Re: fun with lambdas

Thanks to all I settled with this: def partial1(f,b): return lambda a:f(a,b) def partial2(f,a): return lambda b:f(a,b) Juan Pablo 2005/10/20, Mike Meyer <[EMAIL PROTECTED]>: > Robert Kern <[EMAIL PROTECTED]> writes: > > Juan Pablo Romero wrote: > >> Hello! > >> > >> given the d

Re: fun with lambdas

Robert Kern <[EMAIL PROTECTED]> writes: > Juan Pablo Romero wrote: >> Hello! >> >> given the definition >> >> def f(a,b): return a+b >> >> With this code: >> >> fs = [ lambda x: f(x,o) for o in [0,1,2]] >> >> or this >> >> fs = [] >> for o in [0,1,2]: >> fs.append( lambda x: f(x,o) ) >>

Re: fun with lambdas

You are asking it to return a list of lambda, not its evaluated value. map(lambda x: f(x,0), [0,1,2]) works. [ f(o) for o in [0,1,2] ] works too. Juan Pablo Romero wrote: > Hello! > > given the definition > > def f(a,b): return a+b > > With this code: > > fs = [ lambda x: f(x,o) for o in [0,1,

Re: fun with lambdas

Juan Pablo Romero wrote: > Hello! > > given the definition > > def f(a,b): return a+b > > With this code: > > fs = [ lambda x: f(x,o) for o in [0,1,2]] > > or this > > fs = [] > for o in [0,1,2]: > fs.append( lambda x: f(x,o) ) > > I'd expect that fs contains partial evaluated functions,

fun with lambdas

Hello! given the definition def f(a,b): return a+b With this code: fs = [ lambda x: f(x,o) for o in [0,1,2]] or this fs = [] for o in [0,1,2]: fs.append( lambda x: f(x,o) ) I'd expect that fs contains partial evaluated functions, i.e. fs[0](0) == 0 fs[1](0) == 1 fs[2](0) == 2 But this