Juan Pablo Romero wrote: > Hello! > > given the definition > > def f(a,b): return a+b > > With this code: > > fs = [ lambda x: f(x,o) for o in [0,1,2]] > > or this > > fs = [] > for o in [0,1,2]: > fs.append( lambda x: f(x,o) ) > > I'd expect that fs contains partial evaluated functions, i.e. > > fs[0](0) == 0 > fs[1](0) == 1 > fs[2](0) == 2 > > But this is not the case :( > > What is happening here?
Namespaces. The functions are looking up o at runtime. In both cases, o is bound to the last object in [0,1,2] once the iteration is finished. Try this (although I'm sure there are better ways): In [4]: fs = [lambda x, o=o: f(x, o) for o in [0,1,2]] In [5]: fs[0](0) Out[5]: 0 In [6]: fs[0](1) Out[6]: 1 In [7]: fs[0](2) Out[7]: 2 -- Robert Kern [EMAIL PROTECTED] "In the fields of hell where the grass grows high Are the graves of dreams allowed to die." -- Richard Harter -- http://mail.python.org/mailman/listinfo/python-list
