Ryan K wrote:
> It doesn't even run but when I go through it interactively it
> seems okay. Once again, any help is appreciated.
I haven't tested yet, but why don't you make a list of words of the
text (with split), and then accumulate words in a list until the
next word would make the line too l
On Feb 28, 5:50 pm, "Ryan K" <[EMAIL PROTECTED]> wrote:
> On Feb 28, 8:27 pm, [EMAIL PROTECTED] wrote:
>
> > Try:
>
> > import re
> > sample_text = """Personal firewall software may warn about the
> > connection IDLE makes to its subprocess using this computer's internal
> > loopback interface. T
That works great but I need to replace the newlines with 24-(the index
of the \n) spaces.
On Feb 28, 8:27 pm, [EMAIL PROTECTED] wrote:
> On Feb 28, 4:06 pm, "Ryan K" <[EMAIL PROTECTED]> wrote:
>
> > I'm trying to text wrap a string but not using the textwrap module. I
> > have 24x9 "matrix" and
On Feb 28, 4:06 pm, "Ryan K" <[EMAIL PROTECTED]> wrote:
> I'm trying to text wrap a string but not using the textwrap module. I
> have 24x9 "matrix" and the string needs to be text wrapped according
> to those dimensions. Is there a known algorithm for this? Maybe some
> kind of regular expression
I am not certain if I understand your problem, but I think you are just
trying to read in a string and create a visable matrix. If that is true,
then may some of the code below will work. This is in no way elegant.
++
count = 1
width = 2
Okay, I was a little vague in my last post...the matrix is like a
Wheel of Fortune board and it knows nothing about newlines. After 24
characters it spills over onto the next line. Here is what I came up
with:
## Wrap Text
def wrap_text(in_str, chars_line):
""" wrap text """
spaces = 0
I'm trying to text wrap a string but not using the textwrap module. I
have 24x9 "matrix" and the string needs to be text wrapped according
to those dimensions. Is there a known algorithm for this? Maybe some
kind of regular expression? I'm having difficulty programming the
algorithm. Thanks,
Ryan
