Hi.
I understood your point.
thanks...
rahul
Steven Bethard wrote:
> Steven Bethard wrote:
> >
> > def wrap(obj):
> > def f(*args, **kwargs):
> > for arg in args:
> > print arg
> > return obj(*args, **kwargs)
> > return f
> >
> > @wrap
> > def func(a, b, c):
Steven Bethard wrote:
>
> def wrap(obj):
> def f(*args, **kwargs):
> for arg in args:
> print arg
> return obj(*args, **kwargs)
> return f
>
> @wrap
> def func(a, b, c):
> ...
>
> class C(object):
> ...
> C = wrap(C)
Rahul top-posted:
> If you
Rahul wrote:
> If you do C = wrap(C) C no longer remains a class..it becomes a
> function.
Does that matter?
Reinhold
--
http://mail.python.org/mailman/listinfo/python-list
If you do C = wrap(C) C no longer remains a class..it becomes a
function.
Steven Bethard wrote:
> Rahul wrote:
> > def wrapper(obj):
> >g = obj.__call__
> >def f(*args,**kwargs):
> > for arg in args:print arg
> > return g(*args,**kwargs)
> >obj.__call__=f
> > but it seems thi
Rahul wrote:
> def wrapper(obj):
>g = obj.__call__
>def f(*args,**kwargs):
> for arg in args:print arg
> return g(*args,**kwargs)
>obj.__call__=f
> but it seems this will not work for functions :(
def wrap(obj):
def f(*args, **kwargs):
for arg in args:
Hi.
well if you do dir(a) just after defining 'a' then it does show
'__call__'.
the reason i wanted to do it is that i wanted to see if theres a
uniform way to wrap a function and callable objects so that for
example i can get some message printed whenever a function or a
function-like-object is c
Just a guess, but setting "__X__" special methods won't work in most cases
because these are usually optimized when the class is created.
It might work if a.__call__ did exist before (because class a: contained
a __call__ definition).
Andreas
On Wed, Jun 29, 2005 at 09:15:45AM +0100, Michael Hof
Rahul wrote:
> Consider the following:
> def a(x):
> return x+1
>
> def b(f):
> def g(*args,**kwargs):
> for arg in args:
> print arg
> return f(*args,**kwargs)
> return g
>
> a.__call__ = b(a.__call__)
>
> now calling a(1) and a.__call__(1) yield 2 different results!!
> i.e
Consider the following:
def a(x):
return x+1
def b(f):
def g(*args,**kwargs):
for arg in args:
print arg
return f(*args,**kwargs)
return g
a.__call__ = b(a.__call__)
now calling a(1) and a.__call__(1) yield 2 different results!!
i.e. for functions a(1) doesnt seem to be tran
