On Fri, 24 Jun 2011 10:55:52 -0400, Ahmed, Shakir wrote: > Hi, > > > > I am getting following error message while unziping a .zip file. Any > help or idea is highly appreciated.
How do you know it is when unzipping the file? Maybe it is, or maybe it isn't. The line giving the error has *two* IO operations, a read and a write. Either one could give IOError. outfile.write(z.read(name)) IOError: (22, 'Invalid argument') The first thing is to isolate what is causing the error: data = z.read(name) outfile.write(data) Now you can be sure whether it is the read or the write which causes the error. Secondly, find out what the argument is. Assuming it is the read, try this: print repr(name) Can you open the zip file in Winzip or some other zip utility? Does it need a password? I see you do this: fh = open('T:\\test\\*.zip', 'rb') Do you really have a file called *.zip? I find that very hard to believe... as I understand it, * is a reserved character in Windows and you cannot have a file with that name. My guess is that the actual error is when you try to open the file in the first place, before any unzipping takes place, but you've messed up the line numbers (probably by editing the file after importing it). -- Steven >> The problem is happening when it is coming to write option. The * is not the real name of the zip file, I just hide the name. -- http://mail.python.org/mailman/listinfo/python-list