John Machin wrote:
> As viewed with Google Groups, lines 40/41, 63/69, and 89 are indented 8
> spaces more than they should be.
>
> When I save your file and try to run it, I get this: C:\junk>coolgenie.py
> File "C:\junk\coolgenie.py", line 40
> self.w = 520
> ^
> IndentationError: une
> self.numlines = self.config['numlines']
>
> self.w = 520
> self.h = 12*self.numfeeds*(self.numlines+1)
why extra ident here?
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Vladimir Rusinov
GreenMice Solutions: IT-решения на базе Linux
http://greenmice.info/
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--- CoolGenie <[EMAIL PROTECTED]> wrote:
> OK, sorry, this was about indents. Stupid VIM!
One more piece of VIM advice. You can use "set list"
to show where tabs are. I prefer to convert my own
tabs to spaces automatically, but you inevitably come
across code that you don't own where it's nice
--- CoolGenie <[EMAIL PROTECTED]> wrote:
> OK, sorry, this was about indents. Stupid VIM!
No prob. Add something like this (untested) to your
~/.vimrc:
set expandtab
set sw=4
set ts=4
Looking for
On Sun, 09 Dec 2007 12:35:46 -0800, CoolGenie wrote:
> OK, sorry, this was about indents. Stupid VIM!
$ mkdir -p $HOME/.vim/ftplugin/
$ echo "setlocal sw=4
setlocal ts=4
noremap py o/**/
" >> ~/.vim/ftplugin/python.vim
$ echo "syntax on
set sw=2
set ts=2
set nu
set nuw=3
set autoin
--- CoolGenie <[EMAIL PROTECTED]> wrote:
> self.feed = self.config['feedsrc']
> self.numfeeds = self.config['numfeeds']
> self.numlines = self.config['numlines']
>
> self.w = 520
> self.h = 12*self.numfeeds*(self.numlines+1)
> adesklets.
On Dec 10, 7:15 am, CoolGenie <[EMAIL PROTECTED]> wrote:
> Hi!
> I'm trying to write a small adesklet that will read newsfeeds. Here's
> the code:
>
> #
> #
> # fparser.py
> #
> # P. Kaminski <[EMAIL PROTECTED]>
> # Time-stamp: <>
OK, sorry, this was about indents. Stupid VIM!
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Hi!
I'm trying to write a small adesklet that will read newsfeeds. Here's
the code:
#
#
# fparser.py
#
# P. Kaminski <[EMAIL PROTECTED]>
# Time-stamp: <>
##
impor
Attila Szabo wrote:
2005, Feb 25 -> Scott David Daniels wrote :
Attila Szabo wrote:
>>...lambda x: 'ABC%s' % str(x) ...
OK, to no real effect, in main you define an unnamed function that
you can never reference. Pretty silly, but I'll bite.
This code was simplified, the lambda was part of a m
2005, Feb 25 -> Scott David Daniels wrote :
> Attila Szabo wrote:
> >Hi,
> >def main():
> >lambda x: 'ABC%s' % str(x)
> >for k in range(2): exec('print %s' % k)
> OK, to no real effect, in main you define an unnamed function that
> you can never reference. Pretty silly, but I'll bi
"Attila Szabo" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Hi,
>
> I wrote this sample piece of code:
>
> def main():
>lambda x: 'ABC%s' % str(x)
>for k in range(2): exec('print %s' % k)
>
> main()
>
> With the lambda line, I get this:
> SyntaxError: unqualified
Attila Szabo wrote:
Hi,
def main():
lambda x: 'ABC%s' % str(x)
for k in range(2): exec('print %s' % k)
OK, to no real effect, in main you define an unnamed function that
you can never reference. Pretty silly, but I'll bite.
Next you run run a loop with exec looking like you think i
Hi,
I wrote this sample piece of code:
def main():
lambda x: 'ABC%s' % str(x)
for k in range(2): exec('print %s' % k)
main()
With the lambda line, I get this:
SyntaxError: unqualified exec is not allowed in function 'main'
it con
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