), 200, replace=TRUE),
Age=sample(c("days", "weeks", "months"),200,replace=TRUE),
Termites=sample(c(0,1),200,replace=TRUE))
## Show what original data look like
head(data)
Spe
On Fri, May 21, 2010 at 11:27 AM, Mohan L wrote:
>
> Dear All,
>
> I have data some thing like this:
>
> > sample
> StateJan Feb Mar
> A 1 1 1
> B1298 12931294
> C00 0
> D55 5
> E 18 18
Dear All,
I have data some thing like this:
> sample
StateJan Feb Mar
A 1 1 1
B1298 12931294
C00 0
D55 5
E 18 18 18
I need to multiply "Jan" column *1000 and divided by the same num
Still not clear. Follow the posting guide and some examples always help.
Not sure how you "concatenate" numbers?
You can try, for example,
apply(df[1:10,], 2, paste, collapse=" ")
but this will turn everything into strings. Is this what you want?
..Tao
- Original Message
> Fr
it's a excellent solution. I am sorry I missed something in my question.
the column b consists of not only number but also one letter after "chr",
for example chrX, chrY. I want to put them after number but in the order of
ASCII.
i.e. chr1 wrote:
From: Jorge Ivan Velez
Subject: Re: [R] sort a da
Hi,
currently, i am a bit lost. i want to calculate the discriminative
power of items in my questionnaire. i have found the psych package
which should contain that sort of thing, but i cant find it in there.
by what name does it go? it probably does not help that i have got
onlygerman books on the
Hi David,
SORRY - I am trying to be more clearer this time.
Let's say the dataframe has some rows and columns, with unique rownames and
column names. The rest of the data in the dataframe are just numbers.
I wish to concatenate those rows. That means : I wish to concatenate first
10 rows' values
On May 20, 2010, at 11:05 PM, santana sarma wrote:
Hi,
I have a dataframe with some 800 rows and 14 columns.
Could you please advise how I can concatenate the rows - one after
another.
Similarly for columns, one below the other.
Not sure exactly what you are after:
unlist might accompl
Hi,
I have a dataframe with some 800 rows and 14 columns.
Could you please advise how I can concatenate the rows - one after another.
Similarly for columns, one below the other.
Many thanks.
Cheers,
Santana
[[alternative HTML version deleted]]
___
Hi Yuan,
One way would be:
dd[order(factor(substring(dd$b, 4), levels = c(1:22, LETTERS[1:25]))),]
HTH,
Jorge
On Thu, May 20, 2010 at 10:18 PM, Yuan Jian <> wrote:
> it's a excellent solution. I am sorry I missed something in my question.
> the column b consists of not only number but also on
Try this one liner. The first argument of rep is the sorted
intersection and the second argument is the calculated from the
parallel minimum of the counts of elements in a that are also in b and
the counts of elements in b that are also in a.
rep(sort(intersect(a, b)), pmin(table(a[a %in% b]), ta
On May 20, 2010, at 7:10 PM, David Winsemius wrote:
On May 20, 2010, at 6:24 PM, Jonathan wrote:
Thanks, but that doesn't quite work, since I'd want the result of
b[b %in% a] to be symmetric with a[a%in%b] (so if there are two 2's
in EACH vector, I'll get two 2's in the result, but if there
Amitoj S. Chopra gmail.com> writes:
>
>
> Hello to everyone.
>
> I am constructing a GUI table using traitr with multiple buttons that
> respond to different codes. Such as I am doing titration of a protein, and I
> want the script to run and then the end to be displayed in a window. The
> win
On May 20, 2010, at 7:30 PM, Nordlund, Dan (DSHS/RDA) wrote:
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
project.org] On Behalf Of Jonathan
Sent: Thursday, May 20, 2010 3:25 PM
To: David Winsemius
Cc: r-help
Subject: Re: [R] intersect() without discar
I hope this is what you want.
## Exclude replicated rows
(DF1 <- unique(DF))
## Sort the data
(DF2 <- DF1[order(DF1$V1, DF1$V2, DF1$V3, DF1$V4),])
-
A R learner.
--
View this message in context:
http://r.789695.n4.nabble.com/How-to-extract-rows-from-data-frame-based-on-unique-variable-gro
Thanks a lot! This has helped send me in the right direction. I'm not used
to think outside of the loop.
--
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Sent from the R help mailing list archive at Nabble.com.
Hello to everyone.
I am constructing a GUI table using traitr with multiple buttons that
respond to different codes. Such as I am doing titration of a protein, and I
want the script to run and then the end to be displayed in a window. The
window will have a button for data and graphs, where when
Hi:
To illustrate the idea of vectorization that the previous posters raised,
here's a quick example of finding the z-scores that you requested:
# Define a vectorized function to do the standardization - the argument
# x below is a vector. We'll keep it simple and ignore the possibility of
# miss
If you want to sort the data frame according to column "b", the
followding code does this work.
attach(dd)
dd<-dd[order(b),]
detach(dd)
If you want to sort the data frame according to the chr number in column
b, you should extract the numbers first into a vector, say chrnum, and
then use order
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of Jonathan
> Sent: Thursday, May 20, 2010 3:25 PM
> To: David Winsemius
> Cc: r-help
> Subject: Re: [R] intersect() without discarding duplicates?
>
> Thanks, but that doesn't quit
On May 20, 2010, at 6:24 PM, Jonathan wrote:
> Thanks, but that doesn't quite work, since I'd want the result of
> b[b %in% a] to be symmetric with a[a%in%b] (so if there are two 2's
> in EACH vector, I'll get two 2's in the result, but if there are two
> 2's in only one vector, but one two
Thanks, but that doesn't quite work, since I'd want the result of b[b %in%
a] to be symmetric with a[a%in%b] (so if there are two 2's in EACH vector,
I'll get two 2's in the result, but if there are two 2's in only one vector,
but one two in the other, the result will show only one 2.
Consider:
>
On May 20, 2010, at 4:42 PM, egc wrote:
> Greetings -
>
> While I've used R a fair bit for basic statistical machinations, I've
> not used it for data manipulation - I've used SAS for 20+ years (and
> SAS real shines in data handling). So, I've started the process of
> trying to figure out 'how t
On May 20, 2010, at 5:42 PM, egc wrote:
Greetings -
While I've used R a fair bit for basic statistical machinations, I've
not used it for data manipulation - I've used SAS for 20+ years (and
SAS real shines in data handling). So, I've started the process of
trying to figure out 'how to do in R
On May 20, 2010, at 5:58 PM, Jonathan wrote:
Hi all,
The ?intersect entry kindly points out that it discards duplicate
entries. I'm looking, however, to get the intersection while KEEPING
duplicate entries, and there are no instructions on how to
accomplish this
using intersect().
Does a
Hi all,
The ?intersect entry kindly points out that it discards duplicate
entries. I'm looking, however, to get the intersection while KEEPING
duplicate entries, and there are no instructions on how to accomplish this
using intersect().
Does anybody have any idea how this might be done, or am
Thank you for the suggestions, Peter and David!
- Original Message
> From: Peter Ehlers
> To: David Winsemius
> Cc: "Shi, Tao" ; r-help@r-project.org
> Sent: Wed, May 19, 2010 8:45:24 PM
> Subject: Re: [R] colored venn diagram
>
> Tao,
You might also have a look at the venneuler pa
Greetings -
While I've used R a fair bit for basic statistical machinations, I've
not used it for data manipulation - I've used SAS for 20+ years (and
SAS real shines in data handling). So, I've started the process of
trying to figure out 'how to do in R what I can do in my sleep in SAS'
- specifi
Is there a library dealing with correlation in the residuals of a glm?
I have
bin3alt <-glm(respalt~ t+sn+c5.vrm,data=dfalt,family="quasibinomial")
> bin3alt
Call: glm(formula = respalt ~ t + sn + c5.vrm, family = "quasibinomial",
data = dfalt)
Coefficients:
(Intercept) t2
On May 20, 2010, at 4:47 PM, David Winsemius wrote:
On May 20, 2010, at 4:44 PM, David Winsemius wrote:
On May 20, 2010, at 4:32 PM, David Winsemius wrote:
On May 20, 2010, at 11:24 AM, Sabatier, Jennifer F. (CDC/OID/
NCHHSTP) wrote:
Hi R-help,
I posted about this late yesterday bu
Try this:
x_long <- reshape(x, direction = 'long', varying = 2:4, sep = '', idvar =
'V1', timevar = 'V')
subset(x_long[order(x_long$V1),], V != "")
On Thu, May 20, 2010 at 2:13 PM, Mia Bengtsson wrote:
> Hello,
>
> I am a relatively new R-user who has a lot to learn. I have a large dataset
> tha
worked perfectly. kia ora! :)
On Thu, May 20, 2010 at 1:19 PM, Peter Alspach <
peter.alsp...@plantandfood.co.nz> wrote:
> Tena koe Anthony
>
> You could try:
>
> segments(rep(0,6), 2:7, rep(2.3, 6), 2:7)
>
> HTH ...
>
> Peter Alspach
>
> > -Original Message-
> > From: r-help-boun...@r-p
Here's another possibility:
> x <- c("Apple12","HP42","Dell91")
> strsplit(x,"(?<=\\D)(?=\\d)", perl=TRUE)
[[1]]
[1] "Apple" "12"
[[2]]
[1] "HP" "42"
[[3]]
[1] "Dell" "91"
Krishna Tateneni writes:
> Greetings,
>
> I have a vector of values that are a word followed by a number, e.g.,
## Create a function to assign a series of values to a list of objects
## The assign function can only assign one value (could be a vector) to a
name
## Set the environment to be global, otherwise the objects can't be used
outside the function
## List objects that have been created
toto <- functi
thanks! I figured there had to be an argument for it. I was surprised at
not seeing anything in par, but obviously didn't read closely enough.
thanks, and apologies
On Thu, May 20, 2010 at 1:23 PM, Allan Engelhardt wrote:
> Some variation around
>
> axis(2,at=2:7,lab=c("2","3","4","5","6","7"
On May 20, 2010, at 4:44 PM, David Winsemius wrote:
On May 20, 2010, at 4:32 PM, David Winsemius wrote:
On May 20, 2010, at 11:24 AM, Sabatier, Jennifer F. (CDC/OID/
NCHHSTP) wrote:
Hi R-help,
I posted about this late yesterday but got no response. I may have
put
TMI in the original
On May 20, 2010, at 4:32 PM, David Winsemius wrote:
On May 20, 2010, at 11:24 AM, Sabatier, Jennifer F. (CDC/OID/
NCHHSTP) wrote:
Hi R-help,
I posted about this late yesterday but got no response. I may have
put
TMI in the original request. Not to mention I couldn't cut and paste
yes
On 2010-05-20, at 2:38 PM, Anthony Lopez wrote:
> Is there an easier way to make this graph *without* having to specify all of
> the separate segment arguments at the end?
> ...
> axis(2,at=2:7,lab=c("2","3","4","5","6","7"))
> segments(0,2,2.3,2)
> segments(0,3,2.3,3)
> segments(0,4,2.3,4)
> segm
On May 20, 2010, at 11:24 AM, Sabatier, Jennifer F. (CDC/OID/NCHHSTP)
wrote:
Hi R-help,
I posted about this late yesterday but got no response. I may have put
TMI in the original request. Not to mention I couldn't cut and paste
yesterday because I was working R off a non-network computer
Some variation around
axis(2,at=2:7,lab=c("2","3","4","5","6","7"), tck=1)
should do it? See tck in help("par").
Hope this helps.
Allan.
On 20/05/10 18:38, Anthony Lopez wrote:
Is there an easier way to make this graph *without* having to specify all of
the separate segment arguments at the
Tena koe Mike
duplicated() might be what you require.
HTH ...
Peter Alspach
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of Michael H
> Sent: Friday, 21 May 2010 6:37 a.m.
> To: r-help@r-project.org
> Subject: [R] How to ex
On 5/20/2010 9:59 AM, Julian Burgos wrote:
Hi Jim
I´m using R 2.11.0, on Windows XP.
For what it is worth, it works fine for me, too. R 2.11.0 on Windows XP
Pro. My gut instinct is to check that time3 and time4 are really what
you think they are. If that is not it, post the results of dpu
format(1.4, nsmall=2)
Rich
[[alternative HTML version deleted]]
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented
Tena koe Anthony
You could try:
segments(rep(0,6), 2:7, rep(2.3, 6), 2:7)
HTH ...
Peter Alspach
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of Anthony Lopez
> Sent: Friday, 21 May 2010 5:39 a.m.
> To: R-help@r-project.org
Dear R-Help members,
We're looking for a consultant with expertise in *R *and *UNIX*. Could it be
you or someone you know?
We're trying to fill the gap of a consultant who recently left our group and
who wrote some code in need of revision. It would be a paying job
(negotiable) and one that I bel
R community,
I would like to know how to extract rows from a data frame (DF) such that
each row in the new data frame (D.F) represents the first instance of
a unique variable pairing in the original dataframe (ordered first by
variable V1 then by variable V2). The unique function does not se
Hello,
I am a relatively new R-user who has a lot to learn. I have a large dataset
that is in the following dataframe format:
red A B C
green D
blueE F
Where red, green and blue are "species" names and A, B and C are observations
(corresponding to DNA sequen
I've looked through all of the posts about this issue (and there are
plenty!) but I am still unable to solve the error. ERROR: cannot allocate
vector of size 455 Mb
I am using R 2.6.2 - x86_64 on a Linux x86_64 Redhat cluster system. When I
log in, based on the specs I provide [qsub -I -X -l arch
Hi there,
I've a very simple R code:
library(foreign)
library(R2HTML)
a<-read.xport("D:\\Inetpub\\wwwroot\\Rscript\\class.xpt")
HTML(a,"D:\\Inetpub\\wwwroot\\Rscript\\class.html")
When I run it interactive or in batch, I get the class.html file. Everything
looks fine. But once it is used in my
Is there an easier way to make this graph *without* having to specify all of
the separate segment arguments at the end?
> x <- c(1,2)
> off <- c(4,5.5)
> def <- c(5.5,5.9)
> par(fg="lightblue4")
>
plot(x,off,type="o",col="dodgerblue4",ylim=c(2,7),xlim=c(0.7,2.3),axes=F,xlab="Labor
Condition",ylab=
Hi Gavin, Steve
Tons and tons of Thanks! This solved my problem. My sample data differed
from the original working testdata in the factor levels. Once I set the
levels using the command given by Gavin, things started working like
magic.
Hurray!
I learned a great deal from you'll. Thank You for h
I'm not sure that this is the problem, but are you certain that the variable
'con' is in audit ? You check outside the function just really tells you
that X and SEX are in audit.
hth, david freedman (good to see another CDCer using R)
--
View this message in context:
http://r.789695.n4.nabble.
Try this:
sprintf('%.2f', 1.4)
On Thu, May 20, 2010 at 4:58 PM, Paul wrote:
> Hello.
>
> In my opinion the function
>
> signif(1.4,digits=3)
>
> should give 1.40
>
> but actually gives 1.4. Is there a magic way to add the trailing digits
> back (and converting to chracter at the same time ?)
>
Hello.
In my opinion the function
signif(1.4,digits=3)
should give 1.40
but actually gives 1.4. Is there a magic way to add the trailing digits
back (and converting to chracter at the same time ?)
Regards,
Paul.
__
R-help@r-project.org mailing
On 20-May-10 19:29:31, Jonathan wrote:
> Hi all,
> I'm hoping this question has a simple answer, but I can't find it
> through searching or trying commands.
>
> I have a list of numeric vectors called 'husk'. I'd just like to
> treat the set of all numbers from all vectors in the list as if
> it w
Hello Jonathan,
Look at ?sapply Does something like this do what you want?
max(sapply(yourlist, max))
Josh
On Thu, May 20, 2010 at 12:29 PM, Jonathan wrote:
> Hi all,
> I'm hoping this question has a simple answer, but I can't find it through
> searching or trying commands.
>
> I have a li
You have a list that you want to treat as a vector, so ?unlist it.
Jonathan wrote:
Hi all,
I'm hoping this question has a simple answer, but I can't find it through
searching or trying commands.
I have a list of numeric vectors called 'husk'. I'd just like to treat the
set of all numbers fr
I think you want unlist with recursive = TRUE, see ?unlist. Bryan
*
Bryan Hanson
Acting Chair
Professor of Chemistry & Biochemistry
DePauw University, Greencastle IN USA
On 5/20/10 3:29 PM, "Jonathan" wrote:
> Hi all,
>I'm hoping this question has a simple answer, but I can't
Hi all,
I'm hoping this question has a simple answer, but I can't find it through
searching or trying commands.
I have a list of numeric vectors called 'husk'. I'd just like to treat the
set of all numbers from all vectors in the list as if it were one large
vector, because I'd like to extract
Hello,
I am guessing by my environment you mean the global environment (where
you normally assign things from the console). It also looks like you
would like the results of your function call to be a set of new
objects created. If that is what you are looking for, try:
toto <- function(x,y) {
f
Hi Tal,
You're probably right, but I think it's never a waste to get diverse solutions
:)
Cheers,
Ivan
Le 20 mai 2010 à 19:26, Tal Galili a écrit :
> Hi Ivan,
>
> I am not sure if the poster (arnaud) intended for a list() object (although
> that's what he wrote, I suspect he intended for a
Hi there,
I just installed the package under windows, and it works very well. However, as
I tried to install it on a cluster which uses linux OS,
"Linux lionxc.aset.psu.edu 2.6.18-194.el5 #1 SMP Tue Mar 16 21:52:39 EDT 2010
x86_64 x86_64 x86_64 GNU/Linux"
I always failed. The message during
They work on any join that is able to make use of them. If you
preface the select statement with explain query plan then it will give
you some info, e.g.
> sqldf('explain query plan select * from main.A natural join main.B')
order from detail
1 00 TABLE
Thomas Stewart gmail.com> writes:
> If I have the mixed-model with
>
> lmer( y ~ x1 + x2 + (1 | id) + (z1 | w ) , ... )
>
> there is no way for me to specify a correlation structure for the random
> effects? Right?
>
> If I want to specify correlation structure then I need to use lme in the
>
For posterity, this thread was continued on the R-SIG-Mac mailing list
under the same subject. Prof. Brian Ripley was kind enough to point
out an easy work around:
R CMD INSTALL now uses the internal untar() in package utils:
this ensures that all platforms can install bzip2- and
xz-compressed tar
Thank you very much for these clarifying responses, Gabor.
I had mistakenly assumed that creating the index on Tid restricted the
natural join to joining on Tid. Can you describe when and how indices speed
up joins, or can you point me to resources that address this? Is it only for
natural joins o
I have an existing table, and I am trying to use sqlSave to append
additional rows to this database. I omit the primary key, which is a
uniqueidentifier type (MS SQL), so that the database can populate that
field. However, I get the following error:
> sqlSave( ch, result, tablename=thetable
Hi,
>
>I am trying to describe a data.frame by obtaining multiple crosstable summary
>statistics at once. I have tried table, xtab, crosstable, summaryBy and
>describe but none of these functions seems to allow muliple conparisons at
>once.
> Here, is what I would like to do:
>
>I have, for in
Hi Jim
I´m using R 2.11.0, on Windows XP.
On Thu, May 20, 2010 at 4:55 PM, jim holtman wrote:
> Please provide information as to what version you are using; works fine
> for me:
>
> > time3=strptime("2009 06 01 00 47 00",format="%Y %m %d %H %M")
> > time4=strptime("2009 06 01 00 57 00",format=
Please provide information as to what version you are using; works fine for me:
> time3=strptime("2009 06 01 00 47 00",format="%Y %m %d %H %M")
> time4=strptime("2009 06 01 00 57 00",format="%Y %m %d %H %M")
>
> diff(c(time3,time4))
Time difference of 10 mins
>
I have version 2.10.1
On Thu, May
I know this was asked and answered in 2005, I just want to make sure the
answer still holds in 2010.
Question:
If I have the mixed-model with
lmer( y ~ x1 + x2 + (1 | id) + (z1 | w ) , ... )
there is no way for me to specify a correlation structure for the random
effects? Right?
If I want to s
Although that works I had meant to write:
> names(B)[2] <- "dfNameB"
> # ... other commands
> sqldf('select * from main.A natural join main.B')
so that now only Tid is in common so the natural join just picks it up
and also the heuristic works again since we no longer retrieve
duplicate column na
We've scheduled more R courses for June 2010 in Washington DC,
San Francisco, Seattle, New York City and other USA cities
http://www.xlsolutions-corp.com/Rcourses
May - June 2010
*** R/S: Programming Essentials
*** R Fundamentals and Programming Techniques
*** R/S-PLUS Functions by Example
*** R
Dear list,
I´m calculating time differences between series of time stamps and I noticed
something odd:
If I do this...
> time1=strptime("2009 05 31 22 57 00",format="%Y %m %d %H %M")
> time2=strptime("2009 05 31 23 07 00",format="%Y %m %d %H %M")
>
> diff(c(time1,time2),units="mins")
Time differ
Dne Čt 20. května 2010 17:50:42 Luc Villandre napsal(a):
> Dear R-users,
>
> I've recently switched to Ubuntu and I've decided to use Kate to edit my
> R code. I really like how Kate allows one to simply pipe their code to
> the terminal. However, I would find it even better if I could actually
>
On May 20, 2010, at 11:08 AM, Stella Pachidi wrote:
> Dear R experts,
>
> I have a question about the result of difftime() function: Does it
> take into account the different number of days in each month. In my
> example, I have the following:
>
>> firstDay
> [1] "2010-02-20"
>> lastDay
> [1] "2
There are two problems:
1. A natural join will join all columns with the same names in the two
tables and that includes not only Tid but also dfName and since there
are no rows that have the same Tid and dfName the result has zero
rows.
2. the heuristic it uses fails when you retrieve the same co
The "breakpoint" you mentioned is irrelevant here. Clustering 15672
genes (I assume this is a microarray data) requires lots of memory. I
suggest you either filter your gene list down to thousands or just plot
the column dendrogram without showing the heatmap.
plot(hclust(dist(x)))
...Tao
Hi,
the problem is not about the environment, but about the
paste(c("tot", i), collapse = "")
which is not recognized as an object.
Maybe assign() could do the trick
You could also do it this way (though it's not exactly what you want,
but it might be better):
toto <- function(x,y){
tot
On May 20, 2010, at 11:12 AM, Alexander Shenkin wrote:
On 5/20/2010 9:18 AM, David Winsemius wrote:
On May 20, 2010, at 10:02 AM, Alexander Shenkin wrote:
Hello all,
I've been pouring through the various spatial packages, but
haven't come
across the right thing yet.
There is a SIG for
On 2010-05-20 08:52, Shi, Tao wrote:
Will,
I'm wondering if you have any
insights after looking at the cor.test source code. It seems to be fine to me, as the p
value is either calculated by "your first method" or a
.C code.
...Tao
Dear Tao,
I think the described problem of p-values < 2.
Dear R experts,
I have a question about the result of difftime() function: Does it
take into account the different number of days in each month. In my
example, I have the following:
> firstDay
[1] "2010-02-20"
> lastDay
[1] "2010-05-20 16:00:00"
> difftime(lastDay,firstDay,units='days')
Time diff
this is self-reply only to insert my real name
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Hello,
I'm having trouble discovering what's going wrong with my use of natural
joins via sqldf.
Following the instructions under 4i at http://code.google.com/p/sqldf/,
which discusses creating indices to speed joins, I have been only unreliably
able to get natural joins to work.
For example,
>
On Thu, 20 May 2010, ivo welch wrote:
hi thomas---
thanks for the answer. the problem with the "+factor(fmid)" is not just
that it provides uninteresting coefficients and that it eats more memory,
but that it is also MUCH slower when there are (hundred of) thousands of
fixed effects.
There i
Try this:
paste("tot", 4:16, sep = "")
Or:
func <- function(x,y)
{
paste("tot", x:y, sep = "")
}
func(4,16)
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.b
Dear group,
I am trying to write functions, but as a beginner, everything is not so
obvious.
Let's say I want the results in a list of elemts like this :
tot1, tot2, etc
Here is a function:
toto <-
function(x,y)
{
for(i in x:y){
paste(c("tot",i),collapse="")<-(i*2)
}
}
If I type this :
>to
On Thu, May 20, 2010 at 3:20 PM, Lucia Rueda wrote:
>
> Hi,
>
> Thanks for the inputs. I talked to my coworker, who has been the one doing
> the analysis. Perhaps I wasn't making myself clear about the differences
> in
> spatial scales. Here is what he says:
>
> "The truth is that measuring sc
Dear R-users,
I've recently switched to Ubuntu and I've decided to use Kate to edit my
R code. I really like how Kate allows one to simply pipe their code to
the terminal. However, I would find it even better if I could actually
get the Kate console to display error messages (or any console ou
kaveh vakili ulb.ac.be> writes:
>
> Dear List,
>
> I'd like to call pyhton function from within R. I tried installing the latest
> version of RSPython:
>
> wget http://www.omegahat.org/RSPython/RSPython_0.7-1.tar.gz
> R CMD INSTALL --clean RSPython_0.7-1.tar.gz
>
> I get a compile error (po
hi thomas---
thanks for the answer. the problem with the "+factor(fmid)" is not just
that it provides uninteresting coefficients and that it eats more memory,
but that it is also MUCH slower when there are (hundred of) thousands of
fixed effects.
Does Bill Venables describe how to do extend the
Dear R-Experts, Dear friends of dung.
I have a statistical Problem, to which nobody I asked could give me an answer.
Maybe you can.
I was in the African-Savanna and made a Dung-Monitoring. This means I walked
randomly over the field and for every Dung-Event I found I noted following
parameters
Dear List,
I'd like to call pyhton function from within R. I tried installing the latest
version of RSPython:
wget http://www.omegahat.org/RSPython/RSPython_0.7-1.tar.gz
R CMD INSTALL --clean RSPython_0.7-1.tar.gz
I get a compile error (posted below).
Did anyone else run against this ? Is the
On Thu, 20 May 2010, ivo welch wrote:
dear R wizards:
not important. more a curiosity or esthetics question.
is there a way to extend the standard lm command, so that it takes a new
argument that handles fixed effects? right now, I have (provided to me
from an expert---I would have never fi
Hi R-help,
I posted about this late yesterday but got no response. I may have put
TMI in the original request. Not to mention I couldn't cut and paste
yesterday because I was working R off a non-network computer while
asking for help on a network computer.
Essentially, I have this user-define
On Wed, 19 May 2010, Sabatier, Jennifer F. (CDC/OID/NCHHSTP) wrote:
Hi R-help,
Yes, this is my second request for assistance in a single day
I am attempting to use svychisq() inside a function I made. The goal
of this function is to produce a table of summary statistics that I can
later
Try, ofr a factor:
> x <-c("A","B","C")
> x <- factor(x)
> levels(x)
[1] "A" "B" "C"
> x <- factor(x,levels=levels(x)[c(3,2,1)])
> levels(x)
[1] "C" "B" "A"
Rock, DRF
--
View this message in context:
http://r.789695.n4.nabble.com/factor-tp879983p2224639.html
Sent from the R help mailing list a
Hi,
Thanks for the inputs. I talked to my coworker, who has been the one doing
the analysis. Perhaps I wasn't making myself clear about the “differences in
spatial scales”. Here is what he says:
"The truth is that measuring scales (i.e all area related variable are
measured in m2) and spatial d
Hello,
Let's say that I have a data frame of n numbers I want to transfer
into a Excel spreadsheet. I have opened the conection to the file
using ODBC, and I can query the content of these n cells without
problem. However, how do I transfer my new values to these cells?
I.e., overwite them.
Shoul
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