On 6/17/10 12:51 PM, Back9 wrote: > I have one byte data and want to know each bit info, > I mean how I can know each bit is set or not?
>>> BIT_1 = 1 << 0 >>> BIT_2 = 1 << 1 >>> BIT_3 = 1 << 2 >>> BIT_4 = 1 << 3 >>> BIT_5 = 1 << 4 >>> BIT_6 = 1 << 5 >>> BIT_7 = 1 << 6 >>> BIT_8 = 1 << 7 >>> byte = 67 >>> if byte & BIT_1: ... print "Bit 1 is set!" ... else: ... print "Bit 1 is not set!" Bit 1 is set! >>> if not byte & BIT_6: ... byte = byte | BIT_6 ... print "Bit 6 wasn't set, BUT NOW IS." Bit 6 wasn't set, BUT NOW IS. >>> byte 99 (I added 'how to set a specific bit' just cuz) Basically, those BIT_X lines are creating numbers which have *only* the specified bit set. Then you do "byte & BIT_X", and that will return 0 if the byte doesn't have the specified bit in it. You can then set the bit with "byte | BIT_X", and unset the bit with "byte ^ BIT_X". -- Stephen Hansen ... Also: Ixokai ... Mail: me+list/python (AT) ixokai (DOT) io ... Blog: http://meh.ixokai.io/
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