Here are a couple of possibilities: sub(".*\\.", "", s)
library(gsubfn) strapply(s, "[0-9]*$", simplify = c) On Wed, Jul 29, 2009 at 9:10 AM, Petr PIKAL<petr.pi...@precheza.cz> wrote: > Hi all > > I have got something like that (actually those are column names) > > [51] "X19.2.300b...80" "X19.2.400v...80" "X19.2.400b...80" > "X19.2.300v...90" "X19.2.300b...90" > [56] "X19.2.400v...90" "X19.2..400b..90" "X19.2.300v...100" > "X19.2.300b...100" "X19.2.400v...100" > > in character vector. I would like to get last n figures from this > character vector but my regexpr unerstanding is inferior and I did not > succeed. > Please, is there anybody who can extract those n digits from end of each > character string? If there were only 2 digits I could use substr but there > can be one, two or three digits. > > I tried several variations of > > gsub("0:9$", "\\1" ,names(foto)[10]) > > but either got whole string or an error. > > Best regards > Petr > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.