Ahmed, Shakir wrote:
Here is the final code that worked to unzip a large file in the network
drive.
CHUNK_SIZE = 10 * 1024 * 1024
fh = open('T:\\applications\\tst\\py\\Zip_Process\\Zip\\myzip.zip',
'rb')
z = zipfile.ZipFile(fh)
for name in z.namelist():
fn = open(name, 'wb')
ptr = 0
-Original Message-
From: Ethan Furman [mailto:et...@stoneleaf.us]
Sent: Friday, June 24, 2011 3:47 PM
To: Ahmed, Shakir
Cc: Python
Subject: Re: unzip problem
Ahmed, Shakir wrote:
> Thanks once again and you are right I am trying to unzip in the
network
> share drive. here is the
Ahmed, Shakir wrote:
Thanks once again and you are right I am trying to unzip in the network
share drive. here is the script now: If I am doing any wrong. :
## code start here
import zipfile
import os
import time
dir1 = "T:\\applications\\tst\\py\\Zip_Process"
test = '%s/shp'%dir1
os.chdir(test)
Ahmed, Shakir wrote:
Thanks for your help and really appreciate your time.
I changed the code as you mentioned and here it is:
fn = open('T:\\applications\\tst\\py\\Zip_Process\\Zip\\myzip.zip',
'rb')
z = zipfile.ZipFile(fn)
for name in z.namelist():
data = z.read(name)
ptr = 0
Ahmed, Shakir wrote:
> The problem is happening when it is coming to write option.
>
> The * is not the real name of the zip file, I just hide the name.
Please don't waste our time by showing us fake code that doesn't do what you
say it does.
You said that "The script is here", but that was not
Ahmed, Shakir wrote:
Hi,
I am getting following error message while unziping a .zip file. Any
help or idea is highly appreciated.
Error message>>>
Traceback (most recent call last):
File "C:\Zip_Process\py\test2_new.py", line 15, in
outfile.write(z.read(name))
IOError: (22, '
-Original Message-
From: python-list-bounces+shahmed=sfwmd@python.org
[mailto:python-list-bounces+shahmed=sfwmd@python.org] On Behalf Of
Philip Semanchuk
Sent: Friday, June 24, 2011 11:18 AM
To: Lista-Comp-Lang-Python list
Subject: Re: unzip problem
On Jun 24, 2011, at 10:55 AM
On Fri, 24 Jun 2011 10:55:52 -0400, Ahmed, Shakir wrote:
> Hi,
>
>
>
> I am getting following error message while unziping a .zip file. Any
> help or idea is highly appreciated.
How do you know it is when unzipping the file? Maybe it is, or maybe it
isn't. The line giving the error has *two*
On Jun 24, 2011, at 10:55 AM, Ahmed, Shakir wrote:
> Hi,
>
>
>
> I am getting following error message while unziping a .zip file. Any
> help or idea is highly appreciated.
>
>
>
> Error message>>>
>
> Traceback (most recent call last):
>
> File "C:\Zip_Process\py\test2_new.py", line 15,
On Fri, 24 Jun 2011 10:55:52 -0400, Ahmed, Shakir wrote:
> Hi,
>
>
>
> I am getting following error message while unziping a .zip file. Any
> help or idea is highly appreciated.
How do you know it is when unzipping the file? Maybe it is, or maybe it
isn't. The line giving the error has *two*
Hi,
I am getting following error message while unziping a .zip file. Any
help or idea is highly appreciated.
Error message>>>
Traceback (most recent call last):
File "C:\Zip_Process\py\test2_new.py", line 15, in
outfile.write(z.read(name))
IOError: (22, 'Invalid argument')
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