ok, but if i do >>> n=66 >>> m=hex(n) >>> m '0x42' >>> h=int(m,16) >>> h 66 >>>
I end up with 66 again, back where I started, a decimal, right? I want to end up with 0x42 as being a hex value, not a string, so i can pas it as an argument to a function that needs a hex value. (i am trying to replace the 0x42 in the line midi.note_off(channel=0, note=0x42) with a variable) [EMAIL PROTECTED] wrote: > avnit wrote: > > >> If you just want to convert a string to an integer, it would be: >> >> >> >>>>> int(n) >>>>> >>>> > > That's what the OP tried and it didn't work. > > BECAUSE you have to tell the int function what base the string is in > (even though it has "0x" at the start). > > > >>>> int(n,16) >>>> >>> > 66 > > > >> in your case it would be: >> >> >> >>>>> m=66 >>>>> n=int(hex(m)) >>>>> >>>> > > Wrong again, you still have to tell it what base. > > > >>>> h=int(hex(m),16) >>>> h >>>> >>> > 66 > > > -- http://mail.python.org/mailman/listinfo/python-list
