I am a new commer in R. I am using the library tcltk, i need few information
about it.
so that, i wrote the following programme to save the file, but when i save the
file, i do not find the file save, please help me, in order to continue my
projet.
this is the programme:
tt <- tktoplevel()
txt
Michael wrote:
Hi all,
Please recommend good books for the following three categories. (I am
aim at finance, macroeconomics, trading and business applications).
(1) statistical (financial) data analysis;
(2) time series;
(3) econometrics.
More specifically, I am looking for the following two t
On Sat, Nov 08, 2008 at 09:58:14PM -0800, RON70 wrote:
>
> Still waiting for some input. Did my question void forum rule in any manner?
No, no specific rule. It's just not a particularly easy question to
answer, because it's not clear in what context you have seen the
phrase "portmanteau test".
Still waiting for some input. Did my question void forum rule in any manner?
RON70 wrote:
>
> Sorry to be off-topic. Can somebody please explain me what is Portmanteau
> test? Why it's name is like that? When I would say, a particular test is
> portmanteau test? I did some googling but got no s
On Sat, 8 Nov 2008, Heinz Tuechler wrote:
At 08:01 08.11.2008, Prof Brian Ripley wrote:
We have no idea what you understood (you didn't tell us), but the help says
encoding: character vector. The encoding(s) to be assumed when 'file'
is a character string: see 'file'. A possible va
I have read these books already... still searching for better books ...
On Sat, Nov 8, 2008 at 7:49 PM, Spencer Graves <[EMAIL PROTECTED]> wrote:
> One book is Ruey Tsay (2005) Analysis of Financial Time Series, 2nd ed.
> (Wiley). The R package "FinTS" provides script files to that show how
One book is Ruey Tsay (2005) Analysis of Financial Time Series,
2nd ed. (Wiley). The R package "FinTS" provides script files to that
show how to work some of the example in the book.
Try also "RSiteSearch" (www.r-project.org -> search PLUS the
"RSiteSearch" function in R) for more
Wensui Liu wrote:
Dear All,
My question is more a statistical question than a R question. The reason I
am posting here is that there are lots of excellent statistician on this
list, who can always give me good advices.
Per my understanding, the purpose of propensity score is to reduce the bias
Nevermind, when one puts in the proper coordinates in decimal degrees
everything works just fine.
thanks for you patience,
Stephen
On Sat, Nov 8, 2008 at 7:40 PM, stephen sefick <[EMAIL PROTECTED]> wrote:
> ##This is a function that I am trying to write to calculate sunrise
> and sunset and works
I've been marginally curious about this since 2004, and
spent a little time providing the beginnings of a port
which gives the basic facilities of Mark Newman's code
in R. There is a package on the Omegahat repository
via
install.packages("Rcartogram", repos = "http://www.omegahat.org/R";,
##This is a function that I am trying to write to calculate sunrise
and sunset and works "mostly", but returns nonsensical values. What
am I #missing? Thanks in advance.
###remember to include maptools as dependence###
library(maptools)
sunrise.set <- function(lat, long, date, timezone="UTC", nu
Hi all,
Please recommend good books for the following three categories. (I am
aim at finance, macroeconomics, trading and business applications).
(1) statistical (financial) data analysis;
(2) time series;
(3) econometrics.
More specifically, I am looking for the following two types of books:
(
Dear All,
My question is more a statistical question than a R question. The reason I
am posting here is that there are lots of excellent statistician on this
list, who can always give me good advices.
Per my understanding, the purpose of propensity score is to reduce the bias
while estimating the
Wacek Kusnierczyk wrote:
> Duncan Murdoch wrote:
>
> Here's a quick hack to achieve the impossible:
>
That might solve John's problem, but I doubt it. As far as I can see
it won't handle \L, for example.
>>> well, it was not supposed to. it addre
Glad I could be of help.
Some possible enhancements that you may want to try:
I would wrap all of that into a function so that the assignments using <<-
don't put stuff into the global environment but just change things in the top
level functions local environment.
Rather than having the click
Wacek Kusnierczyk wrote:
> Duncan Murdoch wrote:
>
>>
>> That might solve John's problem, but I doubt it. As far as I can see
>> it won't handle \L, for example.
>>
>>
>
> well, it was not supposed to. it addresses the need for doubling
> backslashes when a backslash character is an eleme
Duncan Murdoch wrote:
>
Here's a quick hack to achieve the impossible:
>>> That might solve John's problem, but I doubt it. As far as I can see
>>> it won't handle \L, for example.
>>>
>>
>> well, it was not supposed to. it addresses the need for doubling
>> backslashes when a backslash char
Do:
length(variablename)
where variablename is in {mats,time,quar}, i.e. do it for each of them. This
will tell you. Btw: I think you might wanna pickup an introductory manual.
Btw. Peter Dalgaard pointed to the same issue regarding the plot.
Daniel
-
cuncta stricte d
I'll see if I can speed it up if I get some time. I personally use it on
relatively short strings where the low absolute time means that
the higher relative time your comparisons show are not that
important.
On Sat, Nov 8, 2008 at 5:33 PM, Wacek Kusnierczyk
<[EMAIL PROTECTED]> wrote:
> Gabor Gro
On 08/11/2008 5:43 PM, Wacek Kusnierczyk wrote:
Duncan Murdoch wrote:
I was wondering if that is really necessary for perl=TRUE? wouldn't
it be
possible to parse a string differently in a regex context, e.g.
automatically insert \\ for each \ , such that you can use the perl
syntax
directly? For
Duncan Murdoch wrote:
>
>> I was wondering if that is really necessary for perl=TRUE? wouldn't
>> it be
>> possible to parse a string differently in a regex context, e.g.
>> automatically insert \\ for each \ , such that you can use the perl
>> syntax
>> directly? For exampl
However, now a linear regression with a factor for quarterly effect doesn't
want to work for me:
t2<-lm(mats~time+quar)
and I get an error message:
"Error in model.frame.default(formula = mats ~ time + quar,
drop.unused.levels = TRUE) :
variable lengths differ (found for 'quar')"
Which variabl
Gabor Grothendieck wrote:
> I suspect strapply is only relatively slow on short strings where
> it doesn't matter anyways since for long strings performance would
> likely be dominated by the underlying regexp operations. I know that
> users are using the package for very long strings since I once
Thank you Daniel,
I did try to change xlim's and ylim's, but the fitted line still doesn't
appear on the plot.
Below is a small expample I've created (I'm sorry for using names, but I het
confused with x's and y's):
>mat<-matrix(c(1,2,3,4,5,6,7,8,1,2,3,4,1,2,3,4,1,5,2,7,3,7,5,8),nrow=8,ncol=3)
>
On Sat, Nov 8, 2008 at 5:09 PM, Mark Kimpel <[EMAIL PROTECTED]> wrote:
> I found the article the "Y of R" in the latest R news to be very
> interesting. It is certainly challenging me to learn more about how R works
> "under the hood" as the author states. What is less clear to me is whether
> this
I suspect strapply is only relatively slow on short strings where
it doesn't matter anyways since for long strings performance would
likely be dominated by the underlying regexp operations. I know that
users are using the package for very long strings since I once had
to lift the 25,000 character
I found the article the "Y of R" in the latest R news to be very
interesting. It is certainly challenging me to learn more about how R works
"under the hood" as the author states. What is less clear to me is whether
this approach is primarily for teaching purposes or has a real world
application. W
Gabor Grothendieck wrote:
> For the problem at hand I think I would use your solution
> which is both easily understood and fastest. On the
> other hand the tapply based solutions are coordinate
> free (i.e. no explicit mucking with indices) and readily
> generalize to more than 2 groups -- just r
Hi!
A few weeks ago, I have uploaded a new R package "frontier" for Stochastic
Frontier Analysis (SFA) [1] to CRAN [2]. It includes the FORTRAN code of Tim
Coelli's [3] software "Frontier 4.1" [4]. Hence, the R package "frontier"
should have the same capabilities as "Frontier 4.1", i.e. Maximum
For the problem at hand I think I would use your solution
which is both easily understood and fastest. On the
other hand the tapply based solutions are coordinate
free (i.e. no explicit mucking with indices) and readily
generalize to more than 2 groups -- just replace [^pq] with
[^pqr], say.
On S
On 08/11/2008 3:16 PM, Wacek Kusnierczyk wrote:
Duncan Murdoch wrote:
On 08/11/2008 11:03 AM, Gabor Grothendieck wrote:
On Sat, Nov 8, 2008 at 9:41 AM, Duncan Murdoch <[EMAIL PROTECTED]>
wrote:
On 08/11/2008 7:20 AM, John Wiedenhoeft wrote:
Hi there,
I rejoiced when I realized that you can u
Wacek Kusnierczyk wrote:
> Gabor Grothendieck wrote:
>
>> Here are a few more solutions. x is the input vector
>> of character strings.
>>
>> The first is a slightly shorter version of one of Wacek's.
>> The next three all create an anonymous grouping variable
>> (using sub, substr/gsub and str
Gabor Grothendieck wrote:
> Here are a few more solutions. x is the input vector
> of character strings.
>
> The first is a slightly shorter version of one of Wacek's.
> The next three all create an anonymous grouping variable
> (using sub, substr/gsub and strapply respectively)
> whose components
On Fri, Nov 7, 2008 at 11:03 AM, <[EMAIL PROTECTED]> wrote:
> Dear R Users,
> May be this message should be directy send to Douglas Bates ...
> I just want to know if I can use the AIC value given in the output of an lmer
> model to classify my logistic models.
> I heard that the AIC value given
On Sat, Nov 8, 2008 at 3:59 PM, Rubén Roa-Ureta <[EMAIL PROTECTED]> wrote:
> ...
> The fit is for grouped data.
> ...
As illustrated in my example code, I'm not dealing with data that can be
grouped (x is a continuous random variable).
--
Mike Lawrence
Graduate Student
Department of Psychology
uep wrote:
I'm trying to plot a time series (quarterly observations, seasonal effect,
T=56),regression line and predicted point on the same plot.
I'm using following commands:
plot(qdts,xlim=c(1982,1997))
lines(fitted(m2)~time,data=qd,col="red")
points(predict(m2,newdata=nqd),col="blue")
Umm,
uep wrote:
>
> I'm trying to plot a time series (quarterly observations, seasonal effect,
> T=56),regression line and predicted point on the same plot.
> I'm using following commands:
>> plot(qdts,xlim=c(1982,1997))
>> lines(fitted(m2)~time,data=qd,col="red")
>> points(predict(m2,newdata=nqd),c
Duncan Murdoch wrote:
> On 08/11/2008 11:03 AM, Gabor Grothendieck wrote:
>> On Sat, Nov 8, 2008 at 9:41 AM, Duncan Murdoch <[EMAIL PROTECTED]>
>> wrote:
>>> On 08/11/2008 7:20 AM, John Wiedenhoeft wrote:
Hi there,
I rejoiced when I realized that you can use Perl regex from within R.
Please provide a self-contained example (small simulated dataset or the
original data [if it is or reasonable size] such that it can be copy-pasted
in R). We cannot tell what is going wrong when we can't follow what is going
on.
Generally, that you don't get any error message indicates that the li
Mike Lawrence wrote:
Hi all,
Where f(x) is a logistic function, I have data that follow:
g(x) = f(x)*.5 + .5
How would you suggest I modify the standard glm(..., family='binomial')
function to fit this? Here's an example of a clearly ill-advised attempt to
simply use the standard glm(..., famil
On Sat, Nov 8, 2008 at 2:05 PM, Duncan Murdoch <[EMAIL PROTECTED]> wrote:
> On 08/11/2008 11:03 AM, Gabor Grothendieck wrote:
>>
>> On Sat, Nov 8, 2008 at 9:41 AM, Duncan Murdoch <[EMAIL PROTECTED]>
>> wrote:
>>>
>>> On 08/11/2008 7:20 AM, John Wiedenhoeft wrote:
Hi there,
I rej
Hi all,
Where f(x) is a logistic function, I have data that follow:
g(x) = f(x)*.5 + .5
How would you suggest I modify the standard glm(..., family='binomial')
function to fit this? Here's an example of a clearly ill-advised attempt to
simply use the standard glm(..., family='binomial') approach:
I'm trying to plot a time series (quarterly observations, seasonal effect,
T=56),regression line and predicted point on the same plot.
I'm using following commands:
> plot(qdts,xlim=c(1982,1997))
> lines(fitted(m2)~time,data=qd,col="red")
> points(predict(m2,newdata=nqd),col="blue")
where:
qdts<-
On 08/11/2008 11:03 AM, Gabor Grothendieck wrote:
On Sat, Nov 8, 2008 at 9:41 AM, Duncan Murdoch <[EMAIL PROTECTED]> wrote:
On 08/11/2008 7:20 AM, John Wiedenhoeft wrote:
Hi there,
I rejoiced when I realized that you can use Perl regex from within R.
However, as the FAQ states "Some functions,
Try:
plot(ecdf(x))
lines(ecdf(y), col.hor='blue')
see ?plot.stepfun
On Sat, Nov 8, 2008 at 1:39 PM, eric lee <[EMAIL PROTECTED]> wrote:
> Hi. I'm trying to plot two ecdf's on the same graph using two
> different colors. I can plot using the same color, but it doesn't
> work when I change color
eric lee wrote:
Hi. I'm trying to plot two ecdf's on the same graph using two
different colors. I can plot using the same color, but it doesn't
work when I change colors? Any suggestions? Thanks in advance for
your help.
x <- c(0.80, 0.83, 1.89, 1.04, 1.45, 1.38, 1.91, 1.64, 0.73, 1.46)
y <-
Hi. I'm trying to plot two ecdf's on the same graph using two
different colors. I can plot using the same color, but it doesn't
work when I change colors? Any suggestions? Thanks in advance for
your help.
x <- c(0.80, 0.83, 1.89, 1.04, 1.45, 1.38, 1.91, 1.64, 0.73, 1.46)
y <- c(1.15, 0.88, 0.9
Hi there,
I was wondering if by the way the isotropic bivariate function works in the
mgcv package,
one can use highly correlated coordinates (given the shape of the study area)
without worrying about the potential problems of correlation between
explanatory variables, i.e., does s(LON, LAT) de
Hello,
I'm trying to get the z-axis labels in the right place - they overlap
with the tick marks and axis. How can I move them them to the left?
wireframe(volcano,zlab="",scales =
list(arrows=F,z=list(labels=c(1:100)/1000)))
Thanks,
Andrzej
--
Andrzej Szymański, M.Sc.
tel. +48 12 6174035
dt Excellent wrote:
Hi to everybody
is there any way to update from an older version of R to a newer one without
having to reload all the packages I've used up to that time?Many regards to all
of you
If you install contributed packages into a separate library tree, you
can simply run up
Just expand the weekly data set to have an entry for each day and cbind
SurveyData with the new Modified.sat.data.
I was having a similar problem but with dates and here was a solution suggested
by Gustaf Rydevik using rep() with the each option.
=
Hi, Greg,
Thanks again for your reply. I looked at TkIdentify which lead me to
"plt", which with RSiteSearch("grid plt") lead me to gridBase::gridPLT.
Here's my solution:
stopifnot(require(tkrplot),
require(lattice),
require(gridBase))
makePlot <- function() {
print(xyp
A very simple but long way to do this would be to subset your data set. There
are better ways but this way would be easy to understand.
January <- subset(mydata, Month=="January")
Repeat for each month.
--- On Fri, 11/7/08, Swanton0822 <[EMAIL PROTECTED]> wrote:
> From: Swanton0822 <[EMAIL PR
On Sat, Nov 8, 2008 at 9:41 AM, Duncan Murdoch <[EMAIL PROTECTED]> wrote:
> On 08/11/2008 7:20 AM, John Wiedenhoeft wrote:
>>
>> Hi there,
>>
>> I rejoiced when I realized that you can use Perl regex from within R.
>> However, as the FAQ states "Some functions, particularly those involving
>> regul
It would help a lot if you told us what the error message was, and provided
some data to work with. As it is, we can't even run the function to find
out what goes wrong.
And also, OS, version of R - all that stuff that the posting guide requests.
Sarah
On Sat, Nov 8, 2008 at 10:31 AM, Bryan Rich
Hi to everybody
is there any way to update from an older version of R to a newer one without
having to reload all the packages I've used up to that time?Many regards to all
of you
___
ΧÏηÏιμοÏοιείÏ[[elided Yahoo
Professor Ripley,
My apologies for not clarifying the timezone - I am in California (PDT
-> PST). I did review various help pages and I am still unclear on
the explanation.
I replicated your code:
> as.POSIXct("2008-11-02 01:17:00")
[1] "2008-11-02 01:17:00 PST"
> as.POSIXct("2008-11-02
I am new to R and have written a function that clusters on subsets of a big
data data set with 60,000 points. I am not sure why, but I keep getting a
run-time error. Any suggestions would be greatly appreciated.
Here is the code:
library(cba)
d<-read.csv("data.csv", header=TRUE)
v<-c(53,54,
> "TP" == Thomas Petzoldt <[EMAIL PROTECTED]>
> on Sat, 08 Nov 2008 11:11:30 +0100 writes:
TP> Hi Paul, one possibility: write the tree to a wide pdf
TP> file and then zoom and scroll using Adobe Acrobat or
TP> another PDF reader. Here is a tree with 1000 objects:
TP>
On 08/11/2008 7:20 AM, John Wiedenhoeft wrote:
Hi there,
I rejoiced when I realized that you can use Perl regex from within R. However,
as the FAQ states "Some functions, particularly those involving regular
expression matching, themselves use metacharacters, which may need to be
escaped by t
Some feature to simplify entry of backslashes has been mentioned many times
and keeps coming up from time to time. It would not only be useful for regexp's
but also for latex and Windows path names and I too hope that it will be
addressed.
On Sat, Nov 8, 2008 at 7:20 AM, John Wiedenhoeft <[EMAIL P
Moreover, use 'symbols' to draw the circle, it is a better and simpler solution.
Gabor
On Fri, Nov 7, 2008 at 9:02 PM, Sarah Goslee <[EMAIL PROTECTED]> wrote:
> ?text
>
> On Fri, Nov 7, 2008 at 12:42 PM, Alex99 <[EMAIL PROTECTED]> wrote:
>>
>> Hi guys,
>>
>> I am truing to draw a circle and choos
Hi there,
I rejoiced when I realized that you can use Perl regex from within R. However,
as the FAQ states "Some functions, particularly those involving regular
expression matching, themselves use metacharacters, which may need to be
escaped by the backslash mechanism. In those cases you may ne
Hi Hadley,
thanks for your hints and sorry for my late answer.
I will check them and see whether they will help in my case.
Unfortunately I found some nasty data import problems that I have to
solve before I can continue with the graphics. (encoding problems)
For me the reason for combining d
. http://www.nabble.com/file/p20392420/kew.dat kew.dat
Hi,
i did something wrong,
with the data attach all i want is 12 groups for the months like this:(group
1=group Jan,..group12= group Dec)
group 1 group 2 group 3.. group 12
and inside each group is the vaule of t
Hi Horace
I suppose by 'image' you mean the workspace ?
If that's the case it always has to run in a workspace thus creating one
in memory if you don't choose one yourself.
You may want to go into 'Settings > RKWard Settings > General' and
change 'Startup Actions'.
If, on the other hand, you a
To answer the actual question, your i and j indices are not what you expect (but are what
you specify).
Consider the following, which follows your algorithm:
> vector1 <- sample(1:100,2)
> vector2 <- sample(1:100,2)
> for (i in vector1) {
+ for (j in vector2) {
+ show(c(i, j))
+ }
+ }
[
Thomas Petzoldt wrote:
Hi Tom,
you may have a look at the CRAN package simecol, that has some examples
how to implement different types of dynamic models in R (differential
equations, grid models, individual based models).
Individual-based models (IBMs) are a model family used in ecology, wh
Thomas Petzoldt wrote:
Hi Tom,
you may have a look at the CRAN package simecol, that has some examples
how to implement different types of dynamic models in R (differential
equations, grid models, individual based models).
Individual-based models (IBMs) are a model family used in ecology, wh
See ?ave and ?seq_along
DF <- data.frame(Name = c("Mary", "Mary", "Mary", "Sam", "Sam",
"John", "John", "John", "John"), stringsAsFactors = FALSE)
DF$index <- ave(1:nrow(DF), DF$Name, FUN = seq_along)
On Sat, Nov 8, 2008 at 5:43 AM, jie feng <[EMAIL PROTECTED]> wrote:
> Hi, there,
>
> I have
one way is with ave(), e.g.,
dat <- data.frame(name = rep(c("Mary", "Sam", "John"), c(3,2,4)))
dat$freq <- ave(seq_along(dat$name), dat$name, FUN = seq_along)
dat
I hope it helps.
Best,
Dimitris
jie feng wrote:
Hi, there,
I have a simple data manipulation question for you. Thank you for yo
Hi, there,
I have a simple data manipulation question for you. Thank you for your help!
Suppose that I have this data about people appearing in a class
Mary
Mary
Mary
Sam
Sam
John
John
John
John
Then I want to find out what exact time(s) the student appears at the
moment such as
Mary 1
Mary
Hi Paul,
one possibility: write the tree to a wide pdf file and then zoom and
scroll using Adobe Acrobat or another PDF reader. Here is a tree with
1000 objects:
x <- matrix(rnorm(3000), nrow=1000)
hc <- hclust(dist(x))
pdf("tree.pdf", width=150)
plot(hc)
dev.off()
Thomas P.
paul murima w
Hi Tom,
you may have a look at the CRAN package simecol, that has some examples
how to implement different types of dynamic models in R (differential
equations, grid models, individual based models).
Individual-based models (IBMs) are a model family used in ecology, which
are in its essence almo
At 08:01 08.11.2008, Prof Brian Ripley wrote:
We have no idea what you understood (you didn't tell us), but the help says
encoding: character vector. The encoding(s) to be assumed when 'file'
is a character string: see 'file'. A possible value is
'"unknown"': see the âDet
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