Fredrik Lundh wrote:
> [EMAIL PROTECTED] wrote:
>
> > Fredrik Lundh's solution works if the hex string starts with "0x"
>
> that's what "interpret [it] as a Python literal" meant.
I know from personal experience that the implications of that
sometimes go right over the head of a newbie. Did I do
[EMAIL PROTECTED] wrote:
> Fredrik Lundh's solution works if the hex string starts with "0x"
that's what "interpret [it] as a Python literal" meant.
> (which it will when the string is created with the hex function).
>
> >>> int(hex(m),0)
> 66
>
> But it won't work without the "0x".
>
> >>> int(
On 2005-11-23, tim <[EMAIL PROTECTED]> wrote:
>int(hex(m),16)
>
>
>>66
>>
>>Fredrik Lundh's solution works if the hex string starts with "0x"
>>(which it will when the string is created with the hex function).
>>
> aren't you converting from a hex string to a decimal value here
Brett g Porter wrote:
> tim wrote:
>
>>
>> I end up with 66 again, back where I started, a decimal, right?
>> I want to end up with 0x42 as being a hex value, not a string, so i
>> can pas it as an argument to a function that needs a hex value.
>> (i am trying to replace the 0x42 in the line
>>
tim wrote:
>
> I end up with 66 again, back where I started, a decimal, right?
> I want to end up with 0x42 as being a hex value, not a string, so i can
> pas it as an argument to a function that needs a hex value.
> (i am trying to replace the 0x42 in the line midi.note_off(channel=0,
> note=0
tim wrote:
> ok, but if i do
>
> >>> n=66
> >>> m=hex(n)
> >>> m
> '0x42'
> >>> h=int(m,16)
> >>> h
> 66
> >>>
>
> I end up with 66 again, back where I started, a decimal, right?
> I want to end up with 0x42 as being a hex value, not a string, so i can
> pas it as an argument to a function
[EMAIL PROTECTED] wrote:
>tim wrote:
>
>
>>but then i get :
>>
>> >>> m
>>66
>> >>> n=int(hex(m))
>>Traceback (most recent call last):
>> File "", line 1, in ?
>>ValueError: invalid literal for int(): 0x42
>> >>>
>>
>>what am I missing here ?
>>
>>
>
>Avnit's solution was wrong. When conve
tim wrote:
> but then i get :
>
> >>> m
> 66
> >>> n=int(hex(m))
> Traceback (most recent call last):
> File "", line 1, in ?
> ValueError: invalid literal for int(): 0x42
> >>>
>
> what am I missing here ?
Avnit's solution was wrong. When converting a string, you
must state what base you ar
ok, but if i do
>>> n=66
>>> m=hex(n)
>>> m
'0x42'
>>> h=int(m,16)
>>> h
66
>>>
I end up with 66 again, back where I started, a decimal, right?
I want to end up with 0x42 as being a hex value, not a string, so i can
pas it as an argument to a function that needs a hex value.
(i am trying t
avnit wrote:
> If you just want to convert a string to an integer, it would be:
>
> >>> int(n)
That's what the OP tried and it didn't work.
BECAUSE you have to tell the int function what base the string is in
(even though it has "0x" at the start).
>>> int(n,16)
66
>
> in your case it would be
but then i get :
>>> m
66
>>> n=int(hex(m))
Traceback (most recent call last):
File "", line 1, in ?
ValueError: invalid literal for int(): 0x42
>>>
what am I missing here ?
thank you
Tim
avnit wrote:
>If you just want to convert a string to an integer, it would be:
>
>
>
int(n)
"tim" <[EMAIL PROTECTED]> wrote:
> This is probably another newbie question...but...
> even after reading quite some messages like '..hex to decimal',
> 'creating a hex value' , I can't figure this out:
> If i do
> >>> m=66
> >>> n=hex(m)
> >>> n
> '0x42'
> i cannot use n as value for a variable t
If you just want to convert a string to an integer, it would be:
>>> int(n)
in your case it would be:
>>> m=66
>>> n=int(hex(m))
--
http://mail.python.org/mailman/listinfo/python-list
This is probably another newbie question...but...
even after reading quite some messages like '..hex to decimal',
'creating a hex value' , I can't figure this out:
If i do
>>> m=66
>>> n=hex(m)
>>> n
'0x42'
i cannot use n as value for a variable that takes hex values, because it
throws:
error
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