Back9 writes:
> Hi,
>
> I have one byte data and want to know each bit info,
> I mean how I can know each bit is set or not?
Other than the tedious anding, oring and shifting, you can convert
your byte to a string (with function bin) and use normal string
handling functions to check if individua
On 6/17/10 1:29 PM, Grant Edwards wrote:
> On 2010-06-17, Stephen Hansen wrote:
>
> BIT_1 = 1 << 0
> BIT_2 = 1 << 1
>
> ...
>
>> Basically, those BIT_X lines are creating numbers which have *only* the
>> specified bit set. Then you do "byte & BIT_X", and that will return 0 if
>> the byt
On 2010-06-17, Stephen Hansen wrote:
BIT_1 = 1 << 0
BIT_2 = 1 << 1
...
> Basically, those BIT_X lines are creating numbers which have *only* the
> specified bit set. Then you do "byte & BIT_X", and that will return 0 if
> the byte doesn't have the specified bit in it. You can then set
On 17-6-2010 21:51, Back9 wrote:
Hi,
I have one byte data and want to know each bit info,
I mean how I can know each bit is set or not?
TIA
Use bitwise and, for instance, to see if the third bit is set:
byte = 0b
if byte & 0b0100:
print "bit is set"
-irmen
--
http://mail
On 6/17/10 12:51 PM, Back9 wrote:
> I have one byte data and want to know each bit info,
> I mean how I can know each bit is set or not?
>>> BIT_1 = 1 << 0
>>> BIT_2 = 1 << 1
>>> BIT_3 = 1 << 2
>>> BIT_4 = 1 << 3
>>> BIT_5 = 1 << 4
>>> BIT_6 = 1 << 5
>>> BIT_7 = 1 << 6
>>> BIT_8 = 1 << 7
>>> byte
On Jun 17, 3:51 pm, Back9 wrote:
> Hi,
>
> I have one byte data and want to know each bit info,
> I mean how I can know each bit is set or not?
You want the bitwise-and operator, &.
For example, to check the least significant bit, bitwise-and with 1:
>>> 3 & 1
1
>>> 2 & 1
0
--
http://mail.pyth
Op donderdag 17-06-2010 om 12:51 uur [tijdzone -0700], schreef Back9:
> Hi,
>
> I have one byte data and want to know each bit info,
> I mean how I can know each bit is set or not?
>
> TIA
def bitset(x, n):
"""Return whether nth bit of x was set"""
return bool(x & (1 << n))
--
http://mail.pyt
