On Thursday 16 December 2004 14:46, [EMAIL PROTECTED] wrote:
> > # confDocument is a libxml2 document, from parseFile() etc
> > xp = confDocument.xpathNewContext()
> > xp.xpathRegisterNs("xhtml", "http://www.w3.org/1999/xhtml";)
> > dirElement = xp.xpathEval( "/xhtml:html" )
>
> Stu
> # confDocument is a libxml2 document, from parseFile() etc
> xp = confDocument.xpathNewContext()
> xp.xpathRegisterNs("xhtml", "http://www.w3.org/1999/xhtml";)
> dirElement = xp.xpathEval( "/xhtml:html" )
>
Stupid question, but can the namespace somehow be changed to null to
mak
On Thursday 16 December 2004 12:29, Maxim Khesin wrote:
> I do not believe it is... You can see the doc by clicking on the link.
> Does it have to be?
No, but your XPath statements must match the namespace, no matter what it is.
The document do have a namespace -- as XHTML should:
http://www.w3
I do not believe it is... You can see the doc by clicking on the link.
Does it have to be?
thanks,
m
Martijn Faassen wrote:
Maxim Khesin wrote:
I am trying to do some xpath on
http://fluidobjects.com/doc.xhtml
but cannot get past 'point A' (that is, I am totally stuck):
import libxml2
mydoc = li
Maxim Khesin wrote:
I am trying to do some xpath on
http://fluidobjects.com/doc.xhtml
but cannot get past 'point A' (that is, I am totally stuck):
import libxml2
mydoc = libxml2.parseDoc(text)
mydoc.xpathEval('/html')
[]
this returns an empty resultlist, which just seems plain wrong. Can anyone
t
I am trying to do some xpath on
http://fluidobjects.com/doc.xhtml
but cannot get past 'point A' (that is, I am totally stuck):
>> import libxml2
>> mydoc = libxml2.parseDoc(text)
>> mydoc.xpathEval('/html')
>> []
this returns an empty resultlist, which just seems plain wrong. Can anyone
throw a s
