How can I make maybe 3D subfigures with Python and matplotlib?
I found the following example (http://matplotlib.sourceforge.net/
examples/mplot3d/subplot3d_demo.html), but it doesn't work.
---
from mpl_toolkits.mplot3d.axes3d import Axes3D
import matplotlib.pyplot as plt
# imports specific to th
Hi!
Can you, please, try to help me with Python? I try to convert a MATLAB
program to Python.
Here are the MATLAB codes:
http://pastebin.com/eJetYizv
http://pastebin.com/0eXTVfyN
Here is my Python code:
http://pastebin.com/jCPdLHx7
What is wrong with my Python code? The program doesn't produce
On Nov 17, 10:04 am, MATLABdude wrote:
Thanks guys!
I still have some problems. I made the code somewhat simpler by
dropping off some parts of it (xx, f).
Now my Python code calculates 8 different values for lambda. The
problem is that I don't know where the minus sign comes from. Als
On Nov 17, 10:53 am, Arnaud Delobelle wrote:
> I guess that the step is supposed to be h, so you should write:
> xx = range(-kappa, kappa+1, h)
This is what I have in the source code:
---8<---8<---8<---8<---
h = 0.105069988414
xx = range(-kappa, kappa+1, h)
---8<---8<---8<---8<---
This is w
On Nov 22, 11:11 am, Peter Otten <__pete...@web.de> wrote:
> Try numpy.arange() instead:
> >>> numpy.arange(0, 1, .1)
> array([ 0. , 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9])
Thanks! It worked.
What's wrong with the following code?
---8<---8<---8<---
T0_orig = [5, 50, 500, 5000]
On Nov 23, 9:43 am, Arnaud Delobelle wrote:
> T0_orig is a list and you are trying to multiply this list by a float
> (m**-1)
Yes, yes of course. Thanks! :)
This works:
---8<---8<---8<---
T0_orig = [5, 50, 500, 5000]
for counter in T0_orig:
T0 = (L**2)/(D*pi**2)*counter
a
