On Thursday 16 December 2004 12:29, Maxim Khesin wrote: > I do not believe it is... You can see the doc by clicking on the link. > Does it have to be?
No, but your XPath statements must match the namespace, no matter what it is. The document do have a namespace -- as XHTML should: <html xmlns="http://www.w3.org/1999/xhtml";> The problem with this: mydoc.xpathEval('/html') is that it tries to match a top element whose local name is "html" and whose namespace is null, but in the source document, the local name is "html" but the namespace is not null, it's "http://www.w3.org/1999/xhtml"; --> they don't match. The solution is to have a matching namespace, such that the whole qualified name matches. AFAIK, it is done like this in libxml2: # confDocument is a libxml2 document, from parseFile() etc xp = confDocument.xpathNewContext() xp.xpathRegisterNs("xhtml", "http://www.w3.org/1999/xhtml";) dirElement = xp.xpathEval( "/xhtml:html" ) Cheers, Frans -- http://mail.python.org/mailman/listinfo/python-list
