Hi everyone. I am new to R.
It will be greatly appreciated if someone can help me with the following
questions.
Here's the graph I have just produced.
http://www.nabble.com/file/p24732839/calibration.jpeg
(1) How can I put the legend on top of the grid lines?
(2) How can I match the grid lin
Yes thank you, as far as I understood your proposal it would lead to a similar
result. Is there a good package in order to do principal component analysis?
Best wishes,
Luba
Von: Andreas Hary [mailto:andreash...@googlemail.com]
Gesendet: Mittwoch, 29. Juli 20
Many thanks to you and all others for solutions together with regular
expressions insights.
Petr
"Chuck Taylor" napsal dne 29.07.2009 19:45:10:
> Petr,
>
> Here is a different approach. It, in effect, works from the end of the
> string backwards, rather than from the beginning of the string f
From the help:
Not all modes are applicable to all connections: for example URLs
can only be opened for reading.
You omitted to tell us your platform (and requests to include that and
not send HTML mail are in the posting guide), and pipe() differs by
platform. But AFAIR pipe() is
Dear Samanta,
Take a look at ?scale.
HTH,
Jorge
On Thu, Jul 30, 2009 at 12:52 AM, Sam wrote:
> Hi,
> this is probably a very basic question but I'm just learning R and i
> cannot find a function to standardize a data matrix..
> I'll be grateful for any tips or help you can provide me.
>
> T
Did you mean this:
> m <- matrix(1:12, 3, 4)
> m / max(m)
[,1] [,2] [,3] [,4]
[1,] 0.0833 0.333 0.583 0.833
[2,] 0.1667 0.417 0.667 0.917
[3,] 0.2500 0.500 0.750 1.000
On Thu, Jul 30, 2009 at 12:52 PM, Sam wrote:
> Hi,
> th
scale?
This transforms the columns of a matrix to z-scores. That's one kind of
standardisation.
Bill Venables
http://www.cmis.csiro.au/bill.venables/
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Sam
Sent: Thursday, 30
Hi,
this is probably a very basic question but I'm just learning R and i
cannot find a function to standardize a data matrix..
I'll be grateful for any tips or help you can provide me.
Thank you very much!
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https://s
Gabor Grothendieck wrote:
>
> Try this:
>
> z <- x * y[row(x) + col(x)]
>
Thanks! yes, that's the ticket.
In testing out your solution, I noticed I described my problem wrongly.
Apologies to anyone I confused.
So a clarification for anyone trying to follow this:
The index for y should h
I take it you mean
z[i,j] = x[i,j]*y[i+j-1]
(as you had it z[1,1] = x[1,1]*y[2], whereas your example suggests is should be
y[1])
Here is a suggestion:
> z <- x * y[outer(1:nrow(x), 1:ncol(x), "+")-1]
> z
[,1] [,2] [,3]
[1,] 35.20 63.22 17.28
[2,] 50.14 64.80NA
[3,] 22.68 34.98 10.
Your 'newdata' is a vector. To us predict() the newdata supplied must be a
data frame, with components having the same names as the predictors used in the
model. If some of the variables are factors, then the corresponding factors in
the newdata data frame must have the same names and the same
Try this:
z <- x * y[row(x) + col(x)]
z2 <- x
for(i in 1:nr) for(j in 1:nc) z2[i,j] <- x[i,j] * y[i+j]
all.equal(z, z2) # TRUE
On Wed, Jul 29, 2009 at 11:56 PM, glen_b wrote:
>
>
> For the life of me I couldn't work out what to searc
>
> I have an m*n numeric matrix x and a numeric vector y (
> x <-
+ matrix(c(1239,10,10,10,10,1234,10,10,10,10,1500,11,11,11,11,1001,11,11,11,11,
+
+ 1009,11,11,11,11,1344,12,12,12,12,1349,12,12,12,12,1458,13,13,13,13),8,5,byrow
+ = T)
> x
[,1] [,2] [,3] [,4] [,5]
[1,] 1239 10 10 10 10
[2,] 1234 10 10 10 10
[3,] 1500 11
For the life of me I couldn't work out what to searc
I have an m*n numeric matrix x and a numeric vector y (of length m+n-1)
How do I do a calculation like this?
z[i,j] = x[i,j] * y[i+j] ?
Well, one can write a pair of loops, or write a single loop
within which we calculate a vector at a ti
Hi,
On Jul 29, 2009, at 9:38 PM, Stella Sim wrote:
Dear list,
I would like to fit a wavelet SVM model. Where can I find a wavelet
kernel function? Thanks in advance.
I reckon you might have to implement that one yourself.
It seems like this MATLAB SVM toolbox has a version of them:
http://
Try this:
> bargin$stuffnew<-bargin$stuff[bargin$stuff != "very.high", drop=TRUE]
> bargin$stuffnew
[1] lowmiddle lowlowlowlowmiddle lowmiddle
middle middle middle middle high
[15] high lowmiddle middle lowhigh
Levels: low middle high
>
On Wed, Jul 29, 2009 at
Dear list,
I would like to fit a wavelet SVM model. Where can I find a wavelet
kernel function? Thanks in advance.
Stella Sim
DISCLAIMER:\ This email contains confidential informatio...{{dropped:11}}
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https://stat.
Instantaneous Data, mean flow data could be a start. That would be
wonderful if you would send it to me.
Stephen Sefick
On Wed, Jul 29, 2009 at 8:20 PM, wrote:
> Stephen,
>
> I don't have anything or know of anything in R to do this. But, we download
> USGS streamflow data routinely. I have a
Stephen,
I don't have anything or know of anything in R to do this. But, we download
USGS streamflow data routinely. I have a Perl script that will reformat the
downloaded data into a R-importable format (basically two columns date/time
flow value). Are you interested in mean daily or instantan
I don't even know if this is the right place to ask this question. I
would like to download USGS stream gauging data for a couple of gauges
on a daily basis- save the files to .csv files and append the nest
days time series to this. Is there a way to do this automatically in
R?
thanks,
--
Steph
I don't even know if this is the right place to ask this question. I
would like to download USGS stream gauging data for a couple of gauges
on a daily basis- save the files to .csv files and append the nest
days time series to this. Is there a way to do this automatically in
R?
thanks,
--
Steph
Dear fellow R users,
I would very much like to see an example of read/write connection (open =
"r+" ) for e.g. pipe() or any other R connection.
I have a standalone program which accepts input from stdin, performs some
processing and returns the results on stdout. Is it possible at all to open
a co
Code is provided below.
I was trying to follow the example at the following website:
http://www.ats.ucla.edu/stat/R/modules/factor_variables.htm
Only difference is that I am working with trying to remove a level from a
dataframe. In the example below, notice that "very.high" is still a level in
Hi all
Another question related to my earlier -- how might I get transparency to work
with pyramid.plot in library(plotrix)? I can't figure it out, and the help
page
says it is there but doesn't give an example.
Thanks!
__
R-help@r-project.org mail
>
> library(RODBC)
> library(HYDAT)
> You will need to install HYDAT (the zip file) from
> http://www.geog.ubc.ca/~rdmoore/Rcode.htm
>
> Below is my current code - which works. The [[]] is the way i am accessing
> the columns from the data frame.
>
> thanks again for all your help
>
> # load HY
Hi R-ers
Does anyone know how if there is a way to force pyramid plot where
you determine the bottom axis range? I want to compare many
different pyramids, so I am hoping to force the bottom axis range
from 0% to 10%.
Here is the code so far, if it matters:
mk.pyr = function(data, pumas=NULL,
I do not know if this message got through or not, but please disregard it!
Thanks!
On Wed, Jul 29, 2009 at 2:57 PM, Mehdi Khan wrote:
> Hello everyone,
>
> I have two data frames. One is a vector about 780 rows long consisting of
> lat long data of 780 station locations. The other table was pr
Hi,
I saw that tsdiag function doesn't provide a correct result for Ljung-Box
test. I want to use Box.test function for this, but I don't know how to
determine lag parameter for this function.
For fitdf, as I'm using a SARIMA model (0,1,1)(0,1,1)12, I decided to set it
to 2.
Can you confirm me
Hello All,
I am trying to estimate a generalized linear model using a single dummy
variable (bilat). I want to use contr.sum, in which (please correct me if I
am wrong) the implicit coefficient on the contrast equals the negative of
the sum of all estimated coefficients.
I cannot get the contra
Hello. I'm currently stuck with the same "what does interaction.depth really
mean" stuff. Did you find out what the right answer is?
Best regards,
Boris Yangel.
[[alternative HTML version deleted]]
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h
Hi,
I'm working on a multivariate ARIMA model. I have 2 time series and found
for each an ARIMA model
I'd like to know how are calculated the residuals of my arima model using
residuals() function in R ?
Is it as I think predicted values (from ARIMA model) - observed values ?
Is it relevant to
Hello everyone,
I have two data frames. One is a vector about 780 rows long consisting of
lat long data of 780 station locations. The other table was previously a
shape file which I have converted into a data frame object of lat long
coordinates and attribute data. What I want to do is combine
I think your data is set up incorrectly.
With your data below as "xx" try this.
# Dotcharts are often better than barplots so you might want to
# try this
library(reshape)
mm <- melt(xx, id=c(1:2)); mm
bb <- as.matrix(cast(mm,
Hi dear R help group.
I was wondering how can I find out which CRAN mirror would be the fastest
for me (I leave in Israel and therefore don't have a CRAN mirror for our
country to go to by default)
Thanks,
Tal
--
--
My contact information:
Ta
To test two environments for object equality (Lisp EQ), I can use 'identity':
> e1 <- environment(local(function()x))
> e2 <- environment(local(function()x))
> identical(e1,e2) # compares object identity
[1] FALSE
> identical(as.list(e1),as.list(e2))# compares values as na
Ken-JP wrote:
>
> Is there a way to modify this code to generate RED numbers inside xtable
> for
> negative results in x.ts?
>
This post would probably have been better for R-help. Anyway, you can do it
easily by modifying print.xtable.R in the xtable package. If it is easier,
make a copy o
On Wed, 29-Jul-2009 at 10:29AM +0200, Patrick Schorderet wrote:
>
> Hello everybody,
>
> I'm a newbie in R and just went through an introduction class recently.
Did you get the distinction between a vector and a dataframe?
>
> Here's my problem.
> I have 2 text files (.txt) with plain numbers
On Wed, 29-Jul-2009 at 06:15AM -0700, Bogaso wrote:
|>
|> Hi,
|>
|> I am working with multiple R-windows opened and would like to
|> transport some variables from one to another. Is there any direct
|> way to do this without saving them in hard-disk?
With so little information given, I can't t
Hello -
I am just beginning to look into R Programming and have written some basic R
code. Do you know of anyone in the Boston-USA area that might be offering any
courses on R Programming? Or possibly a course online?
Many thanks
Mike Boucher
Michael Boucher | Quantitative Analyst -
Don't leave us hanging! What is it?
--- On Wed, 7/29/09, Don MacQueen wrote:
> From: Don MacQueen
> Subject: Re: [R] Package with function for plots with embedded hyperlinks?
> To: r-help@r-project.org
> Received: Wednesday, July 29, 2009, 11:43 AM
> Never mind, just after I sent this I
> fi
library(RODBC)
library(HYDAT)
You will need to install HYDAT (the zip file) from
http://www.geog.ubc.ca/~rdmoore/Rcode.htm
Below is my current code - which works. The [[]] is the way i am accessing
the columns from the data frame.
thanks again for all your help
# load HYDAT data
par(mfrow
Well the MASS package is support for a book, the details for most of functions
in the package are detailed in the book, so if you really want to know, either
look at the code, or read the book.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
Hi Brindha
Does this answer your question:
http://onertipaday.blogspot.com/2007/05/make-many-barplot-into-one-plot.html
?
Cheers,
Tal
On Wed, Jul 29, 2009 at 8:48 PM, Brindha Selvaraj wrote:
> Hi,
>
> Many apologies for sending this twice. I accidentally hit the send button
> before I finishe
In the useR 2009 conference there was a lecture on how to use bigmemory to
create and object (a matrix I guess) - and then be able to access it from
two R sessions.
Consider searching for that :)
Tal
On Wed, Jul 29, 2009 at 4:15 PM, Bogaso wrote:
>
> Hi,
>
> I am working with multiple R-
log.raw.data <- log(raw.data[,2:10]) I think but I don't understand the "Data
has the first row for variable name" comment
--- On Wed, 7/29/09, sandsky wrote:
> From: sandsky
> Subject: [R] how to skip a numeric column for averaging other columns?
> To: r-help@r-project.org
> Received: We
Hi,
On Jul 29, 2009, at 3:02 PM, sandsky wrote:
Data has the first row for variable name and the first column for
sample
name. I want to take "Log" for all data, but how to compute without
the
first column for sample name.
That is,
column 1: sample ID
column 2-10: data
I think one thi
Dear All,
I wonder which function in MASS library calculates and output the
standard error of median.
Thank you in advance for your help
Lisa Wang
Biostatistics, Princess Margaret hospital,
toronto, On
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R-help@r-project.org mailing list
https://st
Thanks everyone!
It works now :)
Cheers,
a.
ONKELINX, Thierry wrote:
>
> Dear Angela,
>
> lme() is a part of the nlme package. The lme4 package has the function
> lmer() which is the equivalent of lme() from nlme. Both function differ
> in their capabilities. Briefly: lmer() can (easly) do
Petr,
Here is a different approach. It, in effect, works from the end of the
string backwards, rather than from the beginning of the string forwards.
substring(x, regexpr("[0-9]+$", x))
The regular expression "[0-9]+$" finds a string of 1 or more ("+")
digits ("[0-9]") followed by the end of
I wrote simple function to copy data from/to excel using the clipboard.
These should also work from one window to the next:
# To read from clipboard
"fromExcel" <- function() {read.table("clipboard-128", header=TRUE,
sep="\t")}
"toExcel" <- function(x) {write.table(x, "clipboard-128", sep="\t",
ro
Hello all,
I wonder which function in MASS library is calculating the standard
error of median?
thank you very much in advance,
Lisa
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PLEASE do read the posting guide htt
Data has the first row for variable name and the first column for sample
name. I want to take "Log" for all data, but how to compute without the
first column for sample name.
> log.raw_data=log(raw_data,base=2)
Error in Math.data.frame(list(sample_id = c(1L, 2L, 3L, 4L, 5L, 6L, 7L, :
non-nume
Hi,
Many apologies for sending this twice. I accidentally hit the send
button before I finished writing my mail. I am new to R and I hope
someone can help me with my problem. I am trying to draw a side by side
barplot.
There is a main experiment and there are many sub experiments within
Hi,
I'm switch over from RapidMiner to R. (The learning curve is steep, but
there is so much more I can do with R and it runs much faster overall.)
In RapidMiner, I can "tune" a parameter of my svm in a nice cross
validation loop. The process will print out the progress as it goes.
So for
Dear all,
Here is a little coding problem. It falls in the category of "how can I do
this efficiently?" rather than "how can I do this?" (I know how to do it
inefficiently). So, if you want to take the challenge, keep reading, otherwise
just skip to the next post - I won't be offended by that ;-
Jim-
That did the trick- thanks so much for taking the time to help me out.
Sincerely,
Ian Chidister
On Wed, Jul 29, 2009 at 11:57 AM, Ian Chidister wrote:
> Dear List,
>
> I'm an [R] novice starting analysis of an ecological dataset containing the
> basal areas of different tree species in a
Or even easier:
tapply(Trees$SppID, Trees$PlotID, function(x) length(unique(na.omit(x
On Wed, Jul 29, 2009 at 2:13 PM, Ian Chidister wrote:
> Hi All-
>
> Thanks for your quick responses. I was looking for unique instances, so
> Jim's and Daniel's suggestions got the job done. Using "length
One way is to exclude the NAs from consideration by creating a new
object without NAs in that column:
newTrees <- Trees[!is.na(Trees$SppID),]
tapply(newTrees$SppID, newTrees$PlotID, function(x) length(unique(x)))
On Wed, Jul 29, 2009 at 2:13 PM, Ian Chidister wrote:
> Hi All-
>
> Thanks for your
Hi All-
Thanks for your quick responses. I was looking for unique instances, so
Jim's and Daniel's suggestions got the job done. Using "length" alone
didn't discriminate between multiple occurrences of the same species and
multiple species.
I do have one followup question- my full data set (not
Hey,
i have forgotten to generalize the code so
Correl<-Correl[1:4,,,]
must be
Correl<-Correl[1:length(c),,,]
it's because the comparison levels. I think you don't want the
correlation betweeen A1, B1, D1 and A2, C1, D1 ,
but between A1, B1, D1 and A1, C1, D1 or between A1, B1, D1 and A1, C2, D
Hi,
Many apologies for sending this twice. I accidentally hit the send button
before I finished writing my mail. I am new to R and I hope someone can
help me with my problem. I am trying to draw a side by side barplot.
There is a main experiment and there are many sub experiments within the
mai
Hi,
I am new to R and I hope someone can help me with my problem. I am trying
to draw a side by side barplot.
There is a main experiment and there are many sub experiments within the
main experiment. I would like to draw a bar plot showing the number of
sub_experiments done for each main_exp. F
does "length" instead of "nlevels" do what you want to do?
with(Trees,tapply(SppID,PlotID,unique))
daniel
-
cuncta stricte discussurus
-
-Ursprüngliche Nachricht-
Von: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] Im
This is probably what you want; you need to count the number of unique
instances:
> tapply(Trees$SppID, Trees$PlotID, function(x) length(unique(x)))
BU3F10 BU3F11 BU3F12
1 2 4
>
On Wed, Jul 29, 2009 at 12:57 PM, Ian Chidister wrote:
> Dear List,
>
> I'm an [R] novice starting anal
I'm very impressed by the quick replies on the mailer. Thanks a lot for your
> suggestions. They worked very well.
De : Linlin Yan
Cc : r-help@r-project.org
Envoyé le : Mercredi, 29 Juillet 2009, 18h26mn 32s
Objet : Re: [R] vector
rep(A, each=2)
On Thu, Jul
Caro Sabrina,
Take a look at ?options, especially the max.print parameter.
Ciao,
Jorge
2009/7/29
> Ciao,
> ho aperto con R un file di classe data frame con 15000 righe e 29 colonne.
> Nella console perÅ sono visualizzate solo la prime e l'ultima colonna e le
> ultime 8000 righe circa.
> E' p
>> What I want to do is do a forrest (forest) plot for subgroups within my
>> single dataset as a test of heterogeniety. I have a dataset who received
>> either full dose(FD) or reduced dose(RD) treatment, and a number of
>> characteristics about those subjects: age, sex, renal function, weight,
Dear List,
I'm an [R] novice starting analysis of an ecological dataset containing the
basal areas of different tree species in a number of research plots.
Example data follow:
> Trees<-data.frame(SppID=as.factor(c(rep('QUEELL',2), rep('QUEALB',3),
'CORAME', 'ACENEG', 'TILAME')), BA=c(907.9, 1104
> Are n.FD and n.RD the number of people who received the full/reduced dose
Yes - but I don't have the data structured like that YET - thats what I want to
get to because thats what forest plot seems to be wanting.
> and surv.FD and surv.RD the number of people that survived?
Mmm... was more thin
Try the View function (note capitol V), does that do what you want?
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Beh
Hi,
On Jul 29, 2009, at 12:11 PM, jaregi wrote:
Hi Michael, Steve, and 1Rnwb,
I'm very impressed by the quick replies on the mailer. Thanks a lot
for your
suggestions. They worked very well.
In general, I have to say that I'm a bit disappointed that in R,
like in
Excel, one basically ne
In addition to Benjamin's response (which is the best way that I know of), you
may also want to look at the grconvertX and grconvertY functions for ways to
find the coordinates in the margins to plot at.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@
In addition to the other responses, you may want to look at the subplot
function in the TeachingDemos package for a way to place the image at a
location within the plot (the other answers so far use the image as a full
background), see the last example on the help page for a way to use the R log
rep(A, each=2)
On Thu, Jul 30, 2009 at 12:15 AM, Inchallah
Yarab wrote:
> Hi ,
>
> i have a vector A=(a1,a2,a3,a4) and i want to create another vector
> B=(a1,a1,a2,a2,a3,a3,a4,a4) !!!
> i know that it is simple but i begin with R so i nned your help!!
>
> thank you for your help !!!
>
>
>
>
hi,
i've opened a file with R which data are data.frame. It has 15000 rows and 29
columns.
On the console i only can see the first and the last columns and the last 8000
rows.
Is it possible to visualize the entire data set?
Thanks
Sabrina
Da: sabrina.michie...@
Hi ,
i have a vector A=(a1,a2,a3,a4) and i want to create another vector
B=(a1,a1,a2,a2,a3,a3,a4,a4) !!!
i know that it is simple but i begin with R so i nned your help!!
thank you for your help !!!
[[alternative HTML version deleted]]
__
I am not sure what you mean by "mark the length on each sub plot y axis", but
here is an example of the other parts (and if you know how to mark the length
on a single regular plot, then just add that code to the panel function):
pairs2( iris[,1], iris[,2:4], panel=function(x,y,...) {
Hi Michael, Steve, and 1Rnwb,
I'm very impressed by the quick replies on the mailer. Thanks a lot for your
suggestions. They worked very well.
In general, I have to say that I'm a bit disappointed that in R, like in
Excel, one basically needs to hack to get a dot blot with categories by
adding
dot means any character and * repeats it for as many times
as possible so it replaces eveything (.*) up to the last
dot (\\.) with nothing.
On Wed, Jul 29, 2009 at 9:43 AM, Petr PIKAL wrote:
> Thank you
>
> Gabor Grothendieck napsal dne 29.07.2009
> 15:20:40:
>
>> Here are a couple of possibiliti
It still was not attached, but you can reduce the white space by reducing the
margins using par(mar=c(...)).
If you do par(mar=c(0,0,0,0)), then there will be no space between the plots,
using values larger than 0 will give space. But beware, you need to either
suppress the plotting of axis la
Um Antwort von der R Mailinglite zu bekommen, verwenden Sie bitte eine
aussagekräftige Betreff-Zeile und formulieren Sie Ihre Anfrage in
*Englisch* - nachdem Sie den "posting guide" gelesen haben.
MfG,
Uwe Ligges
sabrina.michie...@alice.it wrote:
Ciao,
ho aperto con R un file di classe data
Never mind, just after I sent this I finally did the right search.
It is
RSVGTipsDevice
-Don
At 8:30 AM -0700 7/29/09, Don MacQueen wrote:
Some years ago, if I recall correctly, I learned of a package that
included a function that would write a plot to a file so that one
could associate hy
Hi,
I'm doing my first steps in R.
I wonder how can I create an n-way table of aggregate statistics, something like
what aggregate.table does, but with an unlimited number of grouping factors.
Thanks,
Yoav Kessler
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ht
Ciao,
ho aperto con R un file di classe data frame con 15000 righe e 29 colonne.
Nella console però sono visualizzate solo la prime e l'ultima colonna e le
ultime 8000 righe circa.
E' possibile una visualizzazione completa?
Grazie
Sabrina
[[alternative HTML version deleted]]
Some years ago, if I recall correctly, I learned of a package that
included a function that would write a plot to a file so that one
could associate hyperlinks with elements of the plot, such as points.
Then, when the plot was displayed in a browser, one could click on
(for example) a point, an
ciao,
ho aperto un file in R di classe data frame di 15000 righe e 29 colonne.
Nella console però sono visualizzate solo la prima e l'ultima colonna e le
ultime 8000 righe circa.
E' possibile una visualizzazione completa?
Grazie
Sabrina
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You need to create the variable names in newdata (which is generally a
dataframe) that match those used in constructing fm. Surely there
must be a worked example that illustrates this on the help page?
On Jul 29, 2009, at 9:30 AM, serbring wrote:
I have found a regression model, and i wou
Newdata needs to be a dataframe with the same variable names as the
explanatory variables in your models.
Model <- lm(y ~ x, data = dataset)
Newdata <- data.frame(x = seq(from=0.1, to=0.32,by=0.02))
Newdata$y <- predict(Model, newdata = Newdata)
HTH,
Thierry
---
Hello,
I also used the norm-package for data with missing values. Are there no
possibilities to fix it (its not under GPL?), or is here anyone able to get
the negotiation for the maintainership for this package?
Another question: I have read, taht "mice" would be an alternative instead
of using
I have found a regression model, and i would like to predict value in
different points. I have tried to use predict function but it doesn't work.
I have used predict function like this:
newdata<-seq(from=0.1, to=0.32,by=0.02)
data<-predict(fm,newdata)
where fm is a regression model. The predict
Look at the xpd option in ?par. If you set par(xpd=TRUE) you should be
able to add a segment for what you want. But please let me know if
someone gives you a better way to do this.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Al
On Tue, Jul 28, 2009 at 11:13:11PM -0700, rajclinasia wrote:
> Actually while opening R console and R commander we see some packages like
> car and datasets. In these packages we have default datasets.
> For example: "Women" and "Prestige" so on. Now we created a "Sales" dataset
> importing either
On Wed, Jul 29, 2009 at 03:12:02PM +0200, Øistein Harsem wrote:
> HiI am contacting you regarding a problem with downloading R. I
> cannot seen to manage because my computer language is in Norwegian.
> DO you know if there is R that can deal with Norwegian letters?
I have never seen a download to
On Tue, 2009-07-28 at 23:13 -0700, rajclinasia wrote:
> Our Query:
>
> Actually while opening R console and R commander we see some packages like
> car and datasets. In these packages we have default datasets.
> For example: "Women" and "Prestige" so on. Now we created a "Sales" dataset
> import
I'm not sure if you can consider grid graphics. If so, then Murrell
has some nice worked examples in:
http://www.stat.auckland.ac.nz/~paul/Talks/gddg.pdf
On Jul 29, 2009, at 4:27 AM, Rainer M Krug wrote:
while teaching R, the question came up if it would be possible to add
a picture (saved
Hi all,
Quick question: What function can I use to draw a line in the margin of a plot?
segments() and lines() both stop at the margin.
In case the answer depends on exactly what I'm trying to do, see below. I'm
using R v. 2.8.1 on Windows XP.
Cheers,
Alan
I'm trying to make a horizontal ba
Thank you
Gabor Grothendieck napsal dne 29.07.2009
15:20:40:
> Here are a couple of possibilities:
>
> sub(".*\\.", "", s)
This seems to be the target. Can you be so kind and translate for me what
it really does?
".* matches several dots?
\\. what is this?
I thought sub finds a match and r
Hi Christian,
Christian Langkamp wrote:
>
> I have the following array: 3 dimensional object, one dimension being
> year. Object is 3*3*3
>
> library(plyr, reshape)
>
# reshape won't be loaded that way, use separate library()
Christian Langkamp wrote:
>
> a1<-rep(c(2007,2008,2009),9)
> a2<-c
Thanks
If somebody does not come with more elaborated solution I will adapt
yours. After strsplit I can get not only 3 but several chunks. If the last
chunk is every time the one I need then
sapply(strsplit(names(foto),"\\..."), length)
[1] 2 6 6 6 6 5 5 6 5 3 3 3 3 3 3 3 3 3 3 4 3 3 4 4 3 3 3
Here are a couple of possibilities:
sub(".*\\.", "", s)
library(gsubfn)
strapply(s, "[0-9]*$", simplify = c)
On Wed, Jul 29, 2009 at 9:10 AM, Petr PIKAL wrote:
> Hi all
>
> I have got something like that (actually those are column names)
>
> [51] "X19.2.300b...80" "X19.2.400v...80" "X
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