On Wed, Sep 23, 2009 at 3:48 AM, Peter Otten <__pete...@web.de> wrote:
> Why's that obsession with speed?
>
Well, most of the solutions posted so far are O(n**2), which may be
noticeably slow if the list is of considerable length. I wonder if the
original poster ran in to that problem.
>>> item
On 23 сен, 12:48, Peter Otten <__pete...@web.de> wrote:
> blumenkraft wrote:
> > I have some list:
> > x = [8, 9, 1, 7]
> > and list of indices I want to delete from x:
> > indices_to_delete = [0, 3], so after deletion x must be equal to [9,
> > 1].
>
> > What is the fastest way to do this? Is ther
Hi
2009/9/23 blumenkraft :
> Hi,
>
> I have some list:
> x = [8, 9, 1, 7]
> and list of indices I want to delete from x:
> indices_to_delete = [0, 3], so after deletion x must be equal to [9,
> 1].
>
> What is the fastest way to do this? Is there any builtin?
Try this-
>>> x = [8, 9, 1, 7]
>>> [x
blumenkraft wrote:
> I have some list:
> x = [8, 9, 1, 7]
> and list of indices I want to delete from x:
> indices_to_delete = [0, 3], so after deletion x must be equal to [9,
> 1].
>
> What is the fastest way to do this? Is there any builtin?
Why's that obsession with speed?
>>> items = ["a",
On Wed, Sep 23, 2009 at 1:25 AM, blumenkraft wrote:
> Hi,
>
> I have some list:
> x = [8, 9, 1, 7]
> and list of indices I want to delete from x:
> indices_to_delete = [0, 3], so after deletion x must be equal to [9,
> 1].
>
> What is the fastest way to do this? Is there any builtin?
#untested &
Hi,
I have some list:
x = [8, 9, 1, 7]
and list of indices I want to delete from x:
indices_to_delete = [0, 3], so after deletion x must be equal to [9,
1].
What is the fastest way to do this? Is there any builtin?
Thanks.
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